WorksheetsQuadratic Equations Unit Review
Total questions: 32
Worksheet time: 2hrs 36mins
Solve. 3x2+2x−1=0
x=31 or x=−1
x=−31 or x=1
x=−1 or x=3
x=1 or x=−3
Solve. x2+12x=4
6±210
−6±210
−6±40
6±40
Solve. x2+7x=−10
x=−5 or x=2
x=5 or x=−2
x=−5 or x=−2
x=5 or x=2
Solve. 2x2−9x−5=0
x=−21or x=5
x=5 or x=−1
x=−5 or x=21
x=10 or x=−1
What is the maximum or minimum value of the quadratic function pictured?
Minimum: (-2,1)
Maximum: (-2,1)
Minimum: (1,-2)
Maximum: (1,-2)
The vertex of the parabola in (𝒙 − 𝟒)² − 𝟓 is
(-4,-5)
(4,-5)
(4,5)
(-4,5)
Find the solution
81x2−9=0x=±3
x=±9
x=±31
Below is the profit equation for a bike company. What represents the maximum profit?
Profit = −200x2 + 92,000x − 8,400,000
vertex x-value
vertex y-value
zero - x-intercept
Below is the profit equation for a bike company. What price should the company sell the bikes at to make a maximum profit?
Profit = −200x2 + 92,000x − 8,400,000
$230
$126
$334
x2 - 12x
x2 + 5x
A quadratic equation has zeros located at −0.5 and 7 . Which equation shows this function?
y=(2x − 1)(x − 7)
y=(2x + 1)(x − 7)
y=(x + 2)(x + 7)
y=(x − 2)(x − 7)
What should you do first in solving this equation using the quadratic formula?
x2 + 6x - 13 = 3
Get factored form
Write down: a=1, b=6, c=-13
Make it equal 0 by subtracting 3 on each side
Type it all in a calculator.
Which statement about f(x) = 45x2 − x − 2 is true?
The zeros are 92 and − 51 because f(x) = (9x − 2)(5x + 1)
The zeros are − 92 and − 51 because f(x) = (9x +2)(5x + 1)
The zeros are 92 and 51 because f(x) = (9x − 2)(5x −1)
The zeros are − 92 and 51 because f(x) = (9x + 2)(5x − 1)
Algebraically determine the vertex of the function
(4, -2)
(-4, 14)
(2, 0)
(8, 6)
Which is the correct graph of the function:
What is something that is NOT true about this function?
It is wider than y = 6x2 + 8
It opens down
It has an axis of symmetry at x = 0
It is translated up 1 unit from y = x2 - 3
Which method would be most efficient for solving the equation?
factoring
completing the square
graphing
quadratic formula
What is the maximum or minimum value of the quadratic function pictured?
Minimum: y = 1
Maximum: x = -2
Minimum: x = -2
Maximum: y = 2
What is the first step to solving this equation if you solve by completing the square (Lesson 9.4)?
a2 + 10a + 21 = 0
Set the equation equal to zero
Divide 10 by 2 and add the result to both sides
Add a2 and 10a together
Subtract the 21
For the following quadratic equation, what is the value of c ?
5x2 + 7x - 11 = 0
5
7
11
-11
For the following quadratic equation, what is the value of a ?
x2 - 7x + 2 = 15
0
x2
-7
1
For the following quadratic equation, what is the value of c ?
x2 - 7x + 2 = 15
2
15
-13
17
h = -16t2 + 64t + 960.
What is the maximum height?
h = -16t2 + 64t + 960.
When did the ball hit the ground?
A dolphin jumps from the water. The equation h = -16t2 + 80t models the dolphin's height at any given time, t. What is the maximum height the dolphin jumps?
1 foot
5 feet
96 feet
100 feet
A ball is thrown vertically into the air. Its height in feet after t seconds is given by the equation h(t) = –5t2 + 20t, and is graphed below. How high will the ball be after 3 seconds?
20 ft
15 ft
5 ft
10 ft
The height of an object thrown into the air can be modeled by the formula h(t) = -16t2 + 70t + 95, where h(t) is in feet after t seconds.
What is the height of the object after 5 seconds?
Hint: f(5)=?
95 feet
45 feet
70 feet
171.56 feet
A ball is thrown into the air with an upward velocity. Its height, h, after t seconds is given by the function below.
h=−16t2+64t+960
How many seconds did it take for the ball to reach its maximum height?
Hint: look at the vertex and remember that x=seconds and y=height.
10 seconds
64 seconds
960 seconds
2 seconds
h=−16t2+64t+960. A ball is thrown into the air with an upward velocity of 100 ft/s. Its height, h, after t seconds is given by the function
When did the ball hit the ground?
Hint: when the height (h) = 0 OR the x-intercept
10 seconds
2 seconds
5 seconds
7 seconds
Which equation matches the graph?
which of the following show the quadratic formula being used properly?
2(1)−7±(7)2−4(1)(−10)
2(1)7±(7)2−4(1)(−10)
2(1)−10±(−10)2−4(1)(7)
2(1)10±(−10)2−4(1)(7)
