WorksheetsHooke's Law and Elastic Potential Energy
Total questions: 15
Worksheet time: 8mins
A 5-newton force causes a spring to stretch 0.2 metre. What is the potential energy stored in the stretched spring?
1 J
0.5 J
0.2 J
0.1 J
At point P, _______.
the force applied to the spring is equal to its elongation
Hooke's Law ceases to be valid
the spring is can be stretched but still springs back into shape reversibly
the spring constant increases
Which quantity can be determined from this graph?
the net force is 4N
the spring is 0.4m long
the stored potential energy in this spring is 1.6 J
the spring constant is 10 N/m
A force of 20 N is applied by a mass hanging at the bottom of a spring. How heavy is the mass?
2.0 g
2.0 kg
20 g
20 kg
Which statement most accurately represents Hooke's Law?
Extension of a spring is proportional to the number of coils.
Thickness of a spring wire is proportional to the force applied.
Extension of a spring is inversely proportional to the force applied.
Extension of a spring is inversely proportional to the force applied.
The formula for calculating elastic potential energy (Ee) is...
2 x spring constant x extension2
1/2 x spring constant2 x extension
1/2 x spring constant x extension2
1/2 x mass x extension2
