WorksheetsQuadratic Formula Review
Total questions: 12
Worksheet time: 17mins
Given −8x2+6x−7=0
Label the values
a = -8
b = 6
c = -7
a = -7
b = -8
c = 6
a = -8x2
b = 6x
c = -7
a = 6
b = -7
c = -8
Given x2=5x−9
Label the values
a = 0
b = 5
c = -9
a = 1
b = -5
c = 9
a = 0
b = -5
c = -9
a = 1
b = -5
c = -9
How do you find the discriminant?
a2 − 4bc
x=−2ab
b2−4ac
c=(21b)2
If the discriminant is positive, then the solution will be
one real solution
two real solutions
no real solutions
all real numbers
If the discriminant is negative, then the solution will be
one real solution
two real solutions
no real solutions
all real numbers
Determine the value of the discriminant
x2 + 7x + 13=0
101
3
-101
-3
For the function below, what is the discriminant?
___________
x² + 8x + 16 = 0
4
-4
0
2
What all must occur BEFORE you can use the Quadratic Formula? Check ALL that apply.
Get the equation equal to zero
Get the equation in Standard Form
Get the equation in Vertex Form
Divide the equation by 2
Solve using the quadratic formula :
x2 - 7x + 12 = 0
x = 3, -4
x = -3, 4
x = 3, 4
x = -3, -4
Use the quadratic formula to find the solutions for
y = -x2 - 5x + 12
No Real Solution
3x2−10x+1=0
Solve using the quadratic formula.
x=6−10±88
x=3−5±222
x=610±112
x=35±22
2x2=8x+3
Step 1: 2x2−8x−3=0
Step 2: x=48±64−4(2)(−3)
Step 3: x=48±40
Step 4: x=48±210
Step 5: x=24±10
Suzanne solved the equation using this process.
Did she make a mistake?
If yes, in which line does her first mistake appear?
Suzanne made no errors.
Step 2
Step 3
Step 4
Step 5
