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WorksheetsPAS Physics Grade 9
Total questions: 10
Worksheet time: 12mins
A glass rod becomes positively charged when it is rubbed with silk. The glass rod becomes charged because it.....
gains protons
gains electrons
loses electrons
gains protons and loses electrons
If a rubber rod repels a pith ball, what can be deduced about the charges on the rubber rod and the pith ball?
Only the rod is charged
Only the pith ball is charged
Either the rod or the pith ball is charged, but not both.
Both the rod and pith ball carry like charges.
How does an electrical conductor differ from an electrical insulator?
Charged particles are free to move about both conductors and insulators.
Charged particles cannot move at all in the insulators.
Charged particles are free to move about conductors.
Insulators have a high ability to conduct electricity.
The SI unit of electric charge is the.....
coulomb
ampere
watt
volt
The figure below shows a negatively-charged rod held near, but not touching, a metal rod. Which of the following statements best describes the movement of the charges?
The electrons from the charged rod jump across the gap and enter the metal rod.
The electrons in the metal rod move from X to Y.
The positive charges in the metal rod move from Y to X.
The positive charges in the charged rod move from X to Y.
Which of the following set-ups cannot be used to determine the resistance of resistor R?
A
B
C
D
Choose the correct statements below.
The SI unit of charge is volt.
Conventional current is in the direction of electron flow.
A thicker wire has a lower resistance than a thinner wire.
A shorter wire has a bigger resistance than a longer wire.
Electric charge that has electric field lines directed away from the charge.
Neutral atom
Positive charge
Electron
Negative charge
Materials that are charged through induction.
Insulators
Conductors
Rubber
None
The ammeter reading in the circuit below is 1 A. Which of the following could be the voltmeter reading and resistance of the resistor?
V = 12 V
R = 6 Ω
V = 1 V
R = 2 Ω
V = 4 V
R = 0.25 Ω
V = 10 V
R = 10 Ω
