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WorksheetsGraded Classwork 2 - Algebra and Consumer
Total questions: 20
Worksheet time: 1hrs 14mins
Factorize a2b+ab2+ab
a2b2(b+a+ab)
ab(a+b+1)
ab(a+b)
ab(ab+1)
Factorise 4xy−6xz
x(4y−6z)
2x(2y−3z)
2(2xy−3xz)
4x(y−6z)
Factorise 6g2−3g3
3(2g2−g3)
3g(2g−g2)
3g2(2−g)
g2(6−3g)
Identify the common factors of
13m2y5-39my3-26y2
13my2
13y2
13m2y5
Simplify:
−(8 − 2p)
8-2p
-8-2p
-8+2p
-8+6p
Expand and simplify
7(p+10q)+2(6p+7q)
7p+70q+12p+14q
19p+84q
15p+17q
19p+77q
Which of the following expressions is equivalent to 10x + 8?
10x - 8
5x + 5x + 4
5(5x + 3)
2(5x + 4)
Expand using FOIL
(b+2)(3b − 5)
4b-3
3b2+b-10
3b2-2b-10
3b2+10b - 1
Expand using FOIL
(2y-3)2
4y2+12y+9
4y2-12y+9
4x2+2x+2
x2-12x+1
Expand and simplify
4u−3(2u−5v)
−2u+15v
2u−15
10u−15v
−2u+15
Expand and simplify
a+3b−(5a−4b)
6a−b
−4a−7b
−4a+7b
4a+7b
Simplify
7n(3n−8)+4n(n+8)
25n−24
25n2– 24n
24−25n
25n2+24n
Each year a car depreciates by 5%. If a car was worth $100,000 at the beginning of January 2014, then its value at the end of December 2014 was
$5,000
$10,000
$90,000
$95,000
A plot of land is valued at $200,000. It appreciates at 5% each year. What will be its value after 2 years?
$210,000
$220,000
$220,500
$20,000
