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¿Qué alternativa muestra la definición de la derivada?
f´(a)=limh→0f(h−a)+f(a)hf´\left(a\right)=\lim_{h\rightarrow0}\frac{f\left(h-a\right)+f\left(a\right)}{h}f´(a)=h→0limhf(h−a)+f(a)
f´(a)=limh→0f(h+a)−f(a)hf´\left(a\right)=\lim_{h\rightarrow0}\frac{f\left(h+a\right)-f\left(a\right)}{h}f´(a)=h→0limhf(h+a)−f(a)
f´(a)=limh→af(h+a)−f(a)hf´\left(a\right)=\lim_{h\rightarrow a}\frac{f\left(h+a\right)-f\left(a\right)}{h}f´(a)=h→alimhf(h+a)−f(a)
f´(a)=limh→0f(h)−f(a)hf´\left(a\right)=\lim_{h\rightarrow0}\frac{f\left(h\right)-f\left(a\right)}{h}f´(a)=h→0limhf(h)−f(a)
Dadas las funciones. Calcula: limx→2+[f(x)+g(x)]\lim_{x\rightarrow2^+}\left[f\left(x\right)+g\left(x\right)\right]x→2+lim[f(x)+g(x)]
35\frac{3}{5}53
34\frac{3}{4}43
43\frac{4}{3}34
Dada la función f(x)=2x−1x+2f\left(x\right)=\frac{2x-1}{x+2}f(x)=x+22x−1 , indicar la asíntota horizontal.
A.H: y=1A.H:\ y=1A.H: y=1
A. H: y=−1A.\ H:\ y=-1A. H: y=−1
A. H: y=2A.\ H:\ y=2A. H: y=2
A. H: y=−2A.\ H:\ y=-2A. H: y=−2
Dada la función f(x)=x+2xf\left(x\right)=\sqrt{x}+2xf(x)=x+2x , ¿Qué alternativa muestra el cálculo correcto de la derivada en x=4?
f´(4)=limh→0h+4+2(h+4)−8hf´\left(4\right)=\lim_{h\rightarrow0}\frac{\sqrt{h+4}+2\left(h+4\right)-8}{h}f´(4)=h→0limhh+4+2(h+4)−8
f´(4)=limh→0h+4+2(h+4)−10hf´\left(4\right)=\lim_{h\rightarrow0}\frac{\sqrt{h+4}+2\left(h+4\right)-10}{h}f´(4)=h→0limhh+4+2(h+4)−10
f´(4)=limh→0h−4+2(h−4)+8hf´\left(4\right)=\lim_{h\rightarrow0}\frac{\sqrt{h-4}+2\left(h-4\right)+8}{h}f´(4)=h→0limhh−4+2(h−4)+8
f´(4)=limh→0h−4+2(h−4)−10hf´\left(4\right)=\lim_{h\rightarrow0}\frac{\sqrt{h-4}+2\left(h-4\right)-10}{h}f´(4)=h→0limhh−4+2(h−4)−10
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