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Worksheets

Numerical CSE B

Total questions: 10

Worksheet time: 26mins

Name
Class
Date
1.

How many Significant digits are in the number of 0.002060

a)

3

b)

4

c)

5

d)

2

2.

If you round off  5\sqrt{5}  to four decimal places , then the corresponding relative error is

a)

 1.4321×105-1.4321\times10^{-5}  

b)

 1.4321×1051.4321\times10^{-5}  

c)

 1.4321×1031.4321\times10^{-3}  

d)

 3.2022×1033.2022\times10^{-3}  

3.

If in Ax=BAx=B  , the number of variables are greater than the number of equations then the system have : 


a)

no solution

b)

unique solution

c)

Infinite solution

d)

May or may not have solution

4.

Consider the following system of linear equations 3y2z=3,     2xy+4z=27,    4xy3z=33y-2z=3,\ \ \ \ \ 2x-y+4z=27,\ \ \ \ 4x-y-3z=3  Use Gauss-Seidel method  with the initial value  x(0)=0, y(0)=0, z(0)=0x^{\left(0\right)}=0,\ y^{\left(0\right)}=0,\ z^{\left(0\right)}=0 the value of  y(1)=y^{\left(1\right)}=  ?

a)

0.75

b)

1

c)

1.75

d)

0

5.

Starting from x0=1 x_0=1\   , one step of Newton-Raphson method in solving the equation  x3+3x7=0x^3+3x-7=0  gives the next value  \left(x_1\right)  as: 

a)

 x1=1.5x_1=1.5  

b)

 x1=0.5x_1=0.5  

c)

 x1=2x_1=2  

d)

 x1=2.5x_1=2.5  

6.

The order of convergence for Bisection method is

a)

1

b)

2

c)

1.5

d)

1.618

7.
a)

l21=2, u11=1, u12=3, u22=2l_{21}=2,\ u_{11}=1,\ u_{12}=3,\ u_{22}=2

b)

l21=2, u11=1, u12=2, u22=2l_{21}=2,\ u_{11}=1,\ u_{12}=2,\ u_{22}=2

c)

l21=2, u11=1, u12=2, u22=3l_{21}=2,\ u_{11}=1,\ u_{12}=2,\ u_{22}=-3

d)

l21=2, u11=1, u12=2, u22=5l_{21}=2,\ u_{11}=1,\ u_{12}=2,\ u_{22}=5

8.

If   dydx=log10(x+y)\frac{\text{d}y}{\text{d}x}=\log_{10}\left(x+y\right)  and  y(0)=2y\left(0\right)=2 , Then the value of   y(0.2)y\left(0.2\right)  in one step using Euler's method is

a)

1

b)

2.0602

c)

2.3010

d)

2.1386

9.

Which one of the following method is a Predictor corrector method.

a)

Euler's method

b)

Runge-Kutta method

c)

Modified Euler's method

d)

matrix inversion method

10.

Newton's formula for finding the square root of  a (a>0)a\ \left(a>0\right) 

is: 

a)

 xn+1=12(xnaxn)x_{n+1}=\frac{1}{2}\left(x_n-\frac{a}{x_n}\right)  

b)

 xn+1=12(xn+axn)x_{n+1}=\frac{1}{2}\left(x_n+\frac{a}{x_n}\right)  

c)

 xn+1=xnaxnx_{n+1}=x_n-\frac{a}{x_n}  

d)

 xn+1=2 xnx_{n+1}=2\ x_n