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Simple and compound interest

Total questions: 10

Worksheet time: 50mins

Name
Class
Date
1.
Emilio borrows $1200 from a bank with 8% simple interest per year.  How much will he have to pay back total in 2 years?
a)
$150
b)
$192
c)
$1350
d)
$1392
2.
Principal = $500
Interest rate =5%
Time = 5 years
What is the interest earned?
a)
95
b)
105
c)
125
d)
135
3.
Jenna borrowed $5,000 for 3 years and had to pay $1,350 simple interest at the end of that time. What rate of interest did she pay?
a)
6%
b)
6%
c)
8%
d)
9%
4.

What is the simple interest on a housing loan of $350,000, over 30 years with a rate of 4.5%?

a)

$350,00

b)

$47,250

c)

$350,000

d)

$472,500

5.

What would be the total amount of your student loan, if you had to pay back a loan of $10,550, at a rate of 3% over the course of 10 years ?

a)

$13,715

b)

$3165

c)

$31,650

d)

$10,550

6.

Jacob borrows $500 from Abraham and agrees to have the loan compounded annually for 5 years with an interest rate of 2.5%. How much will the total amount be that Jacob owes?

a)

$565.70

b)

$262609.38

c)

$65.70

d)

$630.20

7.

Hei-Hei has $1500 in a retirement account earning 5% interest compounded annually. After 5 years how much does Hei-Hei have in the account?

a)

$1750

b)

$2010.14

c)

$2500

d)

$1914.42

8.

Daniel invests $360 in a bank account that is compounded annually for 8 years with an interest rate of 5.5%. What will be the total amount in the account after the 8 years is over?

a)

$625.88

b)

$950.12

c)

$315.45

d)

$552.49

9.
Caiden earned $475 from mowing lawns last summer.He deposited this money in an account that pays an interest rate of 3.8% compounded annually. What will be his balance after 15 years?
a)

$827.52                          

b)

$831.10                

c)

$839.45                    

d)

$846.80                  

10.
The Arnold's took out a loan for $195,000 to purchase a home. At 4.3% interest rate compounded annually, how much will they have paid after 30 years?
a)
$412,749.79
b)
$529.305.61
c)
$689,546.99
d)
$640,891.53