WorksheetsUnit 3 Fluids and Density
Total questions: 27
Worksheet time: 35mins
(a) decreases at 1"Hg per 1,000 ft increase in altitude.
Viscosity is a fluid's resistance to (a)
What are the standard temperature and pressure values for sea level?
0 Degrees C and 1013.2 millibars
15 degrees C and 29.92" Hg
59 degrees C and 1013.2 millibars
59 degrees C and 29.92" Hg
Knowing the pressure altitude is important to aircraft performance because it can be used as a tool to arrive at (a)
Pressure altitude corrects for the difference between (a) and standard pressure.
Which factor would tend to increase the density altitude at a given airport?
decrease in ambient temperature
increase in barometric pressure
decrease in relative humidity
increase in ambient temperature
What is the Pressure Altitude if given
Local Barometric Pressure: 28.92" Hg
Local Elevation: 3500'
PA = (29.92 − Lp) x 1,000 + Le
You may work it out on paper, take a pic, and upload the image if you wish.
Pressure altitude is calculated from (29.92 − 28.92) x 1,000 +3,500 . What information do these numbers give?
the barometric pressure is 29.92" Hg and the elevation is 1,000 ft.
the barometric pressure is 28.92" Hg and the elevation is 1,000 ft.
the barometric pressure is 29.92" Hg and the elevation is 3,500 ft.
the barometric pressure is 28.92" Hg and the elevation is 3,500 ft.
Which of the following are units of measure for atmospheric pressure? Select all that apply. (3.A.2)
feet per second (ft/s)
square centimeters cm2
millibars (mb)
pounds per square inch (psi)
inches of mercury (Hg)
Which combination of atmospheric conditions will reduce takeoff and climb performance? (a) (b) (c)
Which statement is true about an object moving through a fluid? (3.A.1)
viscosity changes according to the size of the object
the object moves faster if fluid is more viscous
fluid friction increases as the object's velocity increases
less viscosity means more fluid friction
Which formula is used for calculating density altitude? (3.B.1)
mass ÷ volume
PA +[120(OAT − ISA)]
(29.92 − LBP)1000 + LE
15 − (10002 ×PA)
Atmospheric pressure is _______ to air density. (3.A.2)
equal to
directly proportional
inversely proportional
unrelated
The “standard day” serves as a universal baseline for measuring _______. (3.B.1)
atmospheric pressure
barometric pressure
density altitude
ground roll
The Magnus Effect occurs because a spinning object drags the air around it. The air being dragged by the object interacts with the surrounding air to create regions of _______. (3.A.1)
high friction
warm and cool air
high and low pressure
high and low viscosity
An airport has an elevation of 1,700 feet. A density altitude of 2,200 feet means that an aircraft will perform as if it is ________ above sea level. (3.B.1)
3,900 ft
500 ft
1,700 ft
2,200 ft
The Coanda Effect is the tendency for a jet of fluid to _______. (3.A.1)
force objects to move faster
lift objects upward
attach to a convex or bulging surface
become more dense
True or False. The primary reason for computing density altitude is to determine airplane performance. (3.B.1.)
True
False
Objects with the same _______ but different masses have different densities. (3.A.2)
temperature
volume
area
viscosity
In what way is the Coanda Effect similar to the Magnus Effect? (3.A.1)
They both create air movement that influence the direction of an airborne object
They both impact the direction of an object that has a convex or bulging surface
They both involve spinning objects that create regions of low pressure.
They both describe the movement of air molecules creating regions of high and low pressure.
Explain how the chart would be used to determine the distance needed for an aircraft to take off. Explain why this is important. (3.B.1)
Explain how the Magnus Effect works and give a real-world example. (3.A.1)
Explain what limits an aircraft’s ability to perform and fly at extremely high altitudes. (3.A.2)
Explain why an aircraft will have diminished performance on a hot day at a high-altitude airport. (3.B.1)
What is the equation DA = PA + [120 (OAT ‒ ISA)] used for? Explain what DA, PA, OAT, and ISA represent in the equation. (3.B.1)
DA = PA+[120(OAT‒ISA)]
PA = (29.92 − LBP)×1000 + LE
ISA = 15 − (10002×PA)
Outside Air Temp: 8°
Barometric Pressure: 30.53
Local Elevation: 12,408 ft
DA = PA+[120(OAT‒ISA)]
PA = (29.92 − LBP)×1000 + LE
ISA = 15 − (10002×PA)
Outside Air Temp: 37°
Barometric Pressure: 29.83
Local Elevation: 27 ft
