WorksheetsElectric Force
Total questions: 25
Worksheet time: 28mins
Calculate the force exerted between two charged objects separated by a distance of 0.6 m. One object has a charge of -5 C and the other has a charge of +2.0 C.
-1.5E-11 N
2.5E11 N
-2.5E11 N
-7.5E-10 N
FE= (k*q1*q2) / r2
According to Coulomb's Law, what will happen to the Electrostatic Force between 2 objects if the distance between them is is quadrupled?
the force will decrease to 1/16 the original strength
the force will increase by 16x
the force will increase by 4x
the force will decrease to 1/4 the original strength
As shown in the figure, the charge Q is midway between two other charges. If Q= -7.5 nC what must be the charge q1 so that charge q2 remains stationary as Q and q1 are held in place?
30 nC
15 nC
7.5 nC
60 nC
Figure shows the electric lines of force emerging from a charged body. If the electric field at A and B are EA and EB respectively and if the displacement between A and B is r then
EA > EB
EA < EB
EA = EB / r
EA = EB / r2
Based on the arrangement of the electric field lines in the diagram, what are the charges?
both charges are the same
the charges are opposite
they are neutral; no charge
Which statement best describes the electric fields in the image?
The charges are neutral.
Both charges are negative, so the field lines are alike.
The field lines move toward a positive charge and away from a negative charge.
The field lines move away from a positive charge and toward a negative charge.
