What will be the output of the following C code?

int a[2][3] = {1, 2, 3, , 4, 5};

int i = 0, j = 0;

for (i = 0; i < 2; i++)

for (j = 0; j < 3; j++)

printf("%d", a[i][j]);

What will be the output of the following C code?

int a[2][3] = {0};

a[0][1] = 3;

int i = 0, j = 0;

for (i = 0; i < 2; i++)

for (j = 0; j < 3; j++)

printf("%d", a[i][j]);

Which of the following is not possible statically in C?

What are the applications of a multidimensional array?

What will be the output of the following C code?

int ary[2][3];

ary[][] = {{1, 2, 3}, {4, 5, 6}};

printf("%d\n", ary[1][0]);

What is the output of this program?

int a[10][20][30]={0};

printf("%ld", &a+1 - &a);

What is the output of the following program? (Assume input is 10)

int a;

printf("%d",scanf("%d",&a));

What will be the output of the following code?

unsigned int a = 5;

if(a > -1)

printf("5 is > -1\n");

What will be the output of the following code?

#include <stdio.h> int main() {

{ char a = 5; int b = 5; if(a == b) printf("char and int compared equal\n"); }

{ int a = 5; long int b = 5; if(a == b) printf("int and long compared equal\n"); }

{ float a = 5.0; double b = 5.0; if(a == b) printf("float and double compared equal\n"); }

{ float a = 5.2; double b = 5.2; if(a == b) printf("float and double again compared equal\n"); }

{ float a = 5.2; if(a == 5.2) printf("float compared equal with constant\n"); }

{ double a = 5.2; if(a == 5.2) printf("double compared equal with constant\n"); } return 0;}

The number of tokens in the following C statement. 

printf("i = %d, &i = %x", i, &i);

Consider the following declaration of a ‘two-dimensional array in C:

char a[100][100];

Assuming that the main memory is byte-addressable and that the array is stored starting from memory address 0, the address of a[40][50] is

Which combination of the integer variables x, y and z makes the variable a get the value 4 in the following expression?

a = (x > y)? ((x > z)? x : z): ((y > z)? y : z)

Consider the C program given below. What does it print?

#include <stdio.h>

int main ()

{

        int i, j;

        int a [8] = {1, 2, 3, 4, 5, 6, 7, 8};

        for(i = 0; i < 3; i++) {

             a[i] = a[i] + 1;

             i++;

        }

        i--;

        for (j = 7; j > 4; j--) {

              int i = j/2;

              a[i] = a[i] - 1;

        }

        printf ("%d, %d", i, a[i]);

}

Consider the following snippet of a C program. Assume that swap(&x, &y)  exchanges the contents of x and y.

int main ()  {

int array[] = {3, 5, 1, 4, 6, 2};

int done = 0;

int i;

while (done == 0)  {

done = 1;

for (i=0; i<=4; i++)  {

if (array[i] < array[i+1])  {

swap (&array[i], &array[i+1]);

done = 0; } }

for (i=5; i>=1; i--)  {

if (array[i] > array[i-1])   {

swap(&array[i], &array[i-1]);

done=0; } } }

printf("%d", array[3]); }