$$y=\frac{1}{x^2}$$  is a function of the

y is undefined when x is positive in the function $$y=\sqrt[]{x}$$  

In the hyperbola graph the vertical asymptotes is $$x=k$$  

$$y=\frac{a}{x-h}+k$$  

This graph is a

This function is a reflection of the hyperbola is $$-y=\frac{a}{x}$$  

When the horizontal asymptotes is ZERO we don't have a

The point (h,k) is the

In the following function $$y=\frac{1}{\left(2x+4\right)^2}-3$$  the graph $$y=\frac{1}{x^2}$$  moves 4 units to the right and 3 units down.