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Cellular Communication System

Total questions: 19

Worksheet time: 55mins

Name
Class
Date
1.

TDMA is used instead of TDM when:

a)

all the signals come from the same source

b)

the signals come from different sources

c)

TDM is used in RF communications

d)

they mean the same thing

2.

When calculating the maximum number of users, a limiting factor in FDM is:

a)

the type of media used

b)

the length of the channel

c)

the bandwidth of each signal

d)

all of the above

3.

A DS-1 signal contains:

a)

12 channels

b)

24 channels

c)

32 channels

d)

64 channels

4.

The bit-rate of a DS-1 signal over a T-1 line is:

a)

64 kbps

b)

256 kbps

c)

1.536 Mbps

d)

1.544 Mbps

5.

Besides data bits, a DS-1 frame contains a:

a)

timing bit

b)

T-bit

c)

signaling bit

d)

framing bit

6.

Spread-spectrum can be done by using:

a)

computer-controlled frequency reuse

b)

frequency-hopping

c)

direct-sequence method

d)

all of the above

7.

To calculate processing gain, divide the transmitted RF bandwidth by:

a)

the digital data bit rate

b)

bandwidth of original baseband

c)

the S/N ratio

d)

the chip size

8.

A receiver for frequency-hopping spread-spectrum would be

a)

a narrowband receiver

b)

a wideband receiver

c)

a direct-conversion receiver

d)

a CDMA receiver

9.

CDMA:

a)

cannot be used with frequency-hopping spread-spectrum

b)

cannot be used with direct-sequence spread-spectrum

c)

cannot be used on an RF channel

d)

allows many transmitters to use a band simultaneously

10.

Multiplexing allows many signals to (a)   a channel.

11.

In FDM, each signal uses part of the bandwidth (a)   of the time.

12.

In TDM, each signal uses all of the bandwidth (a)   of the time.

13.

Using CDMA on a radio channel, all signals can transmit (a)   of the time.

14.

A PN sequence is a (a)   -random noise sequence.

15.

The AM radio band is an example of (a)   -division multiplexing.

16.

A signal would have a bandwidth of 200 kHz and a signal – to – noise ratio of 20 dB if transmitted without spreading. It is spread using a chipping rate of 50:1. Calculate its bandwidth and a signal – to – noise ratio after spreading.

(a)  

17.

The bandwidth of a communication channel is 12.5 kHz. The S/N ratio is 25 dB. Calculate (a) the maximum theoretical data rate in bits per second, (b) the maximum theoretical channel capacity, and (c) the number of coding levels N needed to achieve the maximum speed. [For part (c), use the y x key on a scientii c calculator.]

(a)  

18.

A Frequency – hopping spread – spectrum system hops to each of 100 frequencies every 10 seconds. How long does it spend on each frequency?

(a)  

19.

Determine the carrier frequency of channel five in frequency division multiplexing.

(a)