Worksheets2nd Semester Review 2022
Total questions: 27
Worksheet time: 27mins
Simplify x2−8x+122x−3−x2−8x+12x−1 as much as possible.
x−61
x2−8x+12x−4
x+12x
x2−8x+121
Add and simplify. x2+x−63x+x2+x−6x−2
x2+x−64x−2; x=−3, 2
x2+x−64x−2; x=3, −2
x2+x−62x; x=−3, 2
x2+x−62x; x=3, −2
Simplify the radical expression. x2+5x+6x2−x−12
x+3x+4
x+3x−4
x+2x+4
x+2x−4
Solve for x. 3x=6x+2
6
-2
2
-6
Solve for x. 10x=8x−5
-10
25
-25
10
Determine the restriction(s) for the following. x2−1x2−8x−9
x=±1
x=±9
x=8
x=−1
In the equations shown, x represents a real number. What is the solution to this equation? 3x−5=8
x=16
x=64
x=23
x=−23
Solve for x. 2x−3−5=−2
x=4
x=6
x=-6
x=-4
What are the best first two(2) steps in solving he equation below for x?
x+5−4=6
Add 4 to both sides of the equation, and then square both sides.
Subtract 4 from both sides of the equation, and then square both sides.
Square both sides of the equation, and then add 4 to both sides.
Square both sides of the equation, and then subtract 4 to both sides.
What are the best first two(2) steps in solving the equation below for x?
6x−11=15
Add 11 to both sides of the equation, and then take the square root of both sides.
Take the square root of both sides of the equation, and then add 11 to both sides.
Add 11 to both sides of the equation, and then square both sides.
Square both sides of the equation, and then add 11 to both sides.
Rewrite in exponential form: (5b)3
(5b)32
(5b)23
5b23
5b32
Rewrite in exponential form (x)3
(x)32
(x)23
32x
23x
Simplify 45y7
3y5y
3y35y
3y25
9y25
Simplify 316x5y7
6x2y22xy
6x2y32xy
12x2y32xy
12x2y22xy
Simplify 316x5
2x32x2
3x232x
8x232x
2x232x2
Solve the equation. Check to determine if extraneous solutions exist.
7x+35=x+5
The equation has no real solutions (both are extraneous)
The equations has two solutions; x=−5 or x=2 .
The solution to the equation is x=−5 and x=2 is an extraneous solution.
The solution to the equation is x=2 , and x=−5 is an extraneous solution.
Solve the equation. Check to determine if extraneous solutions exist.
x+2=x−4
The equation has two solutions; 2 and 7
The solutions to the equation is 2, and 7 is an extraneous solution.
The solutions to the equation is 7, and 2 is an extraneous solution.
The equation has no real solutions (both are extraneous)
Multiply, then simplify.
5(25−45)
5
−35
35
−5
Multiply, then simplify
7(57−28)
14
0
21
28
The population of bears in a national forest is changing according to the function
N(t)=900(.95)t where t is the time in years and N(t) is the number of bears. Which statement explains how the bear population is changining?
The population is decreasing by 5% per year.
The population is increasing by 95% per year.
The population is decreasing by 95% per year.
The population is increasing by 5% per year.
The population of deer in a national forest is changing according tot he function, N(t)=875(1.05)t where t is the time in years and N(t) is the number of deer. Which statement explains how the deer population is changing?
The population is decreasing by 5% per year.
The population is increasing by 105% per year.
The population is decreasing by 105% per year.
The population is increasing by 5% per year.
Rewrite using the properties of logarithms.
log(x3w2)
log 2w−3logx
2logw−3logx
2logw−log3x
log2w−log3x
Evaluate x=2∑11(5x−2)
53
503
305
8
Expand k=3∑6(2k−1)
4, 6, 8, 10
4, 6, 8
5, 7, 9, 11
5, 7, 9
How many outfits are possible with 5 pairs of jeans, 8 t-shirts, and 2 pairs of shoes?
15
40
10
80
How many 5-digit (numerical) passwords are possible for the school email system? (repetition is allowed)
11,424,400
10,967,424
9000
100,000
A multiple choice test consists of 10 questions, each permitting a choice of 3 options. In how many ways may a student fill in the answers if they answer each question?
30
59,049
120
720
