NEW
Font size
Worksheets11 maths august month test
Total questions: 50
Worksheet time: 2hrs 6mins
The number of relations on a set containing 3 elements is.......
9
81
512
1024
If A= {(x,y) : y=sin x, x∈R }and B={(x,y) : y=cos x, x∈R } then A∩B Contains
no element
infinitely many elements
only one element
cannot be determined
If A = {1, 3, 5, 7, 9} and B = {2, 3, 5, 7}, what is A ∪ B?
{3, 5, 7}
{2, 3, 5, 7}
{2, 3, 5, 7, 9}
{1, 2, 3, 5, 7, 9}
If A = {1, 3, 5, 7, 9} and B = {2, 3, 5, 7}, what is A ∩ B?
{3, 5, 7}
{2, 3, 5, 7}
{2, 3, 5, 7, 9}
{1, 2, 3, 5, 7, 9}
The Universal Set = { -4, -3, -2, -1, 0, 1, 2, 3 ,4} and A = {0}.
What is the complement of A?
{-4, -3, -2, -1, 0, 1, 2, 3}
{-3, -2, -1, 1, 2, 3}
{-4, -3, -2, -1, 1, 2, 3, 4}
{-4, -3, -2, -1, 1, 2, 3}
If
P = {0, 1, 2, 3, 4}, Q = {4, 5, 6, 7}
R = {3, 6, 9}, and S = {6, 12, 18}
Then what is (P ∪ Q) ∩ (S ∪ R)?
{6}
{3, 6}
{4, 6}
{1, 2, 3, 4, 5, 6, 7, 9, 12, 18}
If
P = {0, 1, 2, 3, 4}, Q = {4, 5, 6, 7}
R = {3, 6, 9}, and S = {6, 12, 18}
Then what is (P -Q)
{6}
{0,1,2,3}
{4, 6}
{1, 2, 3, 4, 5, 6, 7, 9, 12, 18}
If
P = {0, 1, 2, 3, 4}, Q = {4, 5, 6, 7}
R = {3, 6, 9}, and S = {6, 12, 18}
Then what is (P ∆ S)=
{6}
{3, 6}
{4, 6}
{0,1,2,3,4,6,12,18}
Which of the following represents the shaded region?
A union B
A intersect B
A ⊂ B
B ⊂ A
R = { factors of 36 }.
n(R) =
T = { 4, 9, 3, n }.
If set S and set T are equal sets,
the value of m + n =
set V = { m, n, o, p },
find the number of subsets V.
A = {14, 16, 18, 20, 22, 24}
Sin[3π/2 - θ]=
cosθ
sinθ
-cosθ
-sinθ
Determine if these two sets are equal or equivalent.
A = {2, 6, 10, 14}
B = {6, 2, 14, 16}
Equal
Equivalent
List the elements of A Ո B
{5,9}
{2,3,7,6,8}
{2,3,5,9,7,6,8}
{1,4}
List the elements of (A U B)'
{1,4}
{2,3,5,6,7,8,9}
{2,3,6,7,8}
{5,9}
Determine if these two sets are equal or equivalent.
A = {2, 6, 10, 14}
B = {6, 2, 14, 16}
Equal
Equivalent
Solve y = mx + b for x
x = (y-b)/m
x = y/m - b
10x - 2 = 7x + 10
Solve
(((256)⁻¹/²)⁻¹/⁴)³
8
1/8
-1/8
-8
cos3A=
4cosA-3cos³A
4cos³A-3cosA
4COS³A+3cosA
3SinA- 4sin³A
square root of 7-4√3
2-√3
2+√3
-2+√3
-2-√3
2x + 1 = 2x - 1
If the functions f:(-3,3)→S defined by f(x)= x² is on to then S is
[-9,9]
R
[-3,3]
[0,9]
How many solutions does this equation have? 3x²-6x+2=0
One Solution
No Solution
two solutions
sinx > 1/2
x>π/3
x>π/6
x>π/2
x>π
The number of solutions of x²+ |x-1 |=1 is
1
0
2
3
If 3 is the logarthim of 343 then the base is....
5
7
6
9
One of roots of the equation x²-6x-8=0
x = 3
x = -2
x = 5
x = 4
The number of real roots of (x+3)⁴+(x+5)⁴=16 is
4
2
3
0
If a and b are the roots of the equation x²-kx+16=0 satisfy a²+b²=32 then the value of k is
10
-8
k=±8
6
The value of ˡᵒᵍ √2 ⁵¹² is
16
18
9
12
If f(θ)= |sinθ |+ |cosθ |, θ∈R then f(θ) is in the interval
|0,2 |
|1,√2 |
|1,2 |
|0,1 |
If sinα+cosα=b then sin2α is equal to
b²-1 if b≤√2
b²-1 if b>√2
b²-1 if b≥1
b²-1 if b≥√2
The maximum value of 4sin²x+3cos²x+sinx/2+cosx/2 is
4+√2
3+√2
9
4
1/cos80º -√3 /sin80º=
√2
√3
2
4
cos1º+cos2º+cos3º+.......+cos179º=
0
1
-1
89
which of the following is not true?
sinθ=-3/4
cosθ=-1
tanθ=25
secθ=1/4
sin(1440º)=
0
1
-1
1√2
What does If π<2θ<3π/2 then √2+√2+2cos4θ) equals to
-2cosθ
-2sinθ
2cosθ
2sinθ
X= {1,2,3,4} and R={(1,1),(1,2),(1,3),(2,2),(3,3),(2,1)(3,1),(1,4),(4,1)} then R is
reflexive
symmetric
transitive
eqivalance relation
The range of the function 1/1-2sinx
(-∞,-1)∪(1/3, ∞)
(-1,1/3)
[-1,1/3]
(-∞,-1)∪(1/3,∞)
The number of relations on a set containing 3 elements
9
81
512
1024
The function f:[0,2π]⇒[-1,1] defined by f(x)=sinx is
one to one
on to
bijection
cannot be defined
