Free Printable Lecture Week 18: Lesson 18

Worksheets

Lecture Week 18: Lesson 18

Total questions: 15

Worksheet time: 42mins

Name

Class

Date

What is this piece of apparatus called

Pipette

Burette

Janette

Cuvette

What is the reading on this burette?

24.0cm³

25.8cm³

24.2cm³

23.9cm³

Calculate the average volume of acid needed for this neutralisation

15.2cm³

15.0cm³

35.5cm³

30.1cm³

30cm³ of NaOH is neutralised by 12.3cm³ of 0.2mol/l HCl. What is the concentration of the NaOH.

82 mol/l

0.82 mol/l

0.49 mol/l

0.082 mol/l

The reaction of perchloric acid (HClO4) with lithium hydroxide (KOH) is described by the equation
HClO4 + KOH → KClO4 + H2O
Suppose 100 mL of perchloric acid is neutralized by exactly 50,0 mL of 1.0 M of Potassium hydroxide. What is the concentration of the perchloric acid?

0.5M

50M

2.0M

1.0M

The reaction of hydrochloric acid (HCl) with ammonia (NH3) is described by the equation:
HCl + NH3 → NH4Cl
A student is titrating 100.0 mL of 0.10 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the ammonia?

20.0mL

500.0mL

100.0mL

5.0mL

A 50.0 mL sample of Ca(OH)₂ is neutralized by 300.0 mL of HCl solution with a pH of 1.3. Calculate the molarity of the Ca(OH)₂ solution.

1.0 M

0.50 M

0.15 M

0.30 M

30cm³ of NaOH is neutralised by 12.3cm³ of 0.2mol/l HCl. What is the concentration of the NaOH.

82 mol/l

0.82 mol/l

0.49 mol/l

0.082 mol/l

What is the molarity of a NaOH solution if 11.6 mL of 3 M HCl was used to neutralize 25 mL of NaOH?

1.392 M

0.155 M

0.718 M

10.

What mass of KHP will be completely neutrilized by 32.57 ml 0.175 M standard NaOH solution? The Molar Mass of KPH is 204.22 g/mol.

23.28 g KHP

1.164 g KHP

11.64 g KHP

2.328 g KHP

11.

Calculate the volume of a 0.15 M Ba(OH)2 solution required to completely neutralize 45 ml of a 0.29 M HNO3 solution.

43.5 ml

87 ml

23.3 ml

51.9 ml

12.

The K_sp expression for a saturated solution of Ca₃(PO₄)₂is

K_sp= [Ca²⁺][PO₄^3-]

K_sp= [3Ca²⁺][2PO₄^3-]

K_sp= [Ca²⁺]³[PO₄^3-]²

K_sp= [3Ca²⁺]³[2PO₄^3-]²

13.

The molar solubility of silver sulphide is 5.0 x 10^-17 mol/L. Calculate its solubility product.

K_sp= 5 x 10⁴⁹

K_sp= 5 x 10³³

K_sp= 5 x 10^-49

K_sp= 5 x 10^-33

14.

What is unsaturated?

A solution with more solute than solvent

A solution with less than the maximum amount of solutes

A solution with the perfect balance of solutes and solvents

A solution with solids at the bottom

15.

Which of the following salts is the most soluble?

AgCl, K_sp = 1.8x10^-10

AgBr, K_sp = 5.3x10^-13

AgI, K_sp = 8.3x10^-17

CuBr, K_sp = 5.3x10^-9

100 %

Lecture Week 18: Lesson 18

Total questions: 15

Worksheet time: 42mins

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