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WorksheetsCAPE Pure Math Unit 2 Module 1 Revision
Total questions: 51
Worksheet time: 29mins
In the expression
z= x+iy
which letter represents the real part?
z
x
y
i
The conjugate form of z=x-iy is
z*= x+iy
z*= -x-iy
z*= -x+iy
z*= x-iy
The modulus of
∣z∣ isr= (x+y)2−(x−y)2
r=x2+y2
r= x+y
The quadratic equation with imaginary roots is
x2−(αβ)x+αβ=0
x2+(α+β)x −αβ=0
x2−(α+β)x+αβ=0
x2+(αβ)−(α+β)=0
Step 1 in finding the Square Root of a Complex Number
Square both sides
Equate Real and Imaginary Parts
Express square root in the form
a+bi=x+yiSolve for x and y
Step 2 in finding the square root of a Complex Number
Square both sides
Equate real and imaginary parts
Solve for x and y
Express square root in the form
a+bi=x+yiStep 3 in finding the Square Root of a Complex Number
Solve for x and y
Equate real and imaginary parts
Square both sides
Express square root in the form
a+bi=x+yiStep 4 when finding the square root of a Complex Number
a+bi=x+yi Express square root in the form
Equate real and imaginary parts
Square both sides
Solve for x and y
How is zero represented as a Complex Number?
z=
(a)
Quadratic Equations of Complex Numbers with Non-real Coefficients can be solved using the Quadratic Formula. If the Quadratic Equation is given as
z2+iz+2=0 , what are the respective constants?a=1, b=1, c=2
a=0, b=1, c=2
a=1, b=i, c=2
a=0, b=-1, c=2
On the Argand Diagram, what are the respective labels of the axes?
Choose the two correct answers below.
The horizontal is the Imaginary Axis [Im(z)]
The horizontal is the Real Axis [Re(z)]
The vertical is the Real Axis [Re(z)]
The vertical is the Imaginary Axis [Im(z)]
Which of the following correctly represents the locus of a circle?
∣z−c∣=r
∣z−a∣=∣z−b∣
arg(z−a)=0
∣z−z1∣=k∣z−z2∣
Which of the following correctly represents the locus of a perpendicular bisector of a line segment?
∣z−a∣=∣z−b∣
∣z−z1∣=k∣z−z2∣
arg(z−a)=0
∣z−c∣=r
Which of the following correctly represents the locus of Half lines?
∣z−c∣=r
∣z−a∣=∣z−b∣
arg(z−a)=0
∣z−z1∣=k∣z−z2∣
Which of the following correctly represents the locus straight lines?
∣z−a∣=∣z−b∣
arg(z−a)=0
∣z−z1∣=k∣z−z2∣
Which of the following represents the correct formula related to De Moivre's Theorem?
zn=(cosθ±sinθ)n=(cosnθ±isinnθ)
zn=(sinθ±icosθ)n=(sinnθ±icosnθ)
zn=(cosnθ±isinnθ)n
cosθ=
sinθ
cos2θ
cos(−θ)
−sin(−θ)
sinθ
cosθ
sin2θ
−sin(−θ)
sinθ1
dxd(xn)=
xn+1
nxn−1
nxn+1
dxd(ax+b)=0
na(ax+b)n−1
na(ax+b)n+1
na(ax+b)n+1
a(n−1)(ax+b)n−1
dxd(eax+b)
ax+b(eax+b)
ax(eax+b)
a(eax+b)
lnax
axlnax
ax+ba
-sinx
-cosx
cosx
sinxcosx
sinx
cosx
-sinx
-sinxcosx
secx
cosxsinx
-cosecx
sec2x
tan x
tan2x
secxtanx
sec2tanx
-cot x
cot x
cosec x
-cosec x cot x
sinxcosx
cosec2x
−cosec2x
tan x
−1+x1
1−x21
1+x21
−1−x21
1−x21
−1−x21
−1+x21
1+x21
1−x21
−1+x21
−1−x21
1+x21
dxdax=
axlnx
alnx
lnax
ln xa
Which of the following correctly represents the Product Rule?
dxdy=
UV+dxdu(dxdv)
U(dxdv)+V(dxdu)
U(dxdv)−V(dxdu)
Which of the following correctly represents the Quotient Rule?
V2(V((dx)du)−U(dxdv))
V2(U(dxdv)−V(dxdu))
dxdy represents the gradient of
a) Tangent
b) Normal
(a)
−dxdy represents the gradient of
a) Normal
b) Tangent
(a)
The Parametric Equations are defined as:
x=f(t) and y=g(t)
The parametric differential is represented as;
dxdy=dtdy×dtdx
True or False?
(a)
dxd y=
dxdy
dydx
y
xy
dx d y2=
2y
2 dxdy
2 dx2d2y
2 y dxdy
(ax+b)(cx+d)P(x)=
(ax+b)A+(cx+d)B
(ax+b)A+(cx+d)B+(cx+d)2C
(ax+b)A+(cx2+dx+e)(Bx+C)
(ax+b)A+(cx2+dx+e)(Bx+C)+(cx2+dx+e)2(Dx+E)
(ax+b)(cx+d)2P(x)=
(ax+b)A+(cx+d)B
(ax+b)A+(cx2+dx+e)(Bx+C)
(x+2)A+(cx+d)B+(cx+d)2C
(ax+b)A+(cx2+dx+e)(Bx+C)+(cx2+dx+e)2(Dx+E)
(ax+b)(cx2+dx+e)P(x)=
(ax+b)A+(cx+d)B
(ax+b)A+(cx2+dx+e)(Bx+C)
(x+2)A+(cx+d)B+(cx+d)2C
(ax+b)A+(cx2+dx +e)(Bx+C)+(cx2+dx+e)(Dx+E)
(ax+b)(cx2+dx+e)P(x)=
ax+bA+cx+dB
x+2A+cx+dB+(cx+d)2C
ax+bA+cx2+dx+e(Bx+C)+(cx2+dx+e)2(Dx+E)
ax+bA+cx2+dx+e(Bx+C)
∫xy xn=
x1+C
n+1xn+1+C
n−1xn−1+C
∫xy(ax+b)n=
n+1(ax+b)n+1+C
a1[n+1(ax+b)n+1]+C
∫xy x1=
lnx +C
xlnx+C
∫xy ax+b1=
a1 ln (ax+b)+C
ax+b1 ln(ax+b)+C
ax1ln(ax+b)+C
∫xy eax+b=
ax1eax+b+C
a1eax+b+C
∫xy sin(ax+b)=
cos(ax+b)+C
a1(cos(ax+b))
−a1cos(ax+b)+C
∫xy cos(ax+b)=
ax1sin(ax+b)+C
a1sin(ax+b) +C
−a1sin(ax+b)+C
∫xy tanx=
−ln(cosx)+C
ln(cosx)+C
ln(secx)+C
−ln(secx)+
