A

f(x) = ∛(x + 3) + 2

B

f(x) = − ∛(x - 3) + 2

C

f(x) = ∛(x - 3) + 2

D

f(x) = ∛(x - 2) + 3

A

f(x) = − ∛(x + 3) − 1

B

f(x) = − ∛(x - 3) − 1

C

f(x) = ∛(x + 3) − 1

D

f(x) = ∛(x - 1) + 3

Switch the x and y

Solve for x

Draw a graph

solve for y

f^-1(x) = $$-\frac{1}{4}x-3$$  

f^-1(x) =

They are both functions, but not inverse functions.

They are reflected over y=x, but they are not both functions.

They are not reflected over y=x, and they are not both functions.

They are inverse functions.

 $f^{-1}\left(x\right)=x^2-2$  

 $f^{-1}\left(x\right)=x^2+2$  

 $f^{-1}\left(x\right)=\left(x+2\right)^2$  

 $f^{-1}\left(x\right)=\left(x-2\right)^2$  

 $f^{-1}\left(x\right)=x^2+8$  

 $f^{-1}\left(x\right)=x^2-8$  

 $f^{-1}\left(x\right)=\left(x+8\right)^2$  

 $f^{-1}\left(x\right)=\left(x-8\right)^2$  

 $\left(x-1\right)^{\frac{1}{3}}+2$  

 $\left(x+1\right)^{\frac{1}{3}}-2$  

 $\left(x+2\right)^{\frac{1}{3}}-1$  

 $\left(x-2\right)^{\frac{1}{3}}+1$