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Unit 4aLesson 6 Practice Problems

Total questions: 13

Worksheet time: 7mins

Name
Class
Date
1.

The coordinates of Q are (0, 35) and R are (1.5, 14). Which function represents the graph.

a)

35⋅ (2.5)1.5x\ 35\cdot\ \left(2.5\right)^{1.5x}

b)

35⋅ 0.41.5x35\cdot\ \sqrt[1.5]{0.4}^x

c)

35 ⋅ (0.41.5)x\ 35\ \cdot\ \left(\frac{0.4}{1.5}\right)^x

d)

35⋅ 30.4 x35\cdot\ ^3\sqrt{0.4}\ ^x

e)

35 ⋅ (2.51.5)x\ 35\ \cdot\ \left(\frac{2.5}{1.5}\right)^x

2.

A medication has a half-life of 4 hours after it enters the bloodstream. A nurse administers a dose of 225 milligrams to a patient at noon.


Which equation represents the amount of medication left after h hours?

a)

f(h) = 225⋅(0.5)h4f\left(h\right)\ =\ 225\cdot\left(0.5\right)^{\frac{h}{4}}

b)

f(h) = 225⋅(−0.5)hf\left(h\right)\ =\ 225\cdot\left(-0.5\right)^h

c)

f(h) = 225⋅(4 12)hf\left(h\right)\ =\ 225\cdot\left(4\ \frac{1}{2}\right)^h

d)

f(h) = 225⋅(0.54)hf\left(h\right)\ =\ 225\cdot\left(\frac{0.5}{4}\right)^h

e)

f(h) = 225⋅0.54hf\left(h\right)\ =\ 225\cdot\sqrt{0.5}^{4h}

3.

At the beginning of the year a blogger had 200 subscribers. Since then, the number of subscribers has been doubling every 8 weeks.


Select ALL equations that represent the number of subscribers, S, in terms of w weeks since the beginning.

a)

S = 200⋅w2S\ =\ 200\cdot w^2

b)

S = 200⋅2w8S\ =\ 200\cdot2^{\frac{w}{8}}

c)

S = 200 ⋅(28)wS\ =\ 200\ \cdot\left(\frac{2}{8}\right)^w

d)

S = 200⋅28wS\ =\ 200\cdot\sqrt[8]{2}^w

e)

S = 200⋅8wS\ =\ 200\cdot8^w

4.

Select ALL equations that represent the revenue, r, as a function of m months.

a)

r(m)= 72,000(1.25)m3r\left(m\right)=\ 72,000\left(1.25\right)^{\frac{m}{3}}

b)

r(m) = 72,000⋅1.253mr\left(m\right)\ =\ 72,000\cdot\sqrt[3]{1.25}^m

c)

r(m)= 72,000(1.25)mr\left(m\right)=\ 72,000\left(1.25\right)^m

d)

r(m)= 72,000(1.25)6mr\left(m\right)=\ 72,000\left(1.25\right)^{6m}

e)

r(m)= 72,000⋅1.25mr\left(m\right)=\ 72,000\cdot\sqrt{1.25}^m

5.

Select ALL equations that represent the weight, w, of a catfish, t weeks since it was first weighed.

a)

w(t) = 0.3⋅(1.25)t2w\left(t\right)\ =\ 0.3\cdot\left(1.25\right)^{\frac{t}{2}}

b)

w(t) = 0.3⋅1.25tw\left(t\right)\ =\ 0.3\cdot\sqrt{1.25}^t

c)

w(t) = 0.3⋅1.254tw\left(t\right)\ =\ 0.3\cdot\sqrt[4]{1.25}^t

d)

w(t) = 0.3⋅(1.25)t4w\left(t\right)\ =\ 0.3\cdot\left(1.25\right)^{\frac{t}{4}}

6.

The value of a car is decreasing exponentially according to the function V(y).

V(y) = 25,800(0.73)y3V\left(y\right)\ =\ 25,800\left(0.73\right)^{\frac{y}{3}}

According to the function, the decay factor 0.73 occurred over how many years?

a)

3

b)

73

c)

25

d)

8

7.

An insect population is rapidly increasing by doubling every 15 days. If there were originally 100 insects, which equation represents the insects after d days?

a)

f(h) = 100⋅215hf\left(h\right)\ =\ 100\cdot2^{15h}

b)

f(h) = 100⋅ (12)hf\left(h\right)\ =\ 100\cdot\ \left(\frac{1}{2}\right)^h

c)

f(h) = 100⋅2h15f\left(h\right)\ =\ 100\cdot2^{\frac{h}{15}}

d)

f(h) = 100⋅30hf\left(h\right)\ =\ 100\cdot30^h

8.

In 2000 a country had a population of 12.8 thousand. By 2010 the population had increased by 13%. During that decade, the population can be reasonably modeled by an exponential function.


Write an equation to show the country's population p(d), in thousands of people, d decades since 2000.

a)

p(d) = 12.8(1.13)dp\left(d\right)\ =\ 12.8\left(1.13\right)^d

b)

p(d) = 12.8(0.13)dp\left(d\right)\ =\ 12.8\left(0.13\right)^d

c)

p(d) = 12.8 + 1.3dp\left(d\right)\ =\ 12.8\ +\ 1.3d

d)

p(d) = 12.8+0.13dp\left(d\right)\ =\ 12.8+0.13^d

9.

In 2000 a country had a population of 12.8 thousand. By 2010 the population had increased by 13%. During that decade, the population can be reasonably modeled by an exponential function.


Select ALL expressions that represent the country's population in 2003.

a)

 p(d) = 12.8(1.13)310p\left(d\right)\ =\ 12.8\left(1.13\right)^{\frac{3}{10}}

b)

 p(d) = 12.8⋅1.13103p\left(d\right)\ =\ 12.8\cdot\sqrt[10]{1.13}^3

c)

 p(d) = 12.8⋅1.13310p\left(d\right)\ =\ 12.8\cdot\sqrt[3]{1.13}^{10}

d)

 p(d) = 12.8⋅(1.13)2003p\left(d\right)\ =\ 12.8\cdot\left(1.13\right)^{2003}

e)

 p(d) = 12.8⋅(1.13)13p\left(d\right)\ =\ 12.8\cdot\left(1.13\right)^{\frac{1}{3}} 

10.

 y=a⋅bxy=a\cdot b^x 

Write an equation for the graph in the form:

a)

 y = 8⋅2.25xy\ =\ 8\cdot\sqrt{2.25}^x 

b)

 y = 8⋅2.25xy\ =\ 8\cdot2.25^x 

c)

 y = 8 ⋅(2.25)x3y\ =\ 8\ \cdot\left(2.25\right)^{\frac{x}{3}} 

d)

 y = 8⋅(0.44)x2y\ =\ 8\cdot\left(0.44\right)^{\frac{x}{2}} 

11.

 y=a⋅bxy=a\cdot b^x 

Write an equation that represents the graph in the form

a)

 y=15⋅1.864xy=15\cdot\sqrt[4]{1.86}^x 

b)

 y=15⋅0.544xy=15\cdot\sqrt[4]{0.54}^x 

c)

 y=15⋅3.754xy=15\cdot\sqrt[4]{3.75}^x 

d)

 y=15⋅1.86xy=15\cdot\sqrt{1.86}^x 

e)

 y=15⋅3.75xy=15\cdot\sqrt{3.75}^x 

12.

Between 1998 and 2018 inflation for prices of goods and services has been about 51%.

If a salon charged $15 for a haircut in 1998, which expression shows what they would've charge in 2005 to keep up with inflation?

a)

15(1.51)72015\left(1.51\right)^{\frac{7}{20}}

b)

15(1.51)715\left(1.51\right)^7

c)

15(1.51)1215\left(1.51\right)^{\frac{1}{2}}

13.

The value of a house is increasing exponentially. At the beginning of 2015 it was worth $160,000. At the beginning of 2019 it was worth $164,800.

What expression represents the value of the house in 2022?

a)

160,000(1.03)74160,000\left(1.03\right)^{\frac{7}{4}}

b)

160,000(1.03)7160,000\left(1.03\right)^7

c)

160,000(1.03)73160,000\left(1.03\right)^{\frac{7}{3}}

d)

160,000(1.03)410160,000\left(1.03\right)^{\frac{4}{10}}