WorksheetsExponential and Logarithmic Equations
Total questions: 15
Worksheet time: 4hrs 31mins
To solve, 165x = 64x+7, what would be the correct set-up?
42(5x)=43(x+7) is one way to solve, which is another alternate set-up?
44(5x)=416(x+7)
82(5x)=88(x+7)
410x=43x+20
24(5x)=26(x+7)
Solve.
9(ex) - 31 =23
x = 1.79
x = 4.21
x = -3.5
x = 1.27
Solve:
log(x) + log(x+3) = 1
-5, 2
5, -2
-5
2
Solve:
log9(x)+log9(x+2)=log9(35)
5
-7
5, -7
-7, -13
To solve 8 = 25x+7, you could re-write 8 as what base?
8
4
2
Cannot be determined
Rewrite the exponential as a log.
23x+1 = 12
ln(2)= 3x+1
log2(12)= 3x+1
ln(6)=3x+1
log12(2)= 3x+1
Solve:
log2(x + 3)=5
x=2
x=29
x=7
x=32
Solve:
2log6(x-8)=2
14
81/8
18
9969
Which is the correct way to rewrite,log6(x-3)= 2, in order to solve.
62 = x-3
26 = x - 3
ln(2) = x-3
e6 = x-3
The first step to solve 8 + log 7 = 10 is...
Rewrite exponentially
Subtract 8 on both sides to isolate the log
Divide by 7 on both sides
Determine the correct set-up for:
log(x) + log (x-9) = 18
log(x)/(x-9)=18
log(-7x)=18
log(x)+(x-9)=18
log x(x-9)=18
Determine the correct set-up for:
log4(x-1) - log4(x+7) = log46
log4(x-1)/(x+7)=log4(6)
log4(x-1)(x+7)=log4(6)
log4(x+7)/(x-1)=log4(6)
(x-1)(x+7)=6
Interest Rate: 3.75%
Time: 25 years
Compounded Monthly
State the future account balance.
The function that models the decay of Carbon 14 is : y=y0e−0.0001216t where y is the amount of Carbon 14 left after t years, and y0 is the amount of Carbon 14 at t=0 .
How long before y=21y0 ? (What is the half life of Carbon 14?) Round to the nearest whole year.
5700 years
-5700 years
8.4×10−5 years
8.4×105 years
