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WorksheetsAlgebra 1B Exam Review 1
Total questions: 28
Worksheet time: 14mins
Factor using the difference of 2 squares:
x2 – 4
(x+2)(x–2)
(x–2)(x–2)
(x+2)(x+2)
(x+4)(x–4)
Factor using the difference of 2 squares:
9x2 – 100
(x+10)(3x–10)
(3x–10)(3x-10)
(3x+10)(3x+10)
(3x+10)(3x–10)
Factor using the difference of 2 squares:
x2 = 81
(x+3)(x-9)=0
(x-9)(x–9)=0
(x+9)(x+9)=0
(x+9)(x-9)=0
4 – 13 =
7
-7
9
-9
-4 - 14 =
-10
-18
10
-18
-6 + 7 – 2 =
2
-8
1
-1
Multiply
(x)(x)(x) =
x3
3x
3
x
Multiply:
(12x2)(2x10)=
14x12
24x20
24x12
14x20
Simplify
x + x + x =
x3
3x
3
x
2x – 6x + 10x =
-4x
4x
6x
-6x
Distribute:
x(x – 1) =
x2-x
2x-x
x2–1
2x–1
(x–5)(x+4)
x2–9x–20
x2 +9x – 20
x2–x–20
x2–x+20
Factor:
x2+10x+25
(x+5)(x–5)
(x–5)(x–5)
(x+5)(x+5)
(x+1)(x+25)
Factor:
x2-4x+3
(x-3)(x-1)
(x+3)(x+1)
(x-3)(x+1)
(x-1)(x+4)
Factor:
x2+11x+18
(x+9)(x+2)
(x+3)(x+6)
(x+18)(x+1)
(x–9)(x–2)
Factor out a 2 from the following equation:
4x2–8x+12=0
and you get:
2(2x2–4x+6)=0
2(2x2–4x-6)=0
2(2x2+8x+6)=0
2(2x2–4x+24)=0
What would the 2 solutions of x for the following be?
(x–13)(x+13)=0
Hint...separate/”divorce” each and set them equal to 0 to solve for x...
x=13 and x=0
x=-13 and 0
x=-13 and x=13
none of the above
Which of the following would be a perfect equation factoring for “the difference of 2 squares”?
100–x
100x2–10
x2–10
x2–100
Find the a, b, and c values for the following quadratic equation:
x2+14x–12=0
a=2, b=14, c=-12
a=1, b=14, c=12
a=0, b=14, c=-12
a=1, b=14, c=-12
Find the a, b, and c values for the following quadratic equation:
3x2–4x+2=5
a=3, b=4, c=5
a=3, b=-4, c=-3
a=3, b=-4, c=2
a=3, b=4, c=-3
If a=1, b=2, c=-1, then the discriminant, b2-4ac =
9
-9
8
-8
If a=3, b=0, c=-1, then the discriminant, b2-4ac =
-12
9
12
-9
If the discriminant, b2-4ac is positive, the graph
Has 2 real solutions
Has 1 real solution
Has no real solutions
Has infinite solutions
If the discriminant, b2-4ac is zero, the graph
Has 2 real solutions
Has 1 real solution
Has no real solutions
Has infinite solutions
If the discriminant, b2-4ac is negative, the graph
Has 2 real solutions
Has 1 real solution
Has no real solutions
Has infinite solutions
If the a value of the graph is POSITIVE, the graph will open
upward
downward
The graph for the following equation:
-x2 +9x – 20
will open
upward, since it has a positive a value (1)
downward, since it has a negative a value (-1)
What is the Feast day of the Immaculate Conception
December 12th
December 6th
December 18th
December 8th
