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WorksheetsRoot locus-GATE
Total questions: 23
Worksheet time: 16mins
Which of the following points is NOT on the root locus of a system with
the open–loop transfer function G(s)H(s)= s(s+1)(s+3)K [GATE 2002]
S=−j3
s=-1.5
s=-3
s=- ∞
The root locus of the system G(s)H(s)= S(S+2)(S+3)K has the
break-away point located at [GATE 2003]
(-0.5,0)
(-2.5478,0)
(-4,0)
(-0.784,0)
Given G(s)H(s)= S(S+1)(S+3)K the point of intersection of the
asymptotes of the root loci with the real axis is [GATE 2004]
-4
1.33
-1.33
4
A unity feedback system is given as G(s)= s(s+3)K(1−s) Indicate the correct
root locus diagram [GATE 2005]
A unity feedback control system has an open-loop transfer function G(s)= s(s2+7s+12)K The gain K for which s = −1+ j1 will lie on the root
locus of this system is [GATE 2007]
4
5.5
6.5
10
The root locus plot for a system is given below. The open loop transfer function corresponding to this plot is given by [ GATE 2011 ]
G(s)H(s)=(s+2)(s+3)K s(s+1)
G(s)H(s)=s(s+2)(s+3)2K (s+1)
G(s)H(s)= s(s−1)(s+2)(s+3)K
G(s)H(s)=s(s+2)(s+3)K(s+1)
In the root locus plot shown in the figure, the pole/zero marks and the arrows have been removed. Which one of the following transfer functions has this root locus? [GATE 2014]
(s+2)(s+4)(s+7)(s+1)
(s+1)(s+2)(s+7)(s+4)
(s+1)(s+2)(s+4)(s+7)
(s+4)(s+7)(s+1)(s+2)
The open-loop transfer function of a unity-feedback control system is G(s)= s2+5s+5K The value of K at the breakaway point of the feedback control
system's root-locus plot is [GATE 2016]
(a)
The forward-path transfer function and the feedback-path transfer function of a single loop negative feedback control system are given as G(s)= s2+2s+2K(s+2) and H(s)=1, respectively, If the variable parameter K is real positive, then the location of the breakaway point on the root locus diagram of the system is (a) .
[GATE-2016]
A unity feedback system has an open loop transfer function G(s)= s2K Its root locus plot will be [GATE 2002]
Figure shows the root locus plot (location of poles not given) of a third order system whose open loop transfer function is [GATE 2005]
s3K
s2(s+1)K
s(s2+1)K
s(s2−1)K
A closed-loop system has the characteristic function (s2−4)(s+1)+K(s−1)=0 Its root locus plot against K is [GATE 2006]
The characteristic equation of a closed-loop system is s(s+1)(s+3)+K(s+2)=0,K>0 Which of the following statements is true? [GATE 2010]
Its roots are always real
It cannot have a breakaway
point in the range -1 < Re[s] < 0
Two of its roots tend to infinity
along the asymptotes Re[s] = -1
It may have complex roots in the
right half plane
An open loop transfer function G(s) of system is s(s+1)(s+2)K For a unity feedback system, the breakaway point of the root loci on the real axis occurs at,[GATE 2015]
-0.42
-1.58
-0.42 and -1.58
none of the above.
The gain at the breakaway point of the root locus of a unity feedback
system with open loop transfer function G(s)= (s−1)(s−4)Ks is [GATE 2016]
1
2
5
9
The roots locus of a plant is given in the following figure. The rot locus crosses imaginary at ω = 4 2rad / s with gain K= 384. It is observed that the point
s = −1.5 + j 1.5 lies in the root locus. The gain K at s = −1.5 + j1.5 is computed as [GATE 2006]
11.3
21.2
41.25
61.2
Questions Q.2 & Q.3:
A transfer function with unity DC gain has three poles at -1, -2 and -3 and no finite zeros. A plant with this transfer function is connected with this transfer function is connected with a proportional controller of gain K in the forward path, in a unity
feedback configuration.The transfer function is [GATE 2007]
(S−1)(S−2)(S−3)S
(S+1)(S+2)(S+3)6
(S+1)(S+2)(S+3)S
(S−1)(S−2)(S−3)6
If the root locus plot of the closed loop system passes through the points ± j 11 , the maximum value of K for stability of the unity feedback closed loop system is [GATE 2007]
11
6
10
6 11
The open loop transfer function of a unity feedback system is G(s)= (s+1+j1)(s+1−j1)K(s+2) The root locus plot of the system has [GATE 2008]
Two breakaway points located at
s = -0.59 and s = -3.41
One breakaway point located at
s = -0.59
One breakaway point located at
s = -3.41
One breakaway point located at
s = -1.41
Consider the second- order system with the characteristic equation s(s+3)+K(s+5)=0 Based on the properties of the root loci, it can be shown that the complex portion of the root loci of the given system for 0<k<∞ is described by a circle, and the two breakaway points on the real axis are . [GATE 2011]
−5±25
−5±5
−5±10
−5±25
A loop transfer function is given by: G(s)H(s)= s2(s+10)K(s+2) The point of intersection of the asymptotes of G(s)H(s)on the real axis in the s-plane is at (a) .[GATE-2014]
The open loop transfer function of a system G(s)= s2+2s+2s2+6s+10 The angle
of arrival of its root loci are [GATE 2015]
±4π
±3π
±2π
±65π
The open loop transfer function of a unity gain negative feedback control system is given by G(s)= s(s+2)(s+8)s2+4s+8 The angle θ, at which the root locus approaches the zeros of the system satisfies [GATE 2012]
π−tan−1(41)
3π−tan−1(31)
2π−tan−1(41)
4π−tan−1(31)
