Free Printable Chapter 9 Simple harmonic motion (part 2)

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Chapter 9 Simple harmonic motion (part 2)

Total questions: 10

Worksheet time: 9mins

Name

Class

Date

If the length of a simple pendulum is doubled, its period will:

halve

increase by a factor of sqrt(2)

decrease by a factor of sqrt(2)

double

Based on your findings, which equation could best describe the pendulum’s period?

What is the period on Earth of a pendulum with a length of 2.4 m?

3.1 sec

1.9 sec

9.3 sec

5.1 sec

The period of a pendulum may be decreased by

Increasing the mass of the bob

moving the equilibrium point

decreasing the mass of the bob

shortening the length of pendulum

Position at which the body would come to rest if it were to lose all of its energy refers to

equilibrium position

maximum displacement / amplitude

periodic position

good position

When 𝜃 is small, sin 𝜃 is approximately equal to

$2\theta$

$Zero$

$\theta$

$\frac{\theta}{2}$

Which expression is correct for the time period of a simple pendulum:

$T\ \ \propto\ L$

$T\ \alpha\ m$

$T\ \alpha\ \sqrt{L}$

$T\ \alpha\ \sqrt{m}$

The restoring force acting on simple pendulum is given by.

$mg\sinθ\$

$–mg\sinθ$

$mg\cosθ$

$–mg\cosθ$

Pendulum motion approximates SHM provided

the length of the pendulum is short

the length of the pendulum is long

the angle of swing is small

the angle of swing is large

10.

An object is performing vertical SHM. X represents a position on its reference circle. Which point on the graph corresponds to X ?

A or B

C o D

100 %

Chapter 9 Simple harmonic motion (part 2)

Total questions: 10

Worksheet time: 9mins

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