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WorksheetsUnit 6 Quadratics Review
Total questions: 36
Worksheet time: 9hrs 0mins
The x-value when the graph crosses the x-axis
x-intercept
maximum
interval of increase
interval of decrease
f(x)=ax2+bx+c
quadratic function
vertex
interval of increase
interval of decrease
What are the roots of the following graph:
x= 3, 4
x = -4, 3
x=-3, 4
x = -3, -4
Factor x2 + 12x + 20
(x + 2)(x + 10)
(x + 7)(x + 5)
(x + 6)(x + 6)
The solution, root, x-intercept, and zero of a problem are all the same thing.
x2 + 4x= 12
x2 − 10x - 11= 0
a, b, and c for
the quadratic equation:
4x2 – 8x = 3
What should you do first to solve this equation using quadratic formula?
x2 + 6x - 13 = 3
Get factored form
Write down: a=1, b=6, c=-13
Make it equal 0 by subtracting 3 on each side
Type it all in a calculator.
x2 + 4x - 40 = -8
Solve by the Quadratic Formula:
9u2−11u+7=0
18−11±131
1811±131
−1811±131
1811±i373
If b2-4ac is positive, the quadratic equation has:
Two real solutions that are different
Two imaginary solutions that are different
One real solution
One imaginary solution
If b2-4ac is negative, the quadratic equation has:
Two real solutions that are different
Two imaginary solutions that are different
One real solution
One imaginary solution
If b2-4ac is 0, the quadratic equation has:
Two real solutions that are different
Two imaginary solutions that are different
One real solution
One imaginary solution
2x2 + 7x - 15 = 0
Use the quadratic formula to find the solutions for
y = -x2 - 5x + 12
No Real Solution
x2 + 4x + 3 = 0
x2 + 4x - 40 = -8
y = x2 - 4x + 6
y = x + 2
Determine if the point (2,0) is a solution to the following system:
y=2x - 4
y=x2 - 4
Yes, because it works in one equation.
Yes, because it works in the both equations.
No, because it works in neither equation.
No, because it works in only one equation.
Which of the following graphs correctly represents:
y=x2
y=-2x+1
A system that contains one linear function and one quadratic function can have 0, 1, or 2 solutions.
True
False
Cannot be determined
Nobody cares
What are the solutions to this quadratic/ linear system?
(-2, 0) and (3,0)
No Solutions
-6 and -10
(1,-6)
Solve by completing the square.
x2−8x−20=0
x={−2, 10}
x={−10, 2}
x={−20, −8}
x={8, 20}
Solve by completing the square.
x2−12x+20=0
x={2, 10}
x={−10, −2}
x={−12, 20}
x={12, 20}
x2 - 4x + 4 = 20,
what goes in the blank?
(x - __ )2 = 20
