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Digital Modulation schemes

Total questions: 15

Worksheet time: 8mins

Name
Class
Date
1.

FSK reception is

a)

Phase Coherent

b)

Phase non coherent

c)

Phase Coherent & non coherent

d)

None of the mentioned

2.

Which is called as on-off keying?

a)

Amplitude shift keying

b)

Uni-polar PAM

c)

Amplitude shift keying & Uni-polar PAM

d)

None of the mentioned

3.

QAM uses ______ as the dimensions.

a)

In phase

b)

Quadrature

c)

In phase & Quadrature

d)

None of the mentioned

4.

Which has same probability of error?

a)

BPSK and QPSK

b)

BPSK and ASK

c)

BPSK and PAM

d)

BPSK and QAM

5.

Which system uses QAM?

a)

Digital microwave relay

b)

Dial up modem

c)

Digital microwave relay & Dial up modem

d)

None of the mentioned

6.

Modulation process corresponds to ______ the amplitude, frequency or phase.

a)

Switching

b)

Keying

c)

Switching or keying

d)

None of the mentioned

7.

Matched filter

a)

Is a non linear filter

b)

Produces maximum output SNR

c)

All of the mentioned

d)

None of the mentioned

8.

Average energy per bit is given by

a)

average energy symbol/log2 M

b)

average energy symbol * log2 M

c)

log2 M/ Average energy symbol

d)

none of the mentioned

9.

In DPSK technique, the technique used to encode bits is

a)

AMI

b)

Differential code

c)

Uni polar RZ format

d)

Manchester format

10.

In binary data transmission DPSK is preferred to PSK because

a)

a coherent carrier is not required to be generated at the receiver

b)

for a given energy per bit, the probability of error is less

c)

the 1800 phase shifts of the carrier are unimportant

d)

more protection is provided against impulse noise

11.

For the signal constellation shown in the figure, the type of modulation is

a)

QPSK

b)

FSK

c)

ASK

d)

PSK

12.

A DPSK wave is obtained by

a)

BPSK

b)

Differential encoding followed by BPSK

c)

Differential Encoding

d)

None

13.

For coherent FSK modulation probability of error

a)

Pe=12erfc(Eb2No)Pe=\frac{1}{2}erfc\left(\sqrt{\frac{Eb}{2No}}\right)

b)

Pe=12erfc(12EbN0)Pe=\frac{1}{2}erfc\left(\frac{1}{2}\sqrt{\frac{Eb}{N0}}\right)

c)

Pe=12erfc(EbN0)Pe=\frac{1}{2}erfc\left(\sqrt{\frac{Eb}{N0}}\right)

d)

None

14.

QPSK uses a phase shift of

a)

π\pi

b)

π2\frac{\pi}{2}

c)

π4\frac{\pi}{4}

d)

2π2\pi

15.

The Maximum bandwidth is occupied by

a)

ASK

b)

BPSK

c)

FSK

d)

None