WorksheetsSolution-HW
Total questions: 25
Worksheet time: 2hrs 1mins
Which of the following is the Dilution Formula?
V1M1 = V2M2
M = m/V
V = mT
PV = nRT
What volume, in milliliters, of 10.0 M NaOH is needed to prepare 300.0 mL of 2.00 M NaOH by dilution?
0.067 mL
60.0 mL
100 mL
125 mL
If I have 340.0 mL of a 0.500 M NaBr solution, what will the concentration be if I add 560.0 mL more water to it? (Remember to use the total new volume)
.188 M
3.78 M
.389 M
1.76 M
Concentration is
the amount of solute in the solvent
the amount of solvent in the solute
density
particle size
In order to dilute a solution, you need to
add more of the solid
add more water
find the mass
find the volume
Calculate the mass percent of solution, if there is 100 g of sugar and 400 g of water
30
25
20
15
How many moles would be in 85mL of 0.75M KOH?
113.3 mol
1.13 mol
.113mol
0.06375mol
63.75mol
How many grams of water could form in this reaction 85mL of 0.75M KOH?
1.15g
282g
31.9g
113.g
Molarity is:
moles per liter of solution
written with a unit of M
calculated by dividing the moles of a substance by the liters of solvent
all of the above
To convert liters of a solution to moles, one should:
divide by the molarity
multiply by the molarity
multiply by the molar mass
divide by the molar mass then multiply by the speed of light squared
To convert mL to L, one should:
divide by 1000
multiply by 1000
divide by 100
multiply by 100
An unknown substance dissolves readily in water but not in benzene (a nonpolar solvent). Molecules of what type are present in the substance?
neither polar nor nonpolar
polar
nonpolar
either polar or nonpolar
none of these
The interaction between solute particles and water molecules, which tends to cause a salt to fall apart in water, is called
hydration
polarization
dispersion
coagulation
conductivity
Which of the following is a strong acid?
HF
KOH
HClO4
HClO
HBrO
Which of the following is not a strong base?
Ca(OH)2
KOH
NH3
LiOH
Sr(OH)2
A 14.2-g sample of HF is dissolved in water to give 2.0 × 102 mL of solution. The concentration of the solution is:
0.71 M
0.14 M
0.07 M
3.5 M
7.1 M
1.00 mL of a 3.55 × 10–4 M solution of oleic acid is diluted with 9.00 mL of petroleum ether, forming solution A. Then 2.00 mL of solution A is diluted with 8.00 mL of petroleum ether, forming solution B. What is the concentration of solution B?
3.55 × 10–6 M
9.86 × 10–6 M
7.10 × 10–5 M
7.89 × 10–5 M
7.10 × 10–6 M
1.00 mL of a 3.05 × 10–4 M solution of oleic acid is diluted with 9.00 mL of petroleum ether, forming solution A. Then 2.00 mL of solution A is diluted with 8.00 mL of petroleum ether, forming solution B. How many grams of oleic acid are 5.00 mL of solution B? (Molar mass for oleic acid = 282 g/mol)
4.30 × 10–6 g
1.19 × 10–5 g
1.72 × 10–2 g
8.60 × 10–6 g
4.30 × 10–4 g
How many grams of NaCl are contained in 350. mL of a 0.115 M solution of sodium chloride?
6.7 g
2.35 g
4.70 g
40.3 g
none of these
A 61.08-g sample of Ba(OH)2 is dissolved in enough water to make 1.800 liters of solution. How many mL of this solution must be diluted with water in order to make 1.000 L of 0.100 M Ba(OH)2?
505 mL
198 mL
19.8 mL
3.57 mL
280 mL
An analytical procedure requires a solution of chloride ions. How many grams of CaCl2 must be dissolved to make 1.95 L of 0.0439 M Cl–?
9.74 g
0.400 g
4.75 g
2.44 g
19.0 g
