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Total questions: 14
Worksheet time: 9mins
In the equation (x – 5)2 + (y + 2)2 = 16, what is the center and radius of a circle?
A.
Center (5, -2)
Radius = 4
B.
Center (-5, 2)
Radius = 8
C.
Center (5, 2)
Radius = 16
D.
Center (2, -5)
Radius = 4
4. In the equation (x+2)2+(y+3)2=49, the radius of the circle is __.
7
14
49
98
Which of the following is the value of D in the equation x2 + y2 – 2x – 34y + 226 = 0?
-1
226
-3
-2
Convert the equation (x+16)2+(y−1)2=4
into general form.
x2+y2+32x−2y+241
x2+y2+32x−2y+241=0
x2−y2+32x−2y+241=0
x2−y2−32x−2y−241=0
Which is true about (x – h)2 + (y – k)2 = r2?
i. It is an equation of a circle in general form.
ii. It is an equation of a circle in standard form.
i
ii
both
none of the above
Ana was asked to formulate the general equation of the circle given that the radius is 5cm and the coordinate of the center is (-1,2). What will be her answer to this problem?
x2+y2+2x−4y−20=0
x2+y2−2x−4y−20=0
x2+y2−2x+4y−20=0
x2+y2+2x+4y−20=0
(x-4)2+(y+2)2=25
Which of the following is the equation of a circle whose center is at (0, -10) and radius is √2
units?
(x – 10)2 + y2 = √2
x2 + y2 = 4
x2 + (y + 10)2 = 2
x2 – y2 = 4
Transform (x−2)2+(y−4)2=36 into the general equation of a circle
x2+y2−4x−8y+16=0
x2+y2+4x−16y−16=0
x2+y2−4x−16y+16=0
x2+y2−4x−8y−16=0
What is the general form of the equation (x−2)2+(y+5)2=9 ?
x2+y2+6x−8y+12=0
x2+y2−4x+10y+20=0
x2+y2+7x−8y+15=0
x2+y2+3x−2y−4=0
Which is true about (x – h)2 + (y – k)2 = r2?
i. It is an equation of a circle in general form.
ii. It is an equation of a circle in standard form.
i
ii
both
none of the above
Transform (x−2)2+(y−4)2=36 into the general equation of a circle
x2+y2−4x−8y+16=0
x2+y2+4x−16y−16=0
x2+y2−4x−16y+16=0
x2+y2−4x−8y−16=0
Which of the following is the equation of a circle whose center is at (0, 0) and radius is 27 units?
x2 + y2 = 729
2x2 + 2y2 = 27
x2 – y2 = 729
2x2 – 2y2 = 27
(x - a)2 + (y - b)2 = r2 ?
Radius = r2 units
Radius = r units
Radius = r units
Radius = r2 units
