WorksheetsSolving Systems Algebraically
Total questions: 155
Worksheet time: 12hrs 51mins
Solve the following systems of equations using substitution:
x = 6
y = 2x - 3
(6, 6)
(6, 9)
(9, 6)
(9, 9)
How many solutions does the graph have?
One solution
No solution
Infinite solutions
How many solutions does the graph have?
One solution
No solution
Infinite solutions
How many solutions does the graph have?
One solution
No solution
Infinite solutions
Solve the following systems of equations using substitution:
5x - 2y = 3
y = 2x
(6, 3)
(1, 2)
(3, 6)
(2, 1)
Solve the following systems of equations using substitution:
y = 3 - x
3y + x = 5
No solution
(1, 2)
(3, 0)
(2, 1)
"solution to a system of equations"
mean?
Solve the system of equations.
(-34, -17)
(8, 4)
(10, 20)
No solution
Infinite solutions
Solve the system of equations.
(-6, 1)
(-12, -12)
(1, -6)
No solution
Infinite solutions
Give the solution to the system
y=8x+1
y=6x+3
2x + 3y = 4
y= 5x - 27
Which answer has a correct first step for this system:
3x + 3y = 3
y = 3x + 5
The variable is already isolated, so we've already solved the system.
The variable is already isolated for y, so we substitute it in the first equation and solve for x
3x + 3(3x + 5) = 3
Free sha vaca doo
The variable is already isolated for y, so we substitute it in the second equation and solve for x
y = 3(3x + 3y) = 3
Solve this system using substitution
y = 3x - 5
2x + 4y = -6
(1, -2)
(2, -2)
(1, 2)
Why have you done this?
Solve with substitution
x = -3y - 8
x - 2y = -3
(5, -1)
(-5, 1)
(-5,-1)
(1,-5)
Solve the following system:
−2x−3y=−7
(2, 1)
(1, 3)
(2, 5)
(3, 2)
Solve the following system:
y=x−1
(−2,−3)
(4, 5)
(5, 3)
(3, 4)
Solve the following system:
5x−4y=−3
(1, 2)
(1, 5)
(2, 5)
(5, 1)
Solve the following system:
−3x−3y=3
y=−5x−17
(−4,3)
(4, 3)
(3, 4)
(3, −4)
Solve the following system:
4x−3y=18
(3, −2)
(3, 2)
(−2,3)
(2, 3)
Solve the following system:
−3x−2y=−12
(2, 3)
(3, 2)
(−2, −3)
(−2, 3)
Solve the following system:
−5x−y=21
(−3, −6)
(3, 6)
(3, −6)
(−3, 6)
Solve the following system:
x=2y+11
(3, −4)
(3, 4)
(−3, −4)
(−3, 4)
Solve the following system:
−3x+6y=−12
(0, −2)
(0, 2)
(−2, 0)
(2, 0)
Solve the following system:
3x−8y=24
(0, −3)
(0, 3)
(−3, 0)
(3, 0)
y = 8
(1, -4)
(1, 4)
(-4, -7)
(-7, -4)
y = 2x + 1
y = 4x - 1
y = 2x + 1
y = 4x - 1
y = 3x - 8
y = 4 - x
y = 2x + 1
y = 4x - 1
y = 2x - 11
5x + 4y= −14
y = −7x − 15
y = 2x -11
-3y = -6x -15
x = -4y + 2
4x + 2y = 4
-2x + y = 5
y = -6x - 13
y = 2x - 11
y = 2x + 1
y = 4x - 1
The school that Laura goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4 senior citizen tickets, 2 adult tickets and 5 child tickets for a total of $55. The school took in $67 on the second day by selling 7 senior citizen tickets, 2 adult tickets and 5 child tickets. On the third day the show earned $46 when they sold 2 senior citizen tickets, 4 adult tickets and 2 child tickets. What is the price each of one senior citizen ticket, one adult ticket and one child ticket?
Adult: $12
Child: $8
Senior: $8
Adult: $6
Child: $4
Senior: $5
Adult: $7
Child: $5
Senior: $4
None of the above.
x + y + z = 4
x = -2y
z = -3y
3) Solve the system of linear equations.
(3, 1, -5)
(-3, 1, -1)
no solution
infinitely many solutions
Solve the system of equations:
2x−3y=3z−7
4z−2x+3y=12
4y+2z−3x=0
(2, 4, 5)
(-2,-4, 5)
(-2, 4, -4)
None of these
Andrea sells photographs at art fairs. She prices the photos according to size: small photos cost $10, medium photos cost $15, and large photos cost $40. She usually sells as many small photos as medium and large photos combined. She also sells twice as many medium photos as large. A booth at the art fair costs $300.
If her sales go as usual, she will have to sell (a) small photos to pay for the booth.
Sam has a total of 17 bikes, unicycles, and skateboards. A bike has 2 wheels, a skateboard has 4 wheels, a unicycle has one wheel and she has a total of 42 wheels. There are just as many bikes as unicycles and skateboards together. Which system models this scenario?
B + U + S = 42
2B + U + 4S = 17
B = U + S
B + U + S = 17
2B + U + 4S = 42
B = U + S
B + U + S = 17
2B + U + 4S = 42
B = U*S
Uncle Freddy rented a total of 12 movies and games. A movie rents for $3 and a game rents for $4.50, for a total of $42. There are 3 times as many movies than games. Which system models this scenario?
3M + 4.50G = 42
M + G = 12
M = 3G
3M + 4.50G = 12
M + G = 42
3M = G
M + G = 12
4.50M + 3G = 42
3M = G
Solve:
(5,−1,3)
(−1,5,3)
(3,5,−1)
(3,1,−5)
Solve:
(5,4,−2)
(5,3,4)
(4,3,5)
(−1,2,4)
Solve:
(1,−3,5)
(1,−4,3)
(−4,1,3)
(−4,3,1)
Solve:
(0,−3,2)
(0,2,−3)
(0,3,−2)
(3,0,−2)
Solve:
(2,−1,1)
(1,4,1)
(1,−1,2)
(3,−4,0)
Solve using Matrices.
Write the system of equations to solve this problem.
8x+3y=57
5x+4y=39
3x+8y=57
5x+4y=39
What matrix can be used to solve the previous problem?
Use Matrices to solve the previous system.
Solve using a system of equations and matrices.
rose = 4
shrub = 59
rose = 3
shrub = 10
Solve.
(-2, 6, -2)
(76, 2, 722)
x-y=11
2x+y=19
-4x-2y=-12
4x+8y=-24
4x + 8y = 20
−4x + 2y = −30
x − y = 11
2x + y = 19
4x+9y=28
-4x-y=-28
-9x-4y=-20
5x+4y=4
7x+y=-9
-3x-y=5
4x+4y=4
3x+4y=10
7x-9y=29
7x+2y=-15
Solve by elimination:
7x+y=-9
-3x-y=5
No solution
(-1,8)
(-2,-3)
(-1,-2)
4x+9y=28
-4x-y=-28
3x+7y=23
-3x-7y=-17
-9x-4y=-20
5x+4y=4
7x+y=-9
-3x-y=5
4x+4y=4
3x+4y=10
-x+2y=17
2x+2y=-10
7x-9y=29
7x+2y=-15
9x-4y=7
x-4y=-17
-12x-10y= 0
6x+5y= -1
4x-6y= -6
-2x-12y= -12
2x+9y= -7
6x-3y= 9
-6x+y= -2
-3x-6y= 12
2x + 3y = 12
5x - y = 13
3x + 2y = 16
7x + y = 19
8x + 4y = 12
y = -2x + 3
y = 8x + 12
-5x +4y = 21
2x + 10y = -20
-x + 4y = 28
You can solve systems using these methods:
graphing, substitution, and elimination
rearranging, thinking, and guessing
only by graphing
Solve this system by substitution.
(1, -4)
(1, 4)
(-4, -7)
(-7, -4)
What variable do you eliminate?
4x + 8y = 20
−4x + 2y = −30
X because they have opposite signs
Y because they have opposite signs
What variable do you eliminate, and what do you multiply the equation(s) by?
5x + y = 9
10x − 7y = −18
You eliminate x, and multiply the top equation by 11
You eliminate y, and multiply the top equation by 7
3x - y = 7
2x + y = 3
−4x − 4y = 0
4x + 4y = 0
-4x - 6y = 6
4x + 6y = -4
Solve the following systems of equations using substitution:
x = 6
y = 2x - 3
(6, 6)
(6, 9)
(9, 6)
(9, 9)
Solve the following system:
4x−3y=18
(3, −2)
(3, 2)
(−2,3)
(2, 3)
Solve the following system using any method.
y = 2/3x - 2
y = -x + 3
(0,3)
(0,-3)
(3,0)
(-3,0)
Solve the following system using any method.
3x + 2y = 16
7x + y = 19
(-2,5)
(-2,-5)
(2,-5)
(2,5)
Solve the following system using any method.
y = 2x + 1
y = 4x - 1
(1,3)
(-1,-3)
(-1,3)
(3,1)
2x-y=4
y=-2x+8.
What is the value of x in the solution for this system?
x=8
x=3
x=11
x=5
x-2y=1
x+4y=7
y=8x+1
y=6x+3
y=7.30+.90x
x + y = 7.30
y = 7.30 + .65x
y + .65x = 7.30
y = 8.40 + x
y = 8.40x + 58
y = 8.40x
y = 8.40x - 58
Solve the following system using any method.
y=-x+4
y=2x+4
(0,4)
(2,4)
(-1,3)
(4,0)
y = 4x+1
3x + 2y = 13
y = 2x + 1
y = 4x - 1
3x + 2y = 16
7x + y = 19
Which of the following represents the first step in solving:
y = x2 + 3x - 5
y = x + 3
x2 - 3x + 5 = x - 3
x2 + 3x - 5 = x + 3
x2 + 3x - 5 + x + 3 = 0
x2 + 3x - 5 = 0
y = x2 + 3x - 5
y = x + 3
Add
11 8
-4 2
3 2
-6 -6
-3 2
-4 -6
10 8
-6 2
7 -1
1 -4
6 -1
30 -5 0
30 -5 0
11 4 5
-30 5 0
BA=
Undefined
Which of these matrices are in row echelon form?
(a) only
(b) only
(a) and (d)
(a) , (b), and (d)
The augmented matrix shown in row-echelon form indicates a system with
one solution
no solution
infinitely many solutions
The augmented matrix shown in row-echelon form indicates a system with
one solution
no solution
infinitely many solutions
What is the determinant of this matrix?
-2
2
10
24
What is the determinant of this matrix?
0
24
-24
-12
3x + 2y = 8
-3x + 6y = 12
6x+4y=-10
4x+9y=28
-4x-y=-28
4x+4y=4
3x+4y=10
-4x-9y=-23
Solve the system of equations.
(-6, 1)
(-12, -12)
(1, -6)
No solution
Infinite solutions
2x + 3y = 4
y= 5x - 27
Which answer has a correct first step for this system:
3x + 3y = 3
y = 3x + 5
The variable is already isolated, so we've already solved the system.
The variable is already isolated for y, so we substitute it in the first equation and solve for x
3x + 3(3x + 5) = 3
Free sha vaca doo
The variable is already isolated for y, so we substitute it in the second equation and solve for x
y = 3(3x + 3y) = 3
Solve using substitution.
(1,3)
(3,-1)
(7,3)
Solve using elimination.
(4,5)
(3,4)
(5,4)
Solve using the most efficient method.
(2,1)
(1,-2)
(2,-1)
Solve using your preferred method.
(3,7)
(5,7)
(6,6)
Solve using the most efficient method.
(3,4)
(4,12)
(14,17)
Solve using your preferred method
(14,10)
(2,10)
(4,14)
Solve using the most efficient method.
(9,11)
(-2,3)
(3,-2)
Solve using the most efficient method.
(7,-9)
(9,7)
(1,7)
Solve using the most efficient method.
(-6,5)
(5,-6)
(4,-6)
Solve using your preferred method.
(6,1)
(-1,9)
(-7,13)
Solve using your preferred method.
(2,-4)
(-2,-4)
(-2,4)
Solve using the most efficient method.
(4,-6)
(2,10)
(4,2)
