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∣x+9∣=12\left|x+9\right|=12∣x+9∣=12
×=21\times=21×=21
×=3\times=3×=3
x=3, x=−21x=3,\ x=-21x=3, x=−21
x=−3, x=21x=-3,\ x=21x=−3, x=21
∣2x+5∣=9\left|2x+5\right|=9∣2x+5∣=9
x=−2x=-2x=−2
x=2, x=−7x=2,\ x=-7x=2, x=−7
x=2, x=7x=2,\ x=7x=2, x=7
x=−9x=-9x=−9
∣x2+2∣=3\left|x^2+2\right|=3∣∣x2+2∣∣=3
No es real
x=1x=1x=1
x=0x=0x=0
x=−1, x=1x=-1,\ x=1x=−1, x=1
El valor absoluto de un número siempre es: (a)
27−12=\sqrt{27}-\sqrt{12}=27−12=
151515
222
3\sqrt{3}3
2\sqrt{2}2
(2+3)(2−3)=\left(\sqrt{2}+\sqrt{3}\right)\left(\sqrt{2}-\sqrt{3}\right)=(2+3)(2−3)= (a)
(2+18)(2+18)=\left(\sqrt{2}+\sqrt{18}\right)\left(\sqrt{2}+\sqrt{18}\right)=(2+18)(2+18)=
36\sqrt{36}36
32\sqrt{32}32
666
323232
12=\frac{1}{\sqrt{2}}=21=
0.70710.70710.7071
222\sqrt{2}22
22\frac{\sqrt{2}}{2}22
22=\frac{2}{\sqrt{2}}=22=
32+5=\frac{3}{\sqrt{2}+\sqrt{5}}=2+53=
3(2+5)=3\left(\sqrt{2}+\sqrt{5}\right)=3(2+5)=
3(2−5)=3\left(\sqrt{2}-\sqrt{5}\right)=3(2−5)=
2−5\sqrt{2}-\sqrt{5}2−5
5−2\sqrt{5}-\sqrt{2}5−2
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