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WorksheetsModern Physics 01
Total questions: 25
Worksheet time: 18mins
A particle which has zero rest mass and non-zero energy and momentum must travel with a speed:
Equal to c, the speed of light in vacuum
Greater than c
Less than c
Tending to infinity
Dual nature of radiation is shown by
Diffraction and reflection
Refraction and Diffraction
Photoelectric effect alone
Photoelectric effect and diffraction
The energy of a photon of wavelength λ is given by
hλ
hcλ
λhc
hcλ
Rest mass of photon is
0
∞
between 0 and ∞
Equal to that of an electron
The momentum of a photon of energy hυ will be
hυ
chυ
hυc
υh
if the momentum of a photon is P, then its frequency is
cPh
hPc
cmh
hmc
An AIR Station is broadcasting the waves of λ = 300 m.
If the radiating power of the transmitter is 10kW then the number of photons radiated per second is :1.5×1029
1.5×1031
1.5×1033
1.5×1035
The energy of photon is E=hυ and the momentum of photon p=λh , then the velocity of photon will be
PE
EP
P2E2
3×108 secm
The approximate wavelength of photon of energy 2.48 eV is
500 A
5000A
2000 A
1000 A
The momentum of a photon in an X-Ray beam of wavelength 10−10m wavelength is
1.5×10−23 kg−secm
6.6×10−24 kg−secm
6.6×10−44 kg−secm
2.2×10−52 kg−secm
Energy of a quanta of frequency 1015 Hz and h=6.6×10−34J−sec will be
6.6×10−19J
6.6×10−12J
6.6×10−49J
6.6×10−41J
What is the momentum of a photon having frequency 1.5×1013Hz ?
3.3×10−29kg secm
3.3×10−34kg secm
6.6×10−34kg secm
6.6×10−30kg secm
which of following is true for photon
E=21mu2
p=2vE
E=21mc2
E=λhc
The spectrum of radiation 1.0×1014 Hz is in the infrared region. The energy of one photon of this in joules will be
6.62×10−48
6.62×10−20
36.62×10−28
3×6.62×10−28
The number of photons of wavelength 540 nm emitted per second by an electric bulb of power 100 W is ( take h= 6×10−34 )
100
1000
3×1020
3×1018
if the energy of the photon is increased by a factor of 4, then its momentum
Does not change
Decreases by a factor of 4
Increases by a factor of 4
Decreases by a factor of 2
Electron volt is unit of
Potential
Charge
Power
Energy
Assertion : The energy (E) and momentum (p) of a photon are related by p=cE
Reason : The photon behaves like a particle.
Both the assertion and the reason are true and the reason is a correct explanation of the assertion
Both the assertion and reason are true but the reason is not a correct explanation of the assertion
If the assertion is true but the reason is false
If both the assertion and reason are false
Assertion : Mass of moving photon varies inversely as the wavelength.
Reason : Energy of the particle = Mass×(speed of light)2
Both the assertion and the reason are true and the reason is a correct explanation of the assertion
Both the assertion and reason are true but the reason is not a correct explanation of the assertion
If the assertion is true but the reason is false
If both the assertion and reason are false
Monochromatic light of wavelength 667 nm is produced by a helium neon laser. The power emitted is 9mW. The number of photons arriving per second on the average at a target irradiated by this beam is
9×1017
3×1016
9×1015
3×1019
Light with an energy flux of 25×104 m2W falls on a perfectly reflecting surface at normal incidence. If the surface area is 15 cm2 , the average force exerted on the surface is :- AIPMT 2014
1.25×10−6 N
2.5×10−6 N
1.2×10−6 N
3.0×10−6 N
Electromagnetic wave of intensity 1400 m2W falls on metal surface on area 1.5 m2 is completely absorbed by it. Find out force exerted by beam. AIIMS 2016
14×10−5N
14×10−6N
7×10−5N
7×10−6N
A 200 W sodium street lamp emits yellow light of wavelength of 0.6 μm assuming it to be 25 % efficient converting electrical energy to light the number of photons of yellow light it emits per second is AIPMT 2012
62×1020
3×1019
1.5×1020
6×1018
The linear momentum of a 6 MeV photon is
0.01 eVsm−1
0.02 eVsm−1
0.03 eVsm−1
0.04 eVsm−1
The energy flux of sunlight reaching the surface of the earth is 1.52×103 m2W The photons in the sunlight have an average wavelength of 520 nm. How many photons per square meter are incident on the earth per second ?
4×1021
4×1034
4×1031
4×1028
