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Plane & Curved Mirrors Exam

Total questions: 20

Worksheet time: 27mins

Name
Class
Date
1.

The focal length of a spherical mirror is _____ the radius of curvature of the mirror.

a)

twice

b)

half

c)

the same

d)

unrelated to

2.

What type of image is produced by a convex mirror?

a)

enlarged (bigger) and real

b)

reduced (smaller) and virtual

c)

enlarged and virtual

d)

reduced and real

3.

Light from a laser strikes a plane mirror at an angle of 38 degrees to the normal. If the angle of incidence increases by 13 degrees what is the new angle of reflection?

a)

38 degrees

b)

51 degrees

c)

65 degrees

d)

84 degrees

4.

A concave mirror has a 7 cm focal length. You place a 2.4 cm tall object 16 cm from the mirror. Determine the image height.

 HINT. use:   xi=fxoxof      and:        hiho=xixo      HINT.\ use:\ \ \ x_i=\frac{fx_o}{x_o-f}\ \ \ \ \ \ and:\ \ \ \ \ \ \ \ \frac{h_i}{h_o}=-\frac{x_i}{x_o}\ \ \ \ \ \   

a)

7 cm

b)

4 cm

c)

-1.9 cm

d)

-3.5 cm

5.

Under which conditions does a concave mirror produce an enlarged virtual image?

a)

Never

b)

When the object is farther away than the focal point

c)

When the object is farther away than the radius of curvature

d)

When the object is between the focal point and the mirror

6.

You place an object 20 cm in front of a convex mirror with a –15 cm focal length. Calculate the image position

 HINT. Use the mirror equation: 1f=1xi+1xoHINT.\ Use\ the\ mirror\ equation:\ \frac{1}{f}=\frac{1}{x_i}+\frac{1}{x_o}  

a)

9.45 cm

b)

5.34 cm

c)

-4.35 cm

d)

-8.57 cm

7.

If xi = -xo, then what is the meaning of the negative sign?

a)

The image is inverted

b)

The image is virtual

c)

The image is smaller

d)

The image is larger

8.

What is the size and position of an image formed by a plane mirror?

a)

same size, closer to the mirror

b)

same size, same distance away from the mirror

c)

enlarged, closer to the mirror

d)

reduced, farther from the mirror

9.

Identify whether the following statement is true or false: “Virtual images are formed from divergent (scattered) rays.”

a)

True

b)

False

10.

This is an example of a _________ mirror

a)

Concave

b)

Convex

c)

Magnifying

d)

Plane

11.

In diffuse reflection, why are the reflected rays not parallel to each other?

a)

because the light is of various wavelengths

b)

because this only happens in plane mirrors

c)

because the incident rays are not parallel

d)

because the surface is not smooth

12.

Where is the object located if the image that is produced by a concave mirror is SMALLER than the object?

a)

at the mirror’s focal point

b)

between the mirror and the focal point

c)

between the focal point and center of curvature

d)

outside the center of curvature

13.

If the flame on the candle is 2 cm tall, how tall is the flame of the image?

a)

1

b)

2

c)

4

d)

8

14.

Which terms describe the reflection seen in this image?

a)

virtual, upright

b)

virtual, inverted

c)

real, upright

d)

real, inverted

15.

Which of the following mirrors have a focal point?

a)

Plane mirrors only

b)

Concave mirrors only

c)

Plane, convex and concave mirrors

d)

Convex and concave mirrors only

16.

Outside rear-view mirrors on automobiles are generally ____.

a)

concave

b)

convex

c)

plane

d)

magnifying

17.

If an image in a curved mirror is virtual, you can say that the mirror is:

a)

Definitely concave

b)

Definitely convex

c)

Could be concave or convex

18.

If the heigh of the image is a negative number, this means it is:

a)

Upright

b)

Real

c)

Virtual

d)

Inverted

19.

A concave mirror has a radius of curvature of 24 cm. A 6.4 cm tall object is held 26cm from the mirror. Calculate the distance between the image and the mirror.

 HINT. use: f=r2        xi=fxoxofHINT.\ use:\ f=\frac{r}{2}\ \ \ \ \ \ \ \ x_i=\frac{fx_o}{x_o-f}  

a)

22.3 cm

b)

23.2 cm

c)

32.2 cm

d)

23.3 cm

20.

A concave mirror has a focal length of 12 cm. A 6.4 cm tall object is held 26cm from the mirror. The distance from the image to the object is 22.3 cm. What is the height of the image.

 HINT. use: hiho=xixoHINT.\ use:\ \frac{h_i}{h_o}=-\frac{x_i}{x_o}  

a)

-5.5 cm

b)

3.3 cm

c)

5.5 cm

d)

-3.3 cm