WorksheetsMO DIAGRAMS
Total questions: 17
Worksheet time: 4hrs 15mins
BMO is formed due to
Constructive Interference
Destructive Interference
Different sign of wave function
Both 2 & 3
Molecule which have one or more than one unpaired electrons in their molecular electronic configuration are ____________
A. Diamagnetic
B. Paramagnetic
Para magnetic or diamagnetic?
A. Paramagnetic
B.. Diamagnetic
Can you predict the molecule? Justify your answer
A. N2
B. F2
C. O2
Which of the following statements is true?
Electrons are never found in an antibonding MO.
All antibonding MOs are higher in energy than the atomic orbitals of which they are composed.
Antibonding MOs have electron density mainly outside the space between the two nuclei.
None of the statements is true
The electron configuration of a particular diatomic species is (σ2s)2(σ*2s)2(σ2p)2(π2p)2(π*2p)4. What is the bond order for this species?
1.5
1
0.5
0
2
following mo diagram represents which molecule?
N2
O2
F2
none of these
what are the bond orders in O2, O2+,O2-
2, 3,4
2,1.5,2.5
2,2.5,1.5
2.5,2,1.5
Sigma bond is formed when overlapping takes place along (if z-axis is inter nuclear axis)
x-axis
y-axis
z-axis
All axis
The hybridization of the central atom in ClF2+ is:
sp
sp2
sp3
dsp3
d2sp3
A π (pi) bond is the result of the
overlap of two s orbitals
overlap of an s orbital and a p orbital
overlap of two p orbitals along their axes
sidewise overlap of two parallel p orbitals
sidewise overlap of two s orbitals
Which of the following molecules contains the shortest C–C bond?
C2H2
C2H4
C2H6
C2Cl4
C2H4 and C2Cl4
When comparing Be2 and H2:
I.Be2 is more stable because it contains both bonding and antibonding valence electrons.
II.H2 has a higher bond order than Be2.
III.H2 is more stable because it only contains σ1s electrons.
IV.H2 is more stable because it is diamagnetic, whereas Be2 is paramagnetic.
I, II
III only
II, III
II, IV
III, IV
If a molecule demonstrates paramagnetism, then :
I.The substance can have both paired and unpaired electrons.
II.The bond order is not a whole number.
III.It can be determined by drawing a Lewis structure. IV.It must be an ion.
I, II
II,III
I, II, IV
I only
III only
Rank the energy of a bonding MO in comparison to its atomic orbital.
higher
lower
equal
Why is bond order important when examining MO?
The stability of the covalent bond is related to the bond order.
You must fill the orbitals in correct bond order.
