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WorksheetsQ3
Total questions: 20
Worksheet time: 12mins
A system of linear equations is consistent if it has at least one solution.
TRUE
FALSE
If their graphs have one point of intersection, then the system is consistent and independent.
TRUE
FALSE
If the slopes of the first equation and second equation is not the same at all, then the system is consistent and independent.
TRUE
FALSE
Identify what equation of the line does the image shown.
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
Standard Form
Identify what equation of the line does the image shown.
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
Standard Form
Identify what equation of the line does the image shown.
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
Standard Form
Identify what equation of the line does the image shown.
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
Standard Form
To obtain the equation of a line, the given on the problem has a point P(x1,y1) and a slope m.
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
To obtain the equation of a line, the given on the problem has a line passing through P(x1,y1) and Q(x2, y2) .
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
To obtain the equation of a line, the given on the problem has x-intercept a and y- intercept b.
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
To obtain the equation of a line, the given on the problem has slope and y-intercept.
Point-Slope Form
Slope-Intercept Form
Two-Point Form
Intercept Form
Determine the standard equation of a line y=4x−3 .
4x+y=−3
4x−y=3
4x−y=−3
4x+y=3
2x−2y=2
What is the slope-intercept form of the given equation
y=−x−1
y=x+1
y=−x+1
y=x−1
2x−2y=2
What is the value of the slope?
1
-1
2
1/2
2x−2y=2
What is the value of the y-intercept?
1
-1
2
1/2
You either add or subtract the equations to get an equation in one variable
by substitution
by elimination
by graphing
by cross multiplication
The method of solving works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, substituting for the chosen variable and solving for the other.
by substitution
by elimination
by graphing
by cross multiplication
Make the conditional statement to inverse statement.
"If m∠A<90 , then ∠A is an acute angle."
If ∠A is acute angle , then <90m∠A<90
If m∠A is not 90 , then ∠A is not acute angle.
If ∠A is not acute angle , then m∠A is not 90
Make the conditional statement to converse statement.
"If m∠A<90 , then ∠A is an acute angle."
If ∠A is acute angle , then <90m∠A<90
If m∠A is not 90 , then ∠A is not acute angle.
If ∠A is not acute angle , then m∠A is not 90
Make the conditional statement to contrapositive statement.
"If m∠A<90 , then ∠A is an acute angle."
If ∠A is acute angle , then <90m∠A<90
If m∠A is not 90 , then ∠A is not acute angle.
If ∠A is not acute angle , then m∠A is not 90
