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Cinematica del punto

Total questions: 11

Worksheet time: 14mins

Name
Class
Date
1.

Il vettore velocità

vP→\overrightarrow{v_P}  nello SPAZIO è uguale a ...

a)

vP →= dxPdti→+dyPdtj→+dzPdtk→\overrightarrow{v_P\ }=\ \frac{\text{d}x_P}{\text{d}t}\overrightarrow{i}+\frac{\text{d}y_P}{\text{d}t}\overrightarrow{j}+\frac{\text{d}z_P}{\text{d}t}\overrightarrow{k}  

b)

vP →=dsdtt→\overrightarrow{v_P\ }=\frac{\text{d}s}{\text{d}t}\overrightarrow{t}  

c)

vP →= (dxPdt)2 +(dyPdt)2 +(dzPdt)2   t→\overrightarrow{v_P\ }=\ \sqrt{\left(\frac{\text{d}x_P}{\text{d}t}\right)^{2\ }+\left(\frac{\text{d}y_P}{\text{d}t}\right)^{2\ }+\left(\frac{\text{d}z_P}{\text{d}t}\right)^{2\ }}\ \ \overrightarrow{t}  

d)

vP ‾ = dρdteiθ+ρ dθdtei(θ+π2)\overline{v_P\ }\ =\ \frac{\text{d}\rho}{\text{d}t}e^{i\theta}+\rho\ \frac{\text{d}\theta}{\text{d}t}e^{i\left(\theta+\frac{\pi}{2}\right)}  

2.

Il vettore accelerazione

 aP→\overrightarrow{a_P}  nello SPAZIO è uguale a ...

a)

 aP → = d2sdt2n →+1ρ(dsdt)2 t→\overrightarrow{a_P\ }\ =\ \frac{\text{d}^2s}{\text{d}t^2}\overrightarrow{n\ }+\frac{1}{\rho}\left(\frac{\text{d}s}{\text{d}t}\right)^2\ \overrightarrow{t}  

b)

 aP → = d2sdt2t →+1ρ(dsdt)2 n→\overrightarrow{a_P\ }\ =\ \frac{\text{d}^2s}{\text{d}t^2}\overrightarrow{t\ }+\frac{1}{\rho}\left(\frac{\text{d}s}{\text{d}t}\right)^2\ \overrightarrow{n}  

c)

 aP → = d2sdt2n →+(dsdt)2 t→\overrightarrow{a_P\ }\ =\ \frac{\text{d}^2s}{\text{d}t^2}\overrightarrow{n\ }+\left(\frac{\text{d}s}{\text{d}t}\right)^2\ \overrightarrow{t}  

d)

 aP → = d2sdt2t →\overrightarrow{a_P\ }\ =\ \frac{\text{d}^2s}{\text{d}t^2}\overrightarrow{t\ }  

3.

Il vettore accelerazione

 aP→\overrightarrow{a_P}  nel piano è uguale a...

a)

 aP → = d2ρdt2eiθ+ρ (dθdt)2 ei(θ+π)\overrightarrow{a_P\ }\ =\ \frac{\text{d}^2\rho}{\text{d}t^2}e^{i\theta}+\rho\ \left(\frac{\text{d}\theta}{\text{d}t}\right)^2\ e^{i\left(\theta+\pi\right)}  

b)

 aP → = (d2xPdt2)2+(d2yPdt2)2t→\overrightarrow{a_P\ }\ =\ \sqrt{\left(\frac{\text{d}^2x_P}{\text{d}t^2}\right)^2+\left(\frac{\text{d}^2y_P}{\text{d}t^2}\right)^2}\overrightarrow{t}  

c)

 aP→ = aPtt→+aPnn→\overrightarrow{a_P}\ =\ a_{P^{ }}^t\overrightarrow{t}+a_{P^{ }}^n\overrightarrow{n}  

d)

 aP→ = dvPdtt→ +vP2ρn→\overrightarrow{a_P}\ =\ \frac{\text{d}v_P}{\text{d}t}\overrightarrow{t}\ +\frac{v_P^2}{\rho}\overrightarrow{n}  

4.

I versori della terna intrinseca sono...

a)

t→ = vP→∣vP→∣\overrightarrow{t}\ =\ \frac{\overrightarrow{v_P}}{\left|\overrightarrow{v_P}\right|}

b)

n→ = b→ ×t→\overrightarrow{n}\ =\ \overrightarrow{b}\ \times\overrightarrow{t}

c)

b→ = t→×n→\overrightarrow{b}\ =\ \overrightarrow{t}\times\overrightarrow{n}

d)

b→ = n→×t→\overrightarrow{b}\ =\ \overrightarrow{n}\times\overrightarrow{t}

5.

Il moto rettilineo del punto P nel piano...

a)

aPn →= 0\overrightarrow{a_P^n\ }=\ 0

b)

t→ = i→\overrightarrow{t}\ =\ \overrightarrow{i}

c)

t→ = cos⁡(α)i→+sin⁡(α)j→\overrightarrow{t}\ =\ \cos\left(\alpha\right)\overrightarrow{i}+\sin\left(\alpha\right)\overrightarrow{j}

d)

aP→ = (dsdt)2t→\overrightarrow{a_P}\ =\ \left(\frac{\text{d}s}{\text{d}t}\right)^2\overrightarrow{t}

6.

Il moto circolare uniforme del punto P

a)

s = Rωts\ =\ R\omega t

b)

vP → = ρdθdteiθ\overrightarrow{v_P\ }\ =\ \rho\frac{\text{d}\theta}{\text{d}t}e^{i\theta}

c)

vP→ = Rω\overrightarrow{v_P}\ =\ R\omega

d)

vP→ = dρdteiθ\overrightarrow{v_P}\ =\ \frac{\text{d}\rho}{\text{d}t}e^{i\theta}

7.

Il moto circolare uniforme del punto P

a)

aP→ = 0\overrightarrow{a_P}\ =\ 0

b)

aP→ = ωRt→+ω2Rn→\overrightarrow{a_P}\ =\ \omega R\overrightarrow{t}+\omega^2R\overrightarrow{n}

c)

aP→ = ω2Rn→\overrightarrow{a_P}\ =\ \omega^2R\overrightarrow{n}

d)

aP→ = ωRt→\overrightarrow{a_P}\ =\ \omega R\overrightarrow{t}

8.

Il moto circolare NON uniforme del punto P...

a)

∣aP→∣ = (ρd2θdt2)2+(ρ(dθdt)2)2\left|\overrightarrow{a_P}\right|\ =\ \sqrt{\left(\rho\frac{\text{d}^2\theta}{\text{d}t^2}\right)^2+\left(\rho\left(\frac{\text{d}\theta}{\text{d}t}\right)^2\right)^2}

b)

ap→t =ρd2θdt2ei(θ+π2) \overrightarrow{a_p}^t\ =\rho\frac{\text{d}^2\theta}{\text{d}t^2}e^{i\left(\theta+\frac{\pi}{2}\right)}\

c)

ap→n =−ρ(dθdt)2eiθ \overrightarrow{a_p}^n\ =-\rho\left(\frac{\text{d}\theta}{\text{d}t}\right)^2e^{i\theta}\

d)

ap→n =−ρ(dθdt)2ei(θ+π)\overrightarrow{a_p}^n\ =-\rho\left(\frac{\text{d}\theta}{\text{d}t}\right)^2e^{i\left(\theta+\pi\right)}

9.

Il moto circolare NON uniforme del punto P...

a)

∣aP→∣ = (d2sdt2)2+(dsdt)4\left|\overrightarrow{a_P}\right|\ \ =\ \sqrt{\left(\frac{\text{d}^2s}{\text{d}t^2}\right)^2+\left(\frac{\text{d}s}{\text{d}t}\right)^4}

b)

∣aP→∣ = d2xPdt2+d2yPdt2\left|\overrightarrow{a_P}\right|\ =\ \frac{\text{d}^2x_P}{\text{d}t^2}+\frac{\text{d}^2y_P}{\text{d}t^2}

c)

∣aP→∣ = (ρd2θdt2)2+(ρ(dθdt)2)2\left|\overrightarrow{a_P}\right|\ \ =\ \sqrt{\left(\rho\frac{\text{d}^2\theta}{\text{d}t^2}\right)^2+\left(\rho\left(\frac{\text{d}\theta}{\text{d}t}\right)^2\right)^2}

d)

∣aP→∣ = Rd2θdt2\left|\overrightarrow{a_P}\right|\ \ =\ R\frac{\text{d}^2\theta}{\text{d}t^2}

10.

Il moto parabolico del punto P ...

a)

t→= Ai→−2Btj→A2+4B2t2\overrightarrow{t}=\ \frac{A\overrightarrow{i}-2Bt\overrightarrow{j}}{\sqrt{A^2+4B^2t^2}}

b)

∣aP→∣ = 2B\left|\overrightarrow{a_P}\right|\ =\ 2B

c)

y = BA2x2y\ =\ \frac{B}{A^2}x^2

d)

vP→ = (At)2+(−Bt2)2 t→\overrightarrow{v_P}\ =\ \sqrt{\left(At\right)^2+\left(-Bt^2\right)^2\ }\overrightarrow{t}

11.

Quanto ti senti preparato su questo argomento?

a)

Ho capito tutto

b)

Dovrei ripassare alcuni dettagli

c)

Non ho ancora studiato

d)

Ho studiato, ma non mi è molto chiaro