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Worksheetsmake-up Quiz
Total questions: 15
Worksheet time: 17mins
An exothermic reaction causes the surroundings to ______.
warm up.
become acidic.
expand.
decrease its temperature.
release CO2
Calculate the amount of heat necessary to raise the temperature of 12.0 g of water from 15.4°C to 93.0°C. The specific heat of water = 4.18 J/g·°C
Which of these processes is endothermic?
O2(g) + 2H2(g) ---> 2H2O(g)
H2O(g) ---> H2O(l)
3O2(g) + 2CH3OH(g) ----->2CO2(g) + 2H2O(g)
H2O(s) -----> H2O(l)
Which of the following processes always results in an increase in the energy of a system?
The system loses heat and does work on the surroundings.
The system gains heat and does work on the surroundings
The system loses heat and has work done on it by the surroundings.
The system gains heat and has work done on it by the surroundings.
None of these is always true.
Methanol (CH3OH) burns according to the equation
2CH3OH(l) + 3O2(g) -----> 2CO2(g) + 4H2O(l), = -1454 kJ/mol.
How much heat, in kilojoules, is given off when 75.0 g of methanol is burned?
Complete and balance the following redox equation. What is the coefficient of H2S when the equation is balanced using the set of smallest whole-number coefficients?
H2S+MnO^4- ------->Mn2+ + SO42- (acidic solution)
1
2
4
5
Calculate the value of E°cell for the following reaction:
2Au(s) + 3Ca2+(aq) -----> 2Au3+(aq) + 3Ca(s)
-4.37 V
-1.37 V
-11.6 V
1.37 V
Consider an electrochemical cell based on the following cell diagram:
Pt | Pu3+(aq), Pu4+(aq) || Cl2(g), Cl-(aq) | Pt
Given that the standard cell emf is 0.35 V and that the standard reduction potential of chlorine is 1.36 V, what is the standard reduction potential E°(Pu4+/Pu3+)?
Which statement is true for a spontaneous redox reaction carried out at standard-state conditions?
E°red is always negative.
E°cell is always positive
E°ox is always positive
E°red is always positive.
In the following half equation, which is the oxidizing agent?
NO3-(aq) + 4H+(aq) + 3e-------> NO(g) + 2H2O
A radioisotope decays to give an alpha particle and Pb-208. What was the original element?
Se
Bi
Po
Hg
Rn
As a result of beta decay, the product nucleus is
one atomic number lower than the original element
two atomic numbers higher than the original element.
one atomic number higher than the original element.
two atomic numbers lower than the original element.
four atomic numbers lower than the original element.
Find the nuclear binding energy of potassium-40 (atomic mass = 39.9632591 amu) in units of joules per nucleon. [Data: neutron mass = 1.674928 ´ 10-24 g; proton mass = 1.672623 ´ 10-24 g; electron mass = 9.109387 ´ 10-28 g; NA = 6.0221367 ´ 1023 /mol; c = 2.99792458 ´ 108 m/s]
The only stable isotope of iodine is iodine-127. Predict the mode of decay of .
In the decay series there are six radioisotopes that decay by alpha emission, including Th-232 itself, and four radioisotopes that decay by beta emission. The final product of this series is a stable isotope. The symbol for this product is
