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Worksheetsmidterm calculus honors
Total questions: 58
Worksheet time: 58mins
5(cos4x)sinx
-5(cos4x)sinx
Find the derivative f(x) = tan(x)cos(x)
f'(x) = sec2 (x)cos(x) - tan(x)sin(x)
f'(x) = sec2xcos(x) + tan(x)sin(x)
f'(x) = sec2(x)sin(x)
f'(x) = sec2(x)cos(x )- tan(x)cos(x)
Find the derivative of y = cos2(x)
f'(x) = −2sin(x)
f'(x) = −2sin2(x)
f'(x) = 2cos(x)
f'(x) = −2 cos(x) sin(x)
Find the derivative f(x) = x2 +1
f'(x) = 2x2 +11
f'(x) = 4x2 +1x
f'(x) = x2 +1x
f'(x) = x2 +14x
What is f'(x) if f(x) = cos(sin(x))?
f'(x) = -sin(sin(x))cos(x)
f'(x) = -sin(sin(x))
f'(x) = cos(sin(x))cos(x)
f'(x) = -sin(x)cos(x)
What is f'(x) if f(x) = cos(x)sin(x)?
f′(x)=sin2(x)+cos2(x)
f′(x)=−sin2(x)+cos2(x)
f′(x)=sin2(x) − cos2(x)
f′(x)=−sin2(x)cos2(x)
What is f'(x) if f(x)=cos2(x) ?
−xcos((x))sin(x)
xcos((x))sin(x)
xcos((x))
−cos((x))sin(x)
What is f'(x) if f(x)=cos(x) ?
cos(x)−sin(x)
2cos(x)cos(x)
2cos(x)−sin(x)
2sin(x)−x
f(x) = x4 sin x Find the derivative.
x4 cosx - 4x3sinx
x4 cosx + 4x3sinx
4x3cosx
-4x3cosx
Find the fully simplified Derivative of y = 4x2 + 3x + 6x-2
y' = 8x + 3 -12x-3
y' = 8x + 3 +12/x3
y' = 8x + 3 -12/x3
y' = 8x + 3 + 12/x
At which point(s) will the slopes of the tangent line be zero?
at C only
at points A, C and E only
at point B and D only
at points A and E only
Find the slope of f(x) = -3x2 - 6x at x = 1.
m = 0
f'(x) = -6x - 6
f'(x) = 6x
m = -12
Differentiate f(x) = (2/x5) - 5.
x5 - 3
-10x6
x5 - 5
-10x-6
Find the slope of y = 3x2 - 5 at x = 2
10
11
12
13
Find the derivative.
y = x2 / (3x - 1)
y' = 9x2 - 12
y' = (3x - 1) / (3x - 1)2
y' = (3x2 - 2x) / (3x - 1)2
y' = (6x + 1)2 / 3
Differentiate y = x212
y' = 24x-1
y' = -24x-3
y' = -24x-1
y' = 6x-3
Differentiate y = x2x2+x−3
y = 2x + 1 - 3x-1
y' = 4x + 1 - 1x-2
y' = 2 + 3x-2
y' = 4x + 1 - 3x-2
find y' for y=(e5x)+1
5e5x+1
e5x
5e5x
1
find y' for y= (2x+1)10
10(2x+1)9
20(2x-1)9
20(2x+1)10
20(2x+1)9
find y' for y= sin(2x2)
4sin(2x2)
4xcos(2x2)
2xcos(2x2)
xcos(4x2)
f(x) = x7 (5 + 8x)3
dxd[(2x+1)(5x−4)]
10x−3
20x−4
10x−4
20x−3
dxd[(x)(x−1)]
23x21+21x2−1
23x21−21x2−1
21x21−23x2−1
21x21+23x2−1
dxd[x2(x+1)(2x−3)]
8x3−3x2−6x
8x3+3x2−6x
8x3−3x2+6x
8x3+3x2+6x
f(t) = (t2 + 2t)5
dxdsin(x) =
cos(x)
x sin(x)
x1
sin2 (x)
dxdcos(x) =
-sin(x)
x sin(x)
x1
sin2 (x)
dxdarccos(x) =
1−x21
−1−x21
x1
−1+x21
dxdarccot(x) =
1−x21
−1−x21
x1
−1+x21
dxdarctan(x) =
1−x21
−1−x21
1+x21
−1+x21
dxdarcsin(x) =
1−x21
−1−x21
1+x21
−1+x21
dxdln(x) =
1−x21
−1−x21
x1
−1+x21
dxdln(1−x) =
1−x21
1−x−1
x1
1+x1
dxd(x − ln(1+x)) =
1−x21
1−x−x
x1
1+xx
dxdx2+1 =
1+x21
1−x−x
x1
x2+1x
