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Unit 8: Number Theory

Total questions: 14

Worksheet time: 34mins

Name
Class
Date
1.

(8.1) Use a factor tree to find the prime factorization of 27,720. Choose all answers that apply.

a)

2223357112\cdot2\cdot2\cdot3\cdot3\cdot5\cdot7\cdot11

b)

233257112^3\cdot3^2\cdot5\cdot7\cdot11

c)

2357112\cdot3\cdot5\cdot7\cdot11

d)

8957118\cdot9\cdot5\cdot7\cdot11

2.

(8.1) Use Prime Factorization to find

 gcd(99, 216)\gcd\left(-99,\ 216\right)  

a)

1

b)

9

c)

3

d)

-9

e)

-3

3.

(8.1) All of the following numbers are prime except:

a)

491

b)

263

c)

227

d)

493

4.

(8.1) Use the test for divisibility by 4 to determine whether or not 47,877,905,008,564,228 is divisible by 4.

a)

Yes, the number is divisible by 4.

b)

No, the number is not divisible by 4.

5.

(8.2) Is  67212 (mod 5)672\equiv12\ \left(mod\ 5\right) 

a)

Yes

b)

No

6.

(8.2) Calculate (753 · 124 · 43,921 · 100,003) mod 10. Your answer ( rr ) should be

 0r<100\le r<10  

a)

36

b)

11

c)

6

d)

1

7.

(8.2) Find  194786 mod 919^{4786}\ mod\ 9 

a)

-1

b)

1

c)

46,782,356,221

d)

This is too big for my calculator and there is no other way to solve this problem easily.

8.

(8.4) Determine the check digit of the UPC  01430025433?0-14300-25433-? .



(a)  

9.

(8.4) Determine the missing digit of a money order that has ID number 829_8164036.

(a)  

10.

(8.6) Encode the message

TRUTH

using the affine cipher

C = (3P + 5) mod 26.

(a)  

11.

(8.6) 

Part 1- Is  C=(7P+2) mod 26C=\left(7P+2\right)\ mod\ 26 a valid affine cipher? 

a)

Yes, because  gcd(7, 26)=1\gcd\left(7,\ 26\right)=1  

b)

No, because  gcd(7, 26)1\gcd\left(7,\ 26\right)\ne1  

12.

(8.6) 

Part 2- A message was encoded using the affine cipher  C=(7P+2) mod 26C=\left(7P+2\right)\ mod\ 26 . What formula can be used to decode the message?

a)

 P=(7(C2)) mod 26P=\left(7\left(C-2\right)\right)\ mod\ 26  

b)

 C=(15P2) mod 26C=\left(15P-2\right)\ mod\ 26  

c)

 P=(15(C2)) mod 26P=\left(15\left(C-2\right)\right)\ mod\ 26  

d)

 P=(15C2) mod 26P=\left(15C-2\right)\ mod\ 26  

e)

 P=(7(C+2)) mod 26P=\left(7\left(C+2\right)\right)\ mod\ 26  

13.

(8.6)

Part 3- Decipher the message 

ZWDE
which was encoded using the affine cipher

 C=(7P+2) mod 26C=\left(7P+2\right)\ mod\ 26 



(a)  

14.

(8.6) Decipher the message
WHV WIU LGD B
that was encoded with the
Caesar Cipher

 C=(P+3) mod 26C=\left(P+3\right)\ mod\ 26  



(a)