WorksheetsCalc: Quotient and Chain Rule Quiz
Total questions: 22
Worksheet time: 45mins
What is NOT an acceptable way to write the quotient rule for the derivative of y = gf
y′=g2(gf′−fg′)
y′=g2(f′g−g′f)
y′=lo2lo⋅dhi−hi⋅dlo
y′=g2(fg′−gf′)
True
False
Can't tell, it depends on the rule
It's all the parentheses for me
Which rule can you NOT use the chain rule on?
(8x3+π)10
ln(5x3−3)
tan(400x2)
ex(sinx+cosx)
Which rule can you NOT use the quotient rule on?
cotx
secxex
ln(4x)
Chai 6x2x+6 n Rule
Which of the following doesn't require the quotient rule? Meaning it can be rewritten and differentiated with a different rule.
x2sinx
4x3+2xx4−5x+6
exlnx
x45
y=csc8x Which of the following is the proper way to setup up the chain rule?
y=u8, u = cscx
y=cscu, u = x8
Not a composite function
Set up the derivative of y(x)=(x2+2x+1)3x−7
y′(x)=(3x−7)2(3x−7)(2x+2)−(3)(x2+2x+1)
y′(x)=(x2+2x+1)2(3x−7)(2x+2)−3(x2+2x+1)
y′(x)=(x2+2x+1)(3)(x2+2x+1)−(3x−7)(2x+2)
y′(x)=(x2+2x+1)2(3)(x2+2x+1)−(3x−7)(2x+2)
Find and simplify y' if y=x+34x2−5
y′=(x+3)28x2+8x+5
y′=(x+3)24x2+24x+5
y′=(x+3)24x2+24x−5
y′=(4x2−5)28x2+24x+5
Find AND simplify the derivative of secx2x4
y′(x)=secxxtanx+4
y′(x)=secx2x3(4−xtanx)
y′(x)=(2x4)22x3secx(4−xtanx)
y′(x)=sec2x8x3secx−2x4secxtanx
Find AND fully simplify the derivative of y′(x)=ex−sinx
y′(x)=(ex)2−cosx⋅ex+sinx⋅ex
y′(x)=excosx−sinx
y′(x)=ex−cosx+sinx
y′(x)=(−sinx2)−sinxcosx−e2x
Find the derivative of tan (10x5)
sec2(10x5)
sec2(50x4)
50x4tan(10x5)
50x4sec2(10x5)
What is the derivative of ln(x4)
x4
x41
1x4
41ln(x4)
What is the derivative of ecscx ?
−cscxecscx
ecscx
cscxecscx−1
−cscxcotxecscx
Evaluate f'(2) given f(x)=(5x2−8x)3 Enter your answer as a whole number or simplified fraction only (no letters).
(a)
Find f'(1) f(x)=3xx2−2x−1
(a)
Given H(x) = f(x)/g(x), use the table to evaluate H'(5). Enter your answer as a whole number or simplified fraction only (no letters).
(a)
Given J(x) = f(g(x)), use the table to evaluate J'(-8). Enter your answer as a whole number or simplified fraction only (no letters).
(a)
Find the error in dxd(sinxx3)=cosx3x2 , if there is one.
They didn't use the quotient rule
The numerator was differentiated incorrectly
The denominator was differentated incorrectly
It's correct
What is the error?
The inside derivative is incorrect
The outside derivative is incorrect
The inside/outside functions are mislabeled
The wrong rule was used
Find the error in dxd(x2ex)=x4x2ex+2xex , if there is one.
The denominator x4 should be x2
This problem shouldn't be done with the quotient rule
It should be -, not + in the numerator
It's correct!
What is the error?
The inner derivative is missing
The outer derivative is missing
The inside/outside functions are mislabeled
Nothing, it's correct
