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Worksheets

Numerical CSE C

Total questions: 10

Worksheet time: 26mins

Name
Class
Date
1.

How many Significant digits are in the number of 0.007020

a)

3

b)

4

c)

5

d)

6

2.

If the number 37.46235 rounded of to four significant
digits then the percentage error is

a)

 6.27×1036.27\times10^3  

b)

 6.27×1056.27\times10^5  

c)

 6.27×1056.27\times10^{-5}  

d)

 6.27×1036.27\times10^{-3}  

3.

Which of the following operations are allowed in Gauss-Elimination method ?

a)

Swapping two columns

b)

Multiply a row by zero

c)

Swapping two rows

d)

Addition of two columns

4.

Starting from x0=1x_0=1  , one step of Newton-Raphson method in solving the equation   x3+3x7=0x^3+3x-7=0  
  gives the next approximate value  of the root (x1)\left(x_1\right)  as: 

a)

 x1=1.5x_1=1.5  

b)

 x1=0.5x_1=0.5  

c)

 x1=2x_1=2  

d)

 x1=2.5x_1=2.5  

5.

Consider the following system of linear equations 3y2z=3,     2xy+4z=27,    4xy3z=33y-2z=3,\ \ \ \ \ 2x-y+4z=27,\ \ \ \ 4x-y-3z=3  Use Gauss-Seidel method  with the initial value x(0)=0, y(0)=0, z(0)=0x^{\left(0\right)}=0,\ y^{\left(0\right)}=0,\ z^{\left(0\right)}=0   , the value of  y(1)=y^{\left(1\right)}=  ?

a)

0.75

b)

1

c)

1.75

d)

2

6.

The order of convergence for Bisection method is

a)

1

b)

1.5

c)

2

d)

1.618

7.
a)

l21=2, u11=1, u12=3, u22=2l_{21}=2,\ u_{11}=1,\ u_{12}=3,\ u_{22}=2

b)

l21=2, u11=1, u12=2, u22=2l_{21}=2,\ u_{11}=1,\ u_{12}=2,\ u_{22}=2

c)

l21=2, u11=1, u12=2, u22=3l_{21}=2,\ u_{11}=1,\ u_{12}=2,\ u_{22}=-3

d)

l21=2, u11=1, u12=2, u22=5l_{21}=2,\ u_{11}=1,\ u_{12}=2,\ u_{22}=5

8.

If dydx=log10(x+y)\frac{\text{d}y}{\text{d}x}=\log_{10}\left(x+y\right)  and  y(0)=2y\left(0\right)=2  , Then the value of  y\left(0.2\right) in one step using Euler's method is 

a)

2

b)

2.0602

c)

1.0602

d)

2.1386

9.

Which one of the following method is a Predictor corrector method.

a)

Euler's method

b)

Runge-Kutta method

c)

Modified Euler's method

d)

matrix inversion method

10.

Newton's formula for finding the square root of  a (>0)a\ \left(>0\right)  is: 

a)

 xn+1=12(xnaxn)x_{n+1}=\frac{1}{2}\left(x_n-\frac{a}{x_n}\right)  

b)

 xn+1=12(xn+axn)x_{n+1}=\frac{1}{2}\left(x_n+\frac{a}{x_n}\right)  

c)

 xn+1=xnaxnx_{n+1}=x_n-\frac{a}{x_n}  

d)

 xn+1=2 xnx_{n+1}=2\ x_n