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Stoichiometry Basics Review

Total questions: 14

Worksheet time: 13mins

Name
Class
Date
1.

Why must chemical equations be balanced?

a)

So that the equation doesn't explode

b)

The reaction won't happen until it is balanced

c)

Based on the Law of Conservation of Matter, matter cannot be created or destroyed.

d)

Based on the Law of Conservation of Energy, energy cannot be created or destroyed.e

2.

Which are the reactants in the following reaction?

2Mg + O2 ---> 2MgO

a)

Mg and O2

b)

MgO

c)

Mg and MgO

d)

O2 and MgO

3.
How many oxygens are in Al₂(SO₄)₃?
a)
4
b)
12
c)
7
d)
24
4.

Use the following BALANCED chemical equation: 4NH3+6NO  5N2+6H2O4NH_3+6NO\ \rightarrow\ 5N_2+6H_2O    What is the ratio of  NH3NH_3   to  N2N_2  

a)

4:5

b)

1:1

c)

2:3

d)

5:6

5.
What is the correct formula for Sodium Oxide?
a)
NaO
b)
NaO2
c)
Na2O
d)
Na2O2
6.
Octanitrogen tetraoxide
a)
N8O3
b)
N7O3
c)
N8O3
d)
N8O4
7.

SHOW WORK ON YOUR PAPER:

Equation is balanced.

N2 + 3H2 --> 2NH3 How many moles of N2 is needed to react with 6 moles of H2?

a)

6.7

b)

2.0

c)

3.0

d)

15.0

8.

To remember steps, no matter what.....what always goes in the upper left and bottom right of our conversion factors

a)

1 gram

b)

1 mole

c)

the coefficient

d)

the name

9.

Converting from grams C2H18 to grams CO2 , the first conversion factor has grams of what on the bottom

a)

C2H18

b)

CO2

c)

O2

d)

H2O

10.

The middle conversion factor is the

a)

mole ratio of C2H18 to CO2

b)

molar mass of CO2

c)

molar mass of O2

d)

combination lock of your locker

11.

WHAT IS WRONG WITH THIS SET UP??? (other than the missing info)

a)

Your mom

b)

There should be 2 moles per gram.

c)

molar ratio is switched

d)

nothing wrong

12.

SHOW YOUR WORK ON PAPER!

SO2 + PCl5 --> SOCl2 + POCl3

How many grams PCl5 are required to complete this reaction when given 16.2g SO2?

Given Molar masses! SO2 = 64.07 g/mol; PCl5 = 208.22 g/mol

a)

52.6 g

b)

30.1g

c)

26.4g

d)

19.8g

13.

SHOW YOUR WORK ON PAPER!

3CaCO3 + 2FePO4 --> Ca3(PO4)2 + Fe2(CO3)3

We start with 100. g of CaCO3 and 45 g of FePO4, How many grams of calcium phosphate are produced?

Identify the limiting reactant.

Given molar masses: (CaCO3 = 100.09 g/mol; FePO4 = 150.82 g/mol)

a)

iron(V) phosphate

b)

calcium carbonate

c)

iron(III) phosphate

d)

calcium(II) carbonate

14.
Theoretical yield = 73g
Actual yield = 62g
Calculate the percent yield.
a)
1.16%
b)
116%
c)
85%
d)
76%