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Laplace and Inverse Laplace Transform

Total questions: 40

Worksheet time: 20mins

Name
Class
Date
1.

Laplace Transform transforms a function from

a)

f(t) to F(s)f\left(t\right)\ to\ F\left(s\right)

b)

F(s) to f(t)F\left(s\right)\ to\ f\left(t\right)

c)

f(t) to f′(t)f\left(t\right)\ to\ f'\left(t\right)

d)

f"(t) to f′(t)f"\left(t\right)\ to\ f'\left(t\right)

2.

Which one is the correct definition of Laplace Transform?

a)

F(s)=∫0∞e−stf(t)dtF\left(s\right)=\int_0^{\infty}e^{-st}f\left(t\right)dt

b)

F(s)=∫0tf(t)g(t−u)F\left(s\right)=\int_0^tf\left(t\right)g\left(t-u\right)

3.

What is Laplace Transform for e−2te^{-2t}  ?

a)

1s−2\frac{1}{s-2}  

b)

1s+2\frac{1}{s+2}  

c)

2s\frac{2}{s}  

d)

1s2\frac{1}{s^2}  

4.

What is Laplace Transform for sin⁡ 2t\sin\ 2t  ?

a)

2s2+2\frac{2}{s^2+2}  

b)

ss2+2\frac{s}{s^2+2}  

c)

2s2+4\frac{2}{s^2+4}  

d)

ss2+4\frac{s}{s^2+4}  

5.

What is Laplace Transform for 6 sin⁡ 2t6\ \sin\ 2t  ?

a)

2s2+4\frac{2}{s^2+4}  

b)

ss2+4\frac{s}{s^2+4}  

c)

6s2+4\frac{6}{s^2+4}  

d)

12s2+4\frac{12}{s^2+4}  

6.

Define this property:  L(f(t)eat)=F(s−a)L\left(f\left(t\right)e^{at}\right)=F\left(s-a\right)  

a)

Linearity Property

b)

First Shifting Property

c)

Convolution Theorem

d)

Second Shifting Property

7.

What is the formula for Laplace First Order Derivative?

a)

L(𝑓′(𝑡))=𝑠𝐹(𝑠)−𝑓(0)ℒ\left(𝑓′(𝑡)\right)=𝑠𝐹(𝑠)−𝑓(0)

b)

L(𝑓"(𝑡))=𝑠2𝐹(𝑠)−𝑠𝑓(0)−𝑓′(0)ℒ\left(𝑓"(𝑡)\right)=𝑠^2𝐹(𝑠)−𝑠𝑓\left(0\right)−𝑓′\left(0\right)

c)

L(𝑓′(𝑡))=𝑠2𝐹(𝑠)−𝑓(0)ℒ\left(𝑓′(𝑡)\right)=𝑠^2𝐹(𝑠)−𝑓(0)

8.

L(e3tt)L\left(e^{3t}t\right) Based on first shifting property, what is  aa   value?

a)

1

b)

2

c)

3

d)

4

9.

Find L(e3tt)L\left(e^{3t}t\right)  

a)

1(s2)\frac{1}{\left(s^2\right)}  

b)

1(s−3)2\frac{1}{\left(s-3\right)^2}  

c)

1(s−2)2\frac{1}{\left(s-2\right)^2}  

d)

1(s)\frac{1}{\left(s\right)}  

10.

L(e2t sin⁡ t)L\left(e^{2t\ }\sin\ t\right)  What is a and f(t)?

a)

a=2, f(t)=e2ta=2,\ f\left(t\right)=e^{2t}  

b)

a=4, f(t)=cos⁡ ta=4,\ f\left(t\right)=\cos\ t  

c)

a=2, f(t)=sin⁡ ta=2,\ f\left(t\right)=\sin\ t  

11.

Find L(e2tsin⁡ 2t)L\left(e^{2t}\sin\ 2t\right)  

a)

1(s−1)2+1\frac{1}{\left(s-1\right)^2+1^{ }}  

b)

s(s−2)2+4\frac{s}{\left(s-2\right)^2+4}  

c)

s(s−4)2+1\frac{s}{\left(s-4\right)^2+1}  

12.

Find L(t3−3t2+5t)L\left(t^3-3t^2+5t\right)  

a)

6s4−(6s3)+5s2\frac{6}{s^4}-\left(\frac{6}{s^3}\right)+\frac{5}{s^2}  

b)

3s3−(1s(2))+1s\frac{3}{s^3}-\left(\frac{1}{s^{\left(2\right)}}\right)+\frac{1}{s}  

c)

2s3−(3s(2))+5s\frac{2}{s^3}-\left(\frac{3}{s^{\left(2\right)}}\right)+\frac{5}{s}  

13.

L(t cos⁡ 6t)L\left(t\ \cos\ 6t\right)  Which Laplace property is use to solve this?

a)

Linearity Property

b)

Derivative of Laplace Transform

c)

First Shifting Property

d)

Second Shifting Property

14.

L(t sin⁡ 4t)L\left(t\ \sin\ 4t\right)  What is n, f(t) and F(s)?

a)

n=1, f(t)=sin⁡ 4t, F(s)=ss2+16n=1,\ f\left(t\right)=\sin\ 4t,\ F\left(s\right)=\frac{s}{s^2+16}  

b)

n=4, f(t)=t, F(s)=4s2+16n=4,\ f\left(t\right)=t,\ F\left(s\right)=\frac{4}{s^2+16}  

c)

n=1, f(t)=cos⁡ 6t, F(s)=ss2+14n=1,\ f\left(t\right)=\cos\ 6t,\ F\left(s\right)=\frac{s}{s^2+14}  

15.

Find L(tsin⁡ 4t)Find\ L\left(t^{ }\sin\ 4t\right)  

a)

2s2+4\frac{2}{s^2+4}  

b)

−4s(s2+4)2-\frac{4s}{\left(s^2+4\right)^2}  

c)

−8s(s2+16)2-\frac{8s}{\left(s^2+16\right)^2}  

16.

L(sin⁡2t)L\left(\sin^2t\right)  What is  f(t), f′(t) and f(0)f\left(t\right),\ f'\left(t\right)\ and\ f\left(0\right)  ?

a)

f(t)=sin⁡2t, f′(t)=2 cos⁡t, f(0)=0f\left(t\right)=\sin^2t,\ f'\left(t\right)=2\ \cos t,\ f\left(0\right)=0  

b)

f(t)=sin⁡2t, f′(t)=sin⁡ 2t, f(0)=0f\left(t\right)=\sin^2t,\ f'\left(t\right)=\sin\ 2t,\ f\left(0\right)=0  

c)

f(t)=cos⁡2t, f′(t)=− sin⁡2t, f(0)=1f\left(t\right)=\cos^2t,\ f'\left(t\right)=-\ \sin2t,\ f\left(0\right)=1  

17.

What is the formula for Laplace Second Order Derivative?

a)

L(𝑓′(𝑡))=𝑠𝐹(𝑠)−𝑓(0)ℒ\left(𝑓′(𝑡)\right)=𝑠𝐹(𝑠)−𝑓(0)

b)

L(𝑓"(𝑡))=𝑠2𝐹(𝑠)−𝑠𝑓(0)−𝑓′(0)ℒ\left(𝑓"(𝑡)\right)=𝑠^2𝐹(𝑠)−𝑠𝑓\left(0\right)−𝑓′\left(0\right)

c)

L(𝑓"(𝑡))=𝑠2𝐹(𝑠)−𝑓(0)ℒ\left(𝑓"(𝑡)\right)=𝑠^2𝐹(𝑠)−𝑓(0)

18.

Find L(cos⁡ t)L\left(\cos\ t\right)  

a)

1s2+1\frac{1}{s^2+1^{ }}  

b)

1s2+4\frac{1}{s^2+4}  

c)

ss2+1\frac{s}{s^2+1}  

19.

Find L(e3t(t3−3t2+5t))L\left(e^{3t}\left(t^3-3t^2+5t\right)\right)  

a)

2(s−3)4−(3((s−3)3))+5(s−3)2\frac{2}{\left(s-3\right)^4}-\left(\frac{3}{\left(\left(s-3\right)^3\right)}\right)+\frac{5}{\left(s-3\right)^2}  

b)

6(s−3)4−(6(s−3)3)+5(s−3)2\frac{6}{\left(s-3\right)^4}-\left(\frac{6}{\left(s-3\right)^3}\right)+\frac{5}{\left(s-3\right)^2}  

c)

2(s−3)3−(3(s−3)(2))+5s−3\frac{2}{\left(s-3\right)^3}-\left(\frac{3}{\left(s-3\right)^{\left(2\right)}}\right)+\frac{5}{s-3}  

20.

What is the Laplace Transform for f(t)=t3f\left(t\right)=t^3  ?

a)

1s3\frac{1}{s^3}  

b)

2s3\frac{2}{s^3}  

c)

6s4\frac{6}{s^4}  

d)

3s3\frac{3}{s^3}  

21.

Inverse Laplace transform, transform

a)

f(t) to F(s)f\left(t\right)\ to\ F\left(s\right)

b)

F(s) to f(t)F\left(s\right)\ to\ f\left(t\right)

c)

f′(t ) to f(t)f'\left(t\ \right)\ to\ f\left(t\right)

d)

f(t) to f′(t)f\left(t\right)\ to\ f'\left(t\right)

22.

Find L−1(ss2+25)L^{-1}\left(\frac{s}{s^2+25}\right)  

a)

cos 25t

b)

sin 5t

c)

cos 5t

23.

Find L−1(1s2+1)L^{-1}\left(\frac{1}{s^2+1}\right)  

a)

sin t

b)

sin 5t

c)

cos t

24.

L−1(6(s)−4ss2+25)L^{-1}\left(\frac{6}{\left(s\right)}-\frac{4s}{s^2+25}\right)  What is the property use to find the Inverse Laplace Transform of this equation?

a)

Second Shifting Property

b)

First Shifting Property

c)

Linearity Property

d)

Convolution theorem

25.

L−1 (4ss2+25+23(s2+1))L^{-1\ }\left(\frac{4s}{s^2+25}+\frac{2}{3\left(s^2+1\right)}\right)  

a)

4 cos⁡ 25t+23sin⁡ t4\ \cos\ 25t+\frac{2}{3}\sin\ t  

b)

cos⁡ 5t+ sin⁡ t\cos\ 5t+\ \sin\ t  

c)

4 cos⁡ 5t +23sin⁡ t4\ \cos\ 5t\ +\frac{2}{3}\sin\ t  

26.

The  L−1(4(s2+9))L^{-1}\left(\frac{4}{\left(s^2+9\right)}\right)  is  a sin⁡ 3ta\ \sin\ 3t  . What is a?

a)

23\frac{2}{3}  

b)

43\frac{4}{3}  

c)

33  

27.

L(t(4))L\left(t^{\left(4\right)}\right)  ?

a)

24s5\frac{24}{s^5}  

b)

4s5\frac{4}{s^5}  

c)

1s5\frac{1}{s^5}  

28.

L−1(24s5)L^{-1}\left(\frac{24}{s^5}\right) is  t4t^4  . What is  L−1(1s(5))L^{-1}\left(\frac{1}{s^{\left(5\right)}}\right)  ?

a)

24s5\frac{24}{s^5}  

b)

124t4\frac{1}{24}t^4  

c)

124t5\frac{1}{24}t^5  

29.

L−1(4s(3))L^{-1}\left(\frac{4}{s^{\left(3\right)}}\right)  

a)

4t34t^3  

b)

2t22t^2  

c)

2t32t^3  

30.

L−1(3s2+36)L^{-1}\left(\frac{3}{s^2+36}\right)  

a)

12 sin⁡ 6t\frac{1}{2\ }\sin\ 6t  

b)

35sin⁡ 5t\frac{3}{5}\sin\ 5t  

c)

cosh⁡2t\cosh2t  

31.

L−1(F(s−5))=e5tf(t)L^{-1}\left(F\left(s-5\right)\right)=e^{5t}f\left(t\right)  Based on first shifting property for Inverse Laplace transform, what is aa   value?

a)

4

b)

5

c)

3

32.

L−1(1(s−3)2)L^{-1}\left(\frac{1}{\left(s-3\right)^2}\right)  

a)

e2tte^{2t}t  

b)

ett2e^tt^2  

c)

e3tte^{3t}t  

33.

L−1(3s(s+2)4)L^{-1}\left(\frac{3s}{\left(s+2\right)^4}\right)  

a)

12e−t(3t2−t(3))\frac{1}{2}e^{-t}\left(3t^2-t^{\left(3\right)}\right)  

b)

e−2t(32t2−t(3))e^{-2t}\left(\frac{3}{2}t^2-t^{\left(3\right)}\right)  

c)

e−t(32t2−t(3))e^{-t}\left(\frac{3}{2}t^2-t^{\left(3\right)}\right)  

34.

L−1(s(s−4)2+16)L^{-1}\left(\frac{s}{\left(s-4\right)^2+16}\right)  

a)

e4t(cos⁡ 4t+sin⁡ 4t)e^{4t}\left(\cos\ 4t+\sin\ 4t\right)  

b)

e2t(cos⁡ 2t+sin⁡ 2t)e^{2t}\left(\cos\ 2t+\sin\ 2t\right)  

c)

e2t(4cos⁡ t+4sin⁡ t)e^{2t}\left(4\cos\ t+4\sin\ t\right)  

35.

s2+2s+5s^2+2s+5  Complete the square

a)

(s+4)2+2\left(s+4\right)^2+2  

b)

(s+2)2+4\left(s+2\right)^2+4  

c)

(s+2)2+16\left(s+2\right)^2+16  

36.

L−1((s+2)s2+2s+5)L^{-1}\left(\frac{\left(s+2\right)}{s^2+2s+5}\right)  

a)

f(t)=e−tsin⁡(2t)+e−tcos⁡(2t)f(t)=e^{-t}\sin(2t)+e^{-t}\cos(2t)  

b)

f(t)=12e−tsin⁡(2t)+e−tcos⁡(2t)f(t)=\frac{1}{2}e^{-t}\sin(2t)+e^{-t}\cos(2t)  

c)

f(t)=e−tsin⁡(2t)+12e−tcos⁡(2t)f(t)=e^{-t}\sin(2t)+\frac{1}{2}e^{-t}\cos(2t)  

37.

Find the partial fraction for (2s−8)(s−2)(s−3)\frac{\left(2s-8\right)}{\left(s-2\right)\left(s-3\right)}  

a)

2s−2−4s−3\frac{2}{s-2}-\frac{4}{s-3}  

b)

3s−2−2s−3\frac{3}{s-2}-\frac{2}{s-3}  

c)

4s−2−2s−3\frac{4}{s-2}-\frac{2}{s-3}  

38.

Find the Inverse Laplace for (2s−8)(s−2)(s−3)\frac{\left(2s-8\right)}{\left(s-2\right)\left(s-3\right)}  

a)

4e−2t−2e−3t4e^{-2t}-2e^{-3t}  

b)

2e−2t−4e−3t2e^{-2t}-4e^{-3t}

c)

e−2t−e−3te^{-2t}-e^{-3t}  

39.

By convolution theorem, find Laplace Transform for  X(s)=1s(s2+4)X\left(s\right)=\frac{1}{s\left(s^2+4\right)}  

a)

12 sin⁡ 2t\frac{1}{2\ }\sin\ 2t  

b)

14cos⁡ 2t−4\frac{1}{4}\cos\ 2t-4  

c)

14(1−cos⁡ 2t)\frac{1}{4}\left(1-\cos\ 2t\right)  

40.

By convolution theorem, find F(s) and G(s) X(s)=1s(s2+4)X\left(s\right)=\frac{1}{s\left(s^2+4\right)}  

a)

F(s)=1s;G(s)=1s2+4F\left(s\right)=\frac{1}{s};G\left(s\right)=\frac{1}{s^2+4}  

b)

F(s)=1s;G(s)=1s3+4sF\left(s\right)=\frac{1}{s^{ }};G\left(s\right)=\frac{1}{s^3+4s}  

c)

F(s)=1s2+4;G(s)=1sF\left(s\right)=\frac{1}{s^2+4};G\left(s\right)=\frac{1}{s^{ }}