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WorksheetsUnit 2a: Derivative Review AP calculus
Total questions: 72
Worksheet time: 4hrs 38mins
Select all x-values where the graph is not differentiable
-4
-3
-2
0
2
Find the derivative of:
a
b
c
d
Find the derivative of
f(x)=x4sin(x)
x4cos(x)−4x3sin(x)
x4cos(x)+4x3sin(x)
4x3cos(x)
−4x3cos(x)
Find the derivative of
g(x)=x2+23x−2
2x3
(x2+2)23(x2+2)
(x2+2)2−3x2+4x+6
(x2+2)29x2−4x+6
What is the acceleration of the object at time t = 2 s?
Find the average velocity from t = 3 to t = 5.
2 only
2 and 4
0 and 2 only
0,1 and 2
Find the value for that makes f(x) continuous.
0
1
1.5
2
No such value exists
what is the average rate of change of the function f(x)=x2-6x+6 from 2 to 6?
4
2
3
23/4
A
B
C
D
E
If f(x) = 4tan(x/2), then f'(x) =
4sec2(x/2)
-4csc2(x/2)
2sec2(x/2)
-2csc2(x/2)
What is the 2nd derivative of csc(x)?
-csc(x)cot(x)
cscxcot2x+csc3x
−csc2xcotx+cot3x
-cot2(x)
What is the slope of the line normal to the curve y = x2 + x at x = 1?
-1
-1/2
-1/3
-1/4
What is the equation of the line tangent to f(x)= 4x2+2x-1 at x=0?
y+1=2(x+1)
y=2x-1
y=2x+2
y= -x-1
Write the equation of the normal line of: f(x)=2x2−x1 at x = 1
y=−51x+54
y=5x−6
y−1=5(x−1)
y−1=−51(x−1)
Find where the function has a horizontal tangent line.
y=2x2−8x+3x = -2
x = 1
x = 2
x = 1/2
f(x) = x7 (5 + 8x)3
Which option shows the derivative?
h→0lim(h5(x+h)2−5x2)
5x2
10x
10
DNE
Find the limit as x approaches 1.
0
3
DNE
∞
You are given a table containing some values of differentiable functions [eval(f,x)], [eval(g,x)] and their derivatives. Use the table data and the rules of differentiation to solve each problem.
If h(x)=g(x)f(x) Find h′(2)
23
2
65
−3
You are given a table containing some values of differentiable functions [eval(f,x)], [eval(g,x)] and their derivatives. Use the table data and the rules of differentiation to solve each problem.
If h(x)=f(x).g(x) Find h′(3)
0
2
65
−3
If y =secx then dxdy=?
xtan2x
2xsecx.tanx
2xtanx
secx.tanx.2x
Find y′ if y=tan(3x2+2) .
y′=sec2(3x2+2)
y′=sec2(3x2+2)⋅6x
y′=sec2x⋅(3x2+2)⋅6x
y′=sec2(6x)
Let f be a continuous function for which f(-2)=1 and f(5)=-3. The Intermediate Value Theorem guarantees that
f(c)=2 for at least one c between -3 and 1
f(c)=0 for at least one c between -2 and 5
f(c)=0 for at least one c between -3 and 1
f(c)=2 for at least one c between -2 and 5
I only
II only
I, II, III
None
0
1
2
DNE
-4
-1
0
DNE
2
4
32
DNE
Let f be a continuous function for which f(-2)=1 and f(5)=-3. The Intermediate Value Theorem guarantees that
f(c)=2 for at least one c between -3 and 1
f(c)=0 for at least one c between -2 and 5
f(c)=0 for at least one c between -3 and 1
f(c)=2 for at least one c between -2 and 5
I only
II only
I, II, III
None
IVT
EVT
MVT
Is the above function differentiable for all values of x? Why?
Yes, the slope of the tangent line can be calculated for all values of x.
Yes, the function is continuous for all values of x so the function is differentiable.
No, the function has a sharp turn in the first quadrant so if is not differentiable.
No, the function is discontinuous so it is not differentiable.
For what value(s) of x is the function continuous but not differentiable?
x = -1
x = 0
x = 2
x = 3; x = -2
Is the function continuous, differentiable, both, or neither?
continuous
differentiable
both
neither
Is the function continuous, differentiable, both, or neither?
continuous
differentiable
both
neither
Find the values of a and b that make the function f differentiable.
(a)
Find the values of a and b that make the function f differentiable.
(a)
The function shown
is continuous at x = 1
is differentiable at x = 1
has a limit that exists at x = 1
exists at x = 1
The function shown
is continuous at x = 2
is differentiable at x = 2
has a limit that exists at x = 2
exists at x = 2
The function shown
is continuous at x = b
is differentiable at x = b
has a limit that exists at x = b
exists at x = b
The function shown
is continuous at x = c
is differentiable at x = c
has a limit that exists at x = c
exists at x = c
find g′(x) for g(x)=(h(x))3
g′(x)=3(h′(x))2
g′(x)=3h′(x)2
g′(x)=3(h(x))2⋅h′(x)
g′(x)=3h(x)2⋅h′(x)
If y=a(b(x)) , find y′(3)
−25
−20
9
15
