WorksheetsTrigonometric Identities Challenge
Total questions: 64
Worksheet time: 3hrs 21mins
Simplify the expression
sin²θ
cosθ
tanθ
1- sin²θ
Simplify the expression
-1
sin θ
csc θ
1
Simplify the expression
csc²θ
sec²θ
cscθ
1
Simplify the expression
sinθ
cot²θ
tan²θ
cos²θ
Choose all valid strategies for proving an identity
Choose the most complicated looking side to work with
Convert everything in terms of sine and cosine
multiply everything by π
Combine or Separate Fractions
Multiplying by the Conjugate
Which of the following is NOT an Identity under Reciprocal Identity?
cscθ = sinθ1
secθ = cosθ1
tanθ = cosθsinθ
1 = cotθtanθ
cos2θ
sin2θ
tan2θ
1
Simplify sec2−1sin2x
sin2x
cos2x
0
1
Which of the following should be written in Item number 1.
1
sinxsinx
cosxcosx
sinxcosx
Which of the following should be written in Item number 2.
cos x - 1
1- cos x
sinx - cos x
1 - sin x
Which of the following should be written in Item number 3.
1 - cosx
cosxcosx
1 − cos2x
1
Which of the following should be written in Item number 4.
1−cosx
1 + cosx
1 − cos2x
1 + cos2x
Which of the following should be written in Item number 1.
1
sinx + cosx
sin2x + cos2x
sin2x − cos2x
Which of the following should be written in Item number 2.
cos2x
cosx1
csc2x
cos2x1
Which of the following should be written in Item number 3.
cscx
csc2x
cos2x1
sin2x
tanθ =
cosθsinθ
sinθcosθ
cosθ1
cotθ
sin2θ + cos2θ = 1
Solve for cos2θ .
cot2θ+1
sec2θ−1
tanθ+1
1−sin2θ
tanθcosθ can be written in a single trigonometric identity as:
cosθ
sinθ
secθ
cotθ
cos2θ1−cos2θ can be written in a single trigonometric identity as:
cos2θ
sin2θ
sec2θ
tan2θ
cosθ cscθ can be written in a single trigonometric identity as:
cosθ
sinθ
secθ
cotθ
Simplify
cot2θ(1+tan2θ)
csc²θ
sec²θ
cscθ
1
Simplify
sinθ(cscθ−sinθ)
secθ
cos2θ
sin2θ
cos2θsin2θ
Simplify
tanxcscxcosx
cosx1
1
cotx
-1
Simplify (secθ−1)(secθ+1)
2secθ
cot2θ
tan2θ
sec2θ+1
Simplify
csc x(cosx+sinx)
csc x
tan x + 1
cot x
cot x + 1
Simplify tanx(cotx + cscx)
1 + secx
1 + cscx
secx−1
tan2x
tan2θ1−cos2θ can be simplified as
cot2θ
tan2θ
sin2θ
cos2θ
What happens when you multiply two reciprocal functions?
You get a pythagorean identity
It equals 1
You get a quotient identity
It equals 0
Which of the following would be a step to prove the following identity? cscx−secx=sinxcosxcosx−sinx
sinx1−cosx1
sinxcosx−sinx
cosxcosx−sinx
sinxcosx1
One step in proving the identity below would be:
sec2θsec2θ−1
sec2θsec2θ−sec2θ1
sec2θtan2θ
Both A and B
Neither A nor B
tanθtanθ+cotθ can be simplified as:
csc2θ
cot2θ
sin2θ
cos2θ
sinθcotθ secθ
0
1
sinθ
cosθ
Simplify (secθ−1)(secθ+1)
2secθ
cot²θ
tan²θ
sec²θ + 1
Simplify
csc x(cosx+sinx)
csc x
tan x + 1
cot x
cot x + 1
Rewrite tanx in terms of sinx and cosx
tanx=sinxcosx
tanx=cotx1
tanx=cosxsinx
tanx=adjacentopposite
tanθcosθ can be written in a single trigonometric identity as:
cosθ
sinθ
secθ
cotθ
cos2θ1−cos2θ can be written in a single trigonometric identity as:
cos2θ
sin2θ
sec2θ
tan2θ
cosθ cscθ can be written in a single trigonometric identity as:
cosθ
sinθ
secθ
cotθ
Simplify
cot2θ(1+tan2θ)
csc²θ
sec²θ
cscθ
1
Simplify
sinθ(cscθ−sinθ)
secθ
cos2θ
sin2θ
cos2θsin2θ
Simplify
tanxcscxcosx
cosx1
1
cotx
-1
tan2θ1−cos2θ can be simplified as
cot2θ
tan2θ
sin2θ
cos2θ
Which of the following would be a step to prove the following identity? cscx−secx=sinxcosxcosx−sinx
sinx1−cosx1
sinxcosx−sinx
cosxcosx−sinx
sinxcosx1
One step in proving the identity below would be:
sec2θsec2θ−1
sec2θsec2θ−sec2θ1
sec2θtan2θ
Both A and B
Neither A nor B
tanθtanθ+cotθ can be simplified as:
csc2θ
cot2θ
sin2θ
cos2θ
sinθcotθ secθ
0
1
sinθ
cosθ
Simplify
csc x(cosx+sinx)
csc x
tan x + 1
cot x
cot x + 1
Simplify: 1+tan2xsin2x+cos2x+cot2x
cot2x
tan2x
csc2x
sec2x
Simplify: cotxcos2(−x)cscx
−sinx
−cosx
sinx
cosx
Which of these is true because of even symmetry?
cos(−40°)=cos(40°)
sin(−56°)=−sin(56°)
tan(44°)=cot(46°)
tan(12°)=cot(78°)1
cos(−54π)=
Complete this equation using even symmetry.
sec(−54π)1
sin(−54π)
−cos(54π)
cos(54π)
