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How to表達[2(1)+4]+[2(2)+4]+...+[2(10)+4]
∑α=1102a+4\sum_{\alpha=1}^{10}2a+4α=1∑102a+4
∑n=1102nθ+4\sum_{n=1}^{10}2n\theta+4n=1∑102nθ+4
∑n=1∞2n+4\sum_{n=1}^{\infty}2n+4n=1∑∞2n+4
What is the ans of the ∑n=0∞n+1\sum_{n=0}^{\infty}n+1n=0∑∞n+1
∞\infty∞
(n+1)×n÷2\left(n+1\right)\times n\div2(n+1)×n÷2
limans→∞\lim_{ans\rightarrow\infty}ans→∞lim
−112-\frac{1}{12}−121
What we called this? ⟶\longrightarrow⟶ ∑\sum_{ }^{ }∑
(a)
which is correct?
∑n=15n10π\sum_{n=1}^5n^{10\pi}n=1∑5n10π
∫−∞∞a+btan(x−y)\int_{-\infty}^{\infty}a+b^{\tan\left(x\sqrt{-y}\right)}∫−∞∞a+btan(x−y)
a2+b2=2ca^2+b^2=2ca2+b2=2c
e=mc2e=mc2e=mc2
(4x+9(64)x3)+∑n=152n−2=(∑n=1226n)+26\left(4x+\frac{9\left(\sqrt{64}\right)x}{3}\right)+\sum_{n=1}^52n-2=\left(\sum_{n=1}^226n\right)+26(4x+39(64)x)+n=1∑52n−2=(n=1∑226n)+26 What is the sum of ↑\uparrow↑ (a)
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