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WorksheetsFinal Exam Review - Algebra I
Total questions: 104
Worksheet time: 5hrs 19mins
(-1, -1)
(2, 5)
(5, 11)
(-4, -7)
29.5
-13.5
6
3.25
6
-6
3.5
-3.5
36x6
36x8
6x8
not here
What is the range of y = x2 - 2x + 6?
x≥5
y≥5
All Real Numbers
y ≤5
y=x²+2x-3
k2 -2k - 24
k2+7x+10
n2 + 16n + 63
x2 + 13x + 12 = 0
The solution, root, x-intercept, and zero of a problem are all the same thing
Identify the 'b' value: y = 16x2 -8x -24
16
-8
8
-24
y = 2(x - 2)2 + 5
What are the Zeroes for this graph?
x= 0 and x= -4
x= 0 and x= 4
y= 0
x= 2
Given the equation for this parabola, does this parabola have a maximum or minimum value?
y = −(x−4)2 − 3Maximum
Minimum
What is the green dot on the parabola called?
maximum
minimum
roots
zeros
x2 + 6x - 13 = 3
2x2 + 7x - 15 = 0
x2 + 4x - 40 = -8
a, b, and c for
the quadratic equation:
4x2 – 8x = 3
Solve for x:
3x−5=43
2
4
8
8x + 4y = 12
y = -2x + 3
Not factorable.
x2+2x-15=0 are
4x + 1 = 7x - 5
7 - 5x = 12
17xy - x
12x + 9
b2 + 8b + 7
4h² - 17h + 4
x2+4x+8
x2+8x+8
x2+8x+6
x2+6x+8
5x2+16x+8
6x2+12x+8
6x2+16x+6
6x2+16x+8
Simplify:
−3(a + 5)
-3a+15
3a+15
3a-15
-3a-15
(x4 )(x12)
x-3
Evaluate, follow the Order of Operation
(3x – 5)(y + 2) when x = 2, y = 3
(a)
Evaluate, follow the Order of Operation
2x – 3y + 2 when x = -4, y = 2
(a)
Evaluate
15 – 2x2 when x = 2
(a)
Evaluate when x = -4, y = 2
(a)
Is 7 a solution of the equation x2 – x + 2 = 42?
yes
no
Is 5 a solution of the inequality 13 + 2x ≤ 23 ?
yes
no
Simplify
-2-(-7)
(a)
A rectangle has a width of 2x + 1 . It has a length of 4x + 2. Write an expression for the perimeter of this rectangle.
(a)
Solve the following quadratics equation by completing the square...
x2 + 4x + 1 = 0
x = -2 ± √3
x = -3 ± √2
x = 2 ± √3
x = 2 ± √2
Use the quadratic formula to find the solutions for
y = -x2 - 5x + 12
No Real Solution
2x² + 13x + 15
A
B
C
D
The height of an object thrown into the air can be modeled by the formula y=−16x2+70x+95 , where y is in feet after x seconds.
What is the height of the object after 5 seconds?
95 feet
45 feet
70 feet
171.56 feet
A ball is thrown into the air with an upward velocity. Its height, h, after t seconds is given by the function below.
h=−16t2+64t+960
What is the maximum height reached?
1024 feet
64 feet
960 feet
2 feet
a2 b0 a-3
y = 57(1/3)x
a2 + 2a - 24 = 0
2x2 + 17x + 21 = 0
x2 + 13x + 12 = 0
a, b, and c for
the quadratic equation:
4x2 – 8x = 3
-5x6(3x2 - 12x + 30)
-15x8 + 60x7 - 150x6
15x8 - 60x7 - 150x6
8x6 - 17x + 35
-8x6 + 17x - 35x2
x² - 121
Classify the polynomial by its degree:
25x3 + 3y6 + 2x3y4
25
7
6
2
-11√21 - 11√21
Simplify the expression
49
7
√98/√2
It's already simplified
