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WorksheetsLand Survey and GNSS
Total questions: 60
Worksheet time: 1hrs 28mins
The satellite constellation uses 24 satellites in how many orbital planes?
4
3
6
12
The satellite constellation uses 24 satellites PLUS how many operational spares?
8
3
10
2
Select the most correct answer
All satellites transmit on the same 2 L-Band frequencies, just different pseudo-random codes
All satellites transmit on their own frequency but the same pseudo-random code
Satellites transmit on the L1 frequency for precision military ranging
The user segment:
Consists of 24 satellites in 6 orbital planes
Receives, decodes, processes and displays the information given form the satellites
Is located in ground stations around the world
Is located in Colorado Springs, USA!
If 4 satellites are in view:
Position and altitude (3D) information will be available
Only 2D position information will be available
RAIM will be available
Fault Detection and Exclusion (FDE) will be available
GNSS navigation works on the principle of:
The user segment sending radio waves to the satellites and the radio energy reflecting back off the satellite
Secondary Surveillance Radar (SSR)
GNSS measures distance from the satellite by measuring travel time of a radio signal from the satellite to the receiver and uses triangulation or tri-lateration to determine a position
VHF using Frequency Modulation
Ephemeris Data is:
The same as Almanac Data
An error caused by the Earth's atmosphere
The predicted location of all the satellites in the constellation
The satellites position in space
Almanac data is:
Only contained inside the control segment
Position and orbit information of all the satellites in the constellation
Not relevant to GNSS
The current position of one satellite at time of transmission
GPS satellite signals are:
High Power
Very High Power
Low power
The datum used for GPS and instrument approaches is:
NZGS74
The true North Pole
WGS84
The centre of the universe
A RAIM prediction must be performed?
Before take-off if you plan to use a GNSS approach
Before take-off if you plan to use any RNAV route
Before commencing any approach
Every morning
Is it preferable to have a high or low PDOP?
High
Low
In the middle
If a receiver's clock is fast (clock error) it will make the receiver think the satellite is FURTHER away than it actually is, this clock error is minimised by:
Trimming
Each receiver having an atomic clock
There's no such thing as clock error
It cannot be eliminated
GBAS, WAAS and DGPS all use:
Precisely surveyed ground stations to improve GNSS accuracy
The Russian GLONASS system ONLY
An ILS system instead of satellites
DME stations which can give you a groundspeed read out using UHF band
An RNAV route is designated RNAV2, how far either side of track must you remain at least 95% of the time?
2NM either side
1NM either side
0.5NM either side
4NM either side
Global coverage for each system is generally achieved by a satellite constellation of 18–30 satellites at .........................
Medium Earth Orbit
Lower Earth Orbit
High Earth Orbit
Geosynchronous Orbit
How many GPS Satellites are currently in orbit around the earth?
18
22
24
12
How close to your actual position can a GPS receiver measure?
Within 10.0 cm
Within 1.0 m
Within 10.0 m
Within 20.0 m
The three segments of the GPS system are the space segment, the user segment, and the .............. segment.
control
interface
computer
human
What are the clocks called that are used by GPS satellites to very accurately keep time?
Millisecond clocks
Microsecond clocks
Nanosecond clocks
Atomic clocks
How many measurements (minimum) must be made to give us an accurate estimation trilateration of our position on the earth?
1
2
3
4
The purpose of the ................ segment is to Monitor, Predict, Calibrate and Update transmissions from satellites
Control
User
Space
Human
How long does it take a GPS satellite to orbit the earth?
4 Hours
8 Hours
12 Hours
24 Hours
When using GNSS an aircraft on an air transport operation must have:
Two GNSS receivers
Two other sole means navigation systems
One other sole means navigation system
When nominating an alternate, the alternate aerodrome must have:
At least one GNSS based approach
At least one ground based instrument approach
More than one GNSS based instrument approach
What is the definition of surveying?
To draw a shape to interpret what the piece of land being surveyed looks like.
It is a means of making accurate measurements of the earths surface.
To calculate the amount of material contained in a parcel of land.
To calculate the types of minerals located on a parcel of land.
_______________________ surveying the discipline of land surveying that relates to the laws of land ownership and the definition of property boundaries
Cadastral
Geodetic
Topographic
G.P.S
__________________________ surveys are concerned with measurement and mapping of the physical features of the earth.These features are all natural and manmade features.
G.P.S
Plane
Geodetic
Topographic
What are the functions of surveying ?
To determine the existing relative horizontal and vertical positions and to establish marks to control construction or to indicate land boundaries.
To determine longitude and latitude and the relative elevation.
To determine the shape of a piece of land and how its elevation changes across the landscape.
To determine the landscape of the land and how many acres are in the section being surveyed.
How many acres are in a field that measures 5280ft x 1320ft?
160
320
640
25
A closed contour line with one or more higher contour
lines inside represents
cliff
hill
valley
cave
Theodilite is a measuring device which is included
under category of
First order measurements
Second order measurements
Third order measurements
Fourth order measurements
A tape is standardized at 100N pull. If the load applied
is 120N the sag correction
L1 W12
(1.12 × 10–6)
L1 W12
(1.273 × 10–6)
L1 W12
(1.73 × 10–6)
L1 W12
(1.53 × 10–6)
The long and short sides of a rectangle measure
9.32 m and 4.82 m, with errors ± 5 mm. Express the
area of correct number of significant figures
44.98 m2
44.96 m2
44.92 m2
44.85 m2
An offset is laid out 3° from its true direction of the
field. If the scale of plotting is 10 m to 1 cm, find the
maximum length of offset so that the displacement of
the point on paper may not exceed 0.25mm
4.43
4.58
4.23
4.77
The combined correction of curvature and refraction
for distance of 1.29 km is
0.234 m
0.121 m
0.112 m
0.187 m
The observation ray between two triangulation stations
A and B just grazes the sea. If the heights of A and B are
6000 m and 2000 m respectively, the distance AB is
(Let radius of earth R = 6440 km)
432.4 km
438.3 km
450.2 km
442.4 km
The constant for an instrument is 750, the value of
C = 0.3 m and intercept S = 2 m. The distance from
instrument to the staff when the micrometer readings
are 4.326 and 4.283 and the line of sight is at +8° 361
when the staff was held vertical is
172.4 m
(173.2 m
174.8 m
170.8 m
The volume of 130 m long road of formation width
10 m, side slopes 1 : 1, average depth of cutting along
center of line is 5m and slopes of ground in cross-section is 10 to 1 is
9880 m3
9723 m3
9624 m3
9892 m3
In a region with magnetic declination of 4°E, the magnetic
fore bearing (FB) of a line AB was measured as N
82° 501 E. There was a local attraction at A. To determine
the correct magnetic bearing of the line, a point O
was selected at which there was no local attraction. The
magnetic FB of line AO and OA were observed to be
S 42° 401 E and N 48° 201 W respectively. What is the
true FB of line AB?
N 81° 50’
N 82° 10’ E
N 79° 30’ E
N 84° 10’ E
The length of the tape is 30 m and the sag is 30.35 cm
at the mid span under a tension of 100 N, the weight of
the tape is
0.248 N/m
0.269 N/m
0.326 N/m
0.459 N/m
Two distances of 30 and 100 meters were accurately
measured out and the intercepts on the staff between the
outer stadia webs were 0.176 m at the former distance
and 0.892 m at the latter. The tacheometric constant K IS
100
97.7
95
96.2
A flag staff of 2 m height was erected on topic of hill
(Q) and the observations were made from two stations
P and R, 50 meters apart. The horizontal angle measured
at P between R and top of flag staff was 50° 30’
and that measured at R between the top of the flag-staff
P was 50° 18’. Angle of elevation to top of staff was
measured to be 10° 121 at P. The angle of elevation
to top of flag staff and was measured to be 10° 48’ at
R. Staff readings on B.M when the instrument was at
P = 1.826 m and that with the instrument at R = 2.285
m. The elevation of the top of hill Q if the BM was
485.065 m is
485.36 m
488.32 m
224.94 m
498.32 m
Match the following
d , a, b, c
A, b, d, c
d, c, b, a
c, a, b, d
Match the following
d, c, a, b
a, c, d, b
a, b, c, d
d, b, a, c
(i) Optical square is better than prism square.
(ii) In both optical and prism squares, the principle of
operation is same.
only (i) is correct
only (ii) is correct
Both (i) and (ii) are correct
None of the above
A Circular curve has 300 m radius and 55° deflection
angle, then the apex distance is
38.23m
38.21m
39.23m
40.24m
The length of mid ordinate in the above question is
37.23m
38.62m
33.89m
32.43m
Find the area between line AB and the stream taken at a
regular interval of 30 m along line AB, using simpson’s
rule.
7980 m2
6352 m2
5652 m2
4734 m2
The correction for collimation is
0.021
0.048
0.023
0.032
Correction for refraction is
1.33mm
1.34m
1.38m
1.29m
The following observations were taken during testing
of a dumpy level s
If A and B are 100 m apart the angle of inclination of
line of collimation is
14’ 15.50’
12’ 23.30’
10’ 2.29’
131 3.40
The distance between two points A and B by tachometer
fitted with anallactic lens which made a vertical angle
of +10° 46’ and staff intercept of 1.763 m. Later on the
constants of instrument were changed to 100 and 0.5.
The percentage error is computed horizontal distance is
0.287%
0.321%
0.262%
0.213%
In a quadrilateral ABCD, the coordinates of points
are as follows
the area of figure is
4.68 hectares
7.06 hectares
9.12 hectares
12.51 hectares
After surveying an area with plane table at a station it
was detected that the centering of the instrument was
not done accurately. The displacement of the plotted
point at right angles to the ray was 20 cm. The scale
used was 1 cm = 20 m. Determine the error in the plotted
position of the point (in cm)
0.031
0.04
0.01
0.02
To continue a survey line AB past an obstacle, a 400
m long line BC was set out perpendicular to AB and
from C angles BCD and BCE were set out 60° and
45° respectively. Determine the lengths which must be
chained off along CD and CE in order that ED may be
in line with AB produced.
747 m, 620.4 m
(B) 827 m, 580.3 m
800 m, 565.6 m
852 m, 648.3 m
What is the principle of surveying?
Working from part of whole
Working from whole to part
Working from higher to lower.
Working from lower to higher
If the image formed by the objective lens is not in the same plane with cross hairs, then it is known as
Focusing of eye piece
Focusing of objective
Parallax
Aberration
The automatic check for leveling in case of height of instrument method is
𝚺BS — 𝚺FS = Last RL — RL
𝚺BS —𝚺FS = 𝚺Rise — 𝚺fall
𝚺Rise — 𝚺fall = 𝚺last RL — first RL
None of these
Surveyor’s chain consists of 100 links along a length of
100 ft long
33 ft long
66 ft long
50 ft long
