WorksheetsGraphs of Logs/Expos and Expo Word Problems
Total questions: 27
Worksheet time: 54mins
Describe domain of the function shown: y=log2(x+1)
(-∞,∞)
(-1,∞)
(-1,3)
(∞, -1)
Describe range of the function shown: y=log2(x+1)
(-∞,∞)
(-1,∞)
(-1,3)
(∞, -1)
Write the equation of the function f(x)=log3x after the following transformations:
Translate 6 units left and 4 units up.
g(x)=log3(x+6)+4
g(x)=log3(x+4)-6
g(x)=log3(x-6)+4
g(x)=3log(x+6)+4
Choose the equation of the graph shown.
Choose the equation of the graph shown.
Choose the equation of the graph shown.
Choose the equation of the graph shown.
Choose the equation of the graph shown.
Rewrite log28 = 3 in exponential form.
28 = 3
23 = 8
32 = 8
83 = 2
Without a calculator, evaluate log41
1/4
0
-1
not possible
Without technology, determine which of the following is an increasing function. Check all that apply.
y = log2 (x - 4)
y = log3 (x+3)
y = -2log5 (x-1)
y = 1/2 log x + 4
Which of the following has a domain of all real numbers, x > 2 ?
y = log2 x
y = log3 (x+2)
y = log4 (x - 2)
y = log7 x - 2
What is the asymptote of y = 2x - 3
y = 0
y = -3
x = 0
x = -3
What equation matches the graph?
f(x) = 3x
f(x) = (⅓)x
f(x) = -3x
What is the asymptote of y = 2x-3 ?
y = 0
y = -3
x = 0
x = -3
Which equation matches the graph?
y = 4x + 3
y = 4x - 3
y = 4x + 3
y = 4x - 3
A sailboat that costs $5,950 decreases in value by 11% per year. How much will the boat be worth after 6 years?
$5,884.00
$5,178.97
$2,992.96
$2,957.04
The number of research papers in Professor Sycamore area of expertise has been increasing by 5% every year. Given that 30,010 research papers were published this year. Assuming the trend continues, which equation projects the amount of research papers published in x years?
y = 30,010 (.05)x
y = 30,010 (1.05)x
y = 30,010 (.95)x
y = 30,010 (5)x
A city doubles its size every 64 years. If the population is currently 225,000, what will the population be in 128 years?
The population will be 225,000.
The population will be 450,000.
The population will be 900,000.
The population will be 1,800,000.
