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WorksheetsCLASS XII CHEMISTRY (P-BLOCK ELEMENTS)
Total questions: 20
Worksheet time: 11mins
Nitrogen is chemically inert. Why?
Due to presence of double bond require more energy to break
Due to presence of triple bond require more energy to break
Triple bond requires less energy to break
None of the above
Bismuth forms stable compound in +3 state than in +5 state . Why?
(a)
Nitrogen cannot exhibit co valancy more than four due to
Presence of vacant d orbitals
Due to large size
Due to absence of vacant d orbitals
Due to inert nature
Ammonia is a Lewis base and act as complexing agent.
It accepts electron pair
It is neither electron pair donar or acceptor
It act as electron pair donar.
It exhibit covalency more than five
- XeF6 on complete hydrolysis produces
XeOF 4
XeO2F 2
Xe O 3
Xe O 2
4.Which of the following is strongest acid among all ?
HI
HF
HBr
HCl
5.The shape of I F 7
T shape
trigonal bipyramidal
linear
pentagonal bipyramidal
The oxidation number of I in HIO 4
+4
+3
+ 7
+ 5
The correct order of acidic strength of hydrogen halides are
HF<HCl<HBr<HI
HF<HBr<HCl<HI
HI<HBr<HCl<HF
HI<HCl<HBr<HF
In the interhalogen compound XX', which among the following statement is correct
X is larger halogen, X' is smaller halogen
X is smaller halogen, X' is larger halogen
Both X and X' are of the same size
Size of X and X' doesn't matter
In group 15 elements as we move down the group
Non metallic character increase
Metallic character increase
Both
None the above
In groups 15 to 18, the poor shielding effect of d & f electrons are overcome by the increased shielding effect of the additional ________electrons.
s
p
d
f
In groups 15 to 18, the poor shielding effect of d & f electrons are overcome by the increased shielding effect of the additional ________electrons.
s
p
d
f
No. of lone pairs and type of hybridization in "S" in SO3 molecule are respectively
0 and sp2
1 and sp2
0 and sp3
1 and sp3
The geometry and hybridization in the central atom of IF7 are respectively
Octahedral and sp3d3
Trigonal bipyramidal and sp3d2
Pentagonal bipyramidall and sp3d3
Octahedral and sp3d3
The shapes of SO2 and SO3 are respectively
Linear and Trigonal planar
Angular and Trigonal planar
Linear and T shape
Angular and T shape
The type of Hybridization in the central atom in IF7 is
sp3d2
sp3d
sp3
sp3d3
Which of the following is not correctly matched
Acidic oxides – P2O5, NO2, Cl2O7
Basic oxides – Na2O, CaO, MgO
Neutral oxides – CO2, CO, BeO
Amphoteric oxides – ZnO, SnO, Al2O3
The property of halogens which is not correctly matched is
F > Cl > Br > I (Ionisation energy)
F > Cl > Br > I (Electronegativity)
I > Br Cl > F (Density)
F > Cl > Br > I (Electron affinity)
