Free Printable [Eng Apps] Algebra and Spreadsheets Review

1.

Given the equation:

P\ =\ 2L\ +\ 2W

solve for the variable →

L

a)

$L\ =\ \frac{P-2W}{\ 2}$

b)

$L=\ P-\frac{2W}{2}$

c)

$L\ =\ P+\frac{2W}{2}$

d)

$L=\frac{P+2W}{2}$

2.

Given the equation:

A=\pi r^2

solve for the variable →

r

a)

$r=\sqrt{\frac{A}{\pi}}$

b)

$r=\sqrt{\frac{\pi}{A}}$

c)

$r=\frac{\sqrt{A}}{\pi}$

d)

$r=\frac{\sqrt{\pi}}{A}$

3.

Given the equation:

V=\pi r^2h

solve for the variable →

r

a)

$r=\sqrt{\frac{V}{h\pi}}$

b)

$r=\sqrt{\frac{\pi}{hV}}$

c)

$r=\frac{\sqrt{Vh}}{\pi}$

d)

$r=\frac{\sqrt{\pi}}{Vh}$

4.

Given the equation:

V=\pi r^2h

solve for the variable →

h

a)

$h\ =\ \frac{V}{\pi r^2}$

b)

$h=\frac{\pi r^2}{V}$

c)

$h=\sqrt{\frac{V}{\pi r}}$

d)

$h=\sqrt{\frac{\pi r}{V}}$

5.

Given the equation:

V=\frac{1}{3}\pi r^2h

solve for the variable →

r

a)

$r=\sqrt{\frac{3V}{h\pi}}$

b)

$r=\sqrt{\frac{\pi}{3hV}}$

c)

$r=\frac{\sqrt{3Vh}}{\pi}$

d)

$r=\frac{\sqrt{\pi}}{3Vh}$

6.

Given the equation:

V=\frac{1}{3}\pi r^2h

solve for the variable →

h

a)

$h\ =\ \frac{3V}{\pi r^2}$

b)

$h=\frac{\pi r^2}{3V}$

c)

$h=\sqrt{\frac{3V}{\pi r}}$

d)

$h=\sqrt{\frac{\pi r}{3V}}$

7.

Given the equation:

V=\frac{4}{3}\pi r^3

solve for the variable →

r

a)

$r=\left(\frac{3V}{4\pi}\right)^{\frac{1}{3}}$

b)

$r=\left(\frac{4V}{3\pi}\right)^{\frac{1}{3}}$

c)

$h=\sqrt{\frac{3V}{4\pi r}}$

d)

$h=\sqrt{\frac{4\pi r}{3V}}$

8.

Given the equation:

V=\frac{4}{3}\pi r^3+\pi r^2h

solve for the variable →

h

a)

$h=\frac{V-\frac{4}{3}\pi r^3}{\pi r^2}$

b)

$h=\frac{V-\pi r^3}{\frac{4}{3}\pi r^2}$

c)

$h=\frac{4V-\pi r^3}{3\pi r^2}$

d)

$h=\frac{3V-\pi r^3}{4\pi r^2}$

9.

Given the equation:

S=2\pi r\left(r+h\right)

solve for the variable →

h

a)

$h=\frac{S}{2\pi r}-r$

b)

$h=\frac{S}{2\pi r^2}$

c)

$h=\frac{S}{\pi r}-2r$

d)

$h=\frac{2S}{\pi r}-r$

10.

Given the equation:

S=4\pi r^2+2\pi rh

solve for the variable →

h

a)

$h=\frac{S-4\pi r^2}{2\pi r}$

b)

$h=\frac{2S-\pi r^2}{4\pi r}$

c)

$h=\frac{4\pi r^2}{S-2\pi r}$

d)

$h=\frac{2\pi r^2}{S-4\pi r}$

11.

What is the spreadsheet formula version of the equation:

S=2\pi r\left(r+h\right)

a)

= 2*pi( )*r*(r+h)

b)

= 2pi( )*r(r+h)

c)

= 2pi( )*(r^2+h)

d)

= (2*pi( )*r)(r+h)

12.

What is the spreadsheet formula version of the equation:

r=\sqrt{\frac{3V}{2\pi h}}

a)

= ((3*V)/(2*pi()*h))^(1/2)

b)

= ((3*V)/(2*pi()*h))^1/2

c)

= (3*V)/(2*pi()*h)^(1/2)

d)

= (3*V)/(2*pi()*h)^1/2

13.

What is the spreadsheet formula version of the equation:

r=\left(\frac{3V}{4\pi}\right)^{\left(\frac{1}{3}\right)}

a)

= ((3*V)/(4*pi()))^(1/3)

b)

= ((3*V)/(4*pi()))^1/3

c)

= (3*V)/(4*pi())^(1/3)

d)

= ((3*V)/(4*pi))^(1/3)

14.

What is the spreadsheet formula version of the equation:

S=4\pi r^2+2\pi rh

a)

= (4*pi()*r^2) + (2*pi()*r*h)

b)

= (4pi()*r^2) + (2pi()*r*h)

c)

= 4pi()*r^2+2pi()*r*h

d)

= (4*pi*r^2)+(2*pi*r*h)

15.

What is the spreadsheet formula version of the equation:

S=\frac{4}{3}\pi r^3+\pi r^2h

Assume the value for

r

is in cell C3.

a)

= ((4/3)*pi()*C3^3) + (pi()*C3^2*h)

b)

= (4/3)pi()*r^3 + pi()*r*r*h

c)

= ((4/3)*pi()*r^3) + (pi()*r^2*h)

d)

= (4/3)pi()C3^3 + pi()C3^2h

[Eng Apps] Algebra and Spreadsheets Review

Total questions: 15

Worksheet time: 1hrs 15mins

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