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Worksheets

Genetics

Total questions: 18

Worksheet time: 2hrs 30mins

Name
Class
Date
1.

Which of the following statements correctly describes the Law of Independent Assortment?

a)

Sometimes all alleles lack dominance, which leads to a blending of traits.

b)

A large Punnett square can be used to predict the outcome of a parental cross involving two traits.

c)

The dominant allele is represented with an uppercase letter and the recessive allele is represented with a lowercase letter.

d)

The allele a gamete receives for one gene does not influence the allele received for another gene, if the two genes are located on different chromosomes.

2.

In garden pea plants, tall stem height (T) is dominant over short stem height (t), and green pod colour (G) is dominant over yellow pod colour (g).

Using the chart of numbered genotypes, identify the correct number for the genotype of a pure breeding tall, green pod pea plant.

a)

1

b)

3

c)

7

d)

9

3.

In garden pea plants, tall stem height (T) is dominant over short stem height (t), and green pod colour (G) is dominant over yellow pod colour (g).

Using the chart of numbered genotypes, identify the correct number for the genotype of a pea plant used for a test cross.

a)

1

b)

2

c)

8

d)

9

4.

In garden pea plants, tall stem height (T) is dominant over short stem height (t), and green pod colour (G) is dominant over yellow pod colour (g).

Using the chart of numbered genotypes, identify the correct number for the genotype of a yellow pod heterozygous tall pea plant.

a)

4

b)

5

c)

6

d)

8

5.

In garden pea plants, tall stem height (T) is dominant over short stem height (t), and green pod colour (G) is dominant over yellow pod colour (g).


Which of the following parental crosses represents the genotype of a dwarf homozygous green pea plant crossed with a homozygous tall yellow pea plant?

a)

ttGG X TTgg

b)

ttGg X Ttgg

c)

TTgg X ttGg

d)

TtGG X TTGg

6.

How many possible allele combinations can be formed in the gametes produced from parents with the genotypes RRww and RrWW, respectively?

a)

2 and 1

b)

2 and 2

c)

1 and 1

d)

1 and 2

7.

What are the possible allele combinations that could be formed in the gametes produced from a parent with the genotype RrWw?

a)

RW, Rw, rW, and rw

b)

RW, Rw, and rw

c)

RW and rw

d)

RW, RW, rw, and rw

8.

In garden pea plants, tall stem height (T) is dominant over short stem height (t), and round seed shape (R) is dominant over wrinkled seed shape (r).


A tall, wrinkled seed plant (Ttrr) is crossed with a tall, round seed plant (TtRR). Which row identifies the gametes produced by these plants?

Select one:

a)

Tall wrinkled Tall round

Tr and tr TR, Tr, tR, and tr

b)

Tall wrinkled. Tall round

TR,Tr, tR, tr TR and tR

c)

Tall wrinkled Tall round

Tr and tr TR and tR

d)

Tall wrinkled Tall round

TR and tR Tr and tr

9.

In guinea pigs, a black coat (B) is dominant over a white coat (b), and straight hair (S) is dominant over curly hair (s). The genes for coat color and type of hair are located on different chromosomes.


Which of the following genotypes would produce a population in which 50% of the offspring would have a black coat and all of the offspring would have curly hair?

a)

bbSS and bbSs

b)

Bbss and bbss

c)

Bbss and BbSs

d)

BBSS and bbss

10.

In mice, black fur (W) is dominant over white fur (w), and black eyes are dominant (R) over red eyes (r). The two genes are located on different chromosomes.


A male mouse with black fur and black eyes mated with a female mouse with white fur and red eyes. Out of 64 offspring, 30 had black fur and black eyes, and 34 had white fur and black eyes.


What is the genotype of the male parental mouse?

a)

WWRr

b)

WwRR

c)

WwRr

d)

WWRR

11.

A male mouse heterozygous for both fur and eye colour mated with a female mouse heterozygous for both traits.


Out of 64 offspring, how many mice can be expected to be heterozygous for both fur and eye colour?

a)

36

b)

16

c)

12

d)

1

e)

4

12.

In Labrador retrievers, two genes work together to determine coat colour.The first gene affects the colour of the dark pigment, eumelanin. A genotype containing at least one dominant allele of this pigment gene results in black pigmentation (B_). A homozygous recessive genotype of this gene results in chocolate (brown) pigmentation.


The second gene affects whether the pigment eumelanin is present in the fur. If a dog has one dominant allele for this expression gene (E_), fur colouration is determined by the pigment gene. If a dog is homozygous recessive for the extension trait, the dog will have a yellow coat.


Description Genotype(s)

Black coat B_E_

Chocolate coat. bbE_

Yellow coat _ _ ee


What percentage of chocolate labs would be produced from the mating of a yellow lab who is homozygous recessive for both genes to a black lab who is heterozygous for both coat colour and expression?

a)

25%

b)

33%

c)

50%

d)

75%

13.

Use the following information to answer the next three questions.


There are two genes that determine the coat colour expression in some dogs: eumelanin and merle. These genes are located on two separate chromosomes.


For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e).


The merle gene controls the degree to which these coat colours are expressed through incomplete dominance.


The following table describes the merle gene expression.

Genotype Phenotype

MM White

Mm Half colour (Grey or light red)

mm Full colour (Black or Red)


A grey dog that is heterozygous for the eumelanin gene mates with a light red dog.


What is the probability they would have a grey puppy?

a)

0.13

b)

0.50

c)

0.38

d)

0.25

14.

Above is a simplified chart for polygenic trait of eye colour. The amount of melanin in the iris is what determines the colour of the eye. People with brown eyes have more melanin in their iris than people with blue eyes. The amount of melanin is controlled by how many dominant alleles a person has for eye colour as seen in the chart.


Which of the following parental crosses explains how two brown-eyed parents can produce a blue-eyed child?

a)

AaBB X AaBb

b)

AaBB X AABb

c)

Aabb X AABB

d)

AABB X AaBb

15.

Which of the following is NOT true of Y-linked traits?

a)

They are passed from father to son.

b)

They are extremely uncommon in females.

c)

They are always expressed.

d)

They carry both dominant and recessive alleles of a trait.

16.

Red-green colour blindness is a sex-linked trait. Red-green colour blindness (Xrg) is the inability to distinguish between red and green colours. The Xrg allele is recessive to the normal X-linked allele.


A normal woman has a father who has red-green colour blindness. She had a child with a man who does not have red-green colour blindness.


What is the probability they will have a son with red-green colour blindness?

a)

0.50

b)

0.25

c)

0

d)

0.13

17.

Marfan syndrome is an autosomal dominant disorder caused by mutations in the FBN1 gene. It affects connective tissues, commonly resulting in long bones, abnormal curvature of the spine, defects in the eye (glaucoma), and faulty heart valves.


X-linked hypophosphatemia is an X-linked dominant disorder that causes a type of rickets.


Which of the following rows describes the inheritance pattern of these disorders?

a)

Marfan Syndrome

Males are affected more frequently than females.


X-linked Hypophosphatemia

Female carriers can pass on the trait to their sons.

b)

Marfan Syndrome

Female carriers can pass on the trait to their sons.


X-linked Hypophosphatemia

Males are affected more frequently than females.

c)

Marfan Syndrome

Affected males can only pass on the trait to their daughters.


X-linked Hypophosphatemia

Males and females are affected with equal frequently.

d)

Marfan Syndrome

Males and females are affected with equal frequency.


X-linked Hypophosphatemia

Affected males can only pass on the trait to their daughters.

18.

The inheritance of colour in domestic pigeons involves several genes. The dominance hierarchy of three colour alleles is ash-red > blue-black > brown (ZA > ZB > Zb ).


These colours are carried on the Z sex chromosome. Unlike humans, female pigeons have two different sex chromosomes (Z and W) and males have two of the same kind of sex chromosome (ZZ).


In birds, males have two Z sex chromosomes (ZZ) and females have one Z and one W sex chromosome (ZW). Since female birds have only one Z chromosome, they have only one copy of all Z-linked genes and they express the phenotype of the allele that they get.


Barred is a sex-linked dominant trait in chickens. The barring allele causes white pigment in bars on a solid color producing an alternating pattern. The original solid color in the chickens below is black.


The possible genotypes and their corresponding phenotypes as described in the chart above.


Which of the following rows correctly displays the phenotypes of the F1 generation of a cross between a pure breeding barred rooster and a black hen AND a black rooster and a barred hen, respectively?

a)

Barred Male X Black Female Black Male X Barred Female

100% barred Barred males and black

females

b)

Barred Male X Black Female Black Male X Barred Female

Barred males and black females 100% barred

c)

Barred Male X Black Female Black Male X Barred Female

100% barred 100% barred

d)

Barred Male X Black Female Black Male X Barred Female

100% barred 2 barred females : 1 barred male

: 1 black male